my approach was a bit different , I use Pythagoras to make quadratic which returned imaginary roots so triangle cannot exist

This proves that sometimes, we need to think before you write anything.,

Guys another tricky question(super easy actually) for Permutations and combinations

Imagine there is one rook/castle piece placed in A1(red box) , it should finally reach h8(orange box) the rook/castle can only move up or right, so what's the total different ways of rook/castle to reach h8(orange box)

It can move 7ups and then 7rights , or 7rights 1st then 7ups, it doesn't matter how many rights/ups

Yg ni 1 mark question 😂😂😂

Siapa mau lagi 1 soalan kbat yg mmg Susah gila Kalau U tak tahu Cara penyelesaian

its just 14C7 😂

So 3432

Pukul 1.15 saya akan hantar

Imagine U are a king of a country, and in 24 hours,U have an event with 1000 guests, and U prepared 1000 bottle of wine for the guests, but a bad guy poisoned 1 of the wine bottles, so now U have 10 rats to find out which is the poisoned wine, U can feed a drop of wine to the rats, rats can drink from multiple bottle of wines... U should find the exact bottle of wine and throw it, U can't throw all the bottles of wines, and the best part is the rat will die in 24 hours once drank the poison..

Bayangkan U adalah raja sebuah negara, dan dalam masa 24 jam, U mengadakan acara dengan 1000 tetamu, dan U menyediakan 1000 botol wain untuk tetamu, tetapi orang jahat meracuni 1 botol wain, jadi sekarang U mempunyai 10 ekor tikus untuk mengetahui yang manakah wain beracun, Anda boleh menyuapkan setitik wain kepada tikus-tikus itu, sebotol wain dan tin yang tepat dapat dibuang... ia, anda tidak boleh membuang semua botol wain, dan bahagian yang terbaik ialah tikus akan mati dalam masa 24 jam setelah minum racun..

Google translate

Question is how U will find the poisoned bottle?

Guys actually I am just form 4 now, but my father asks me many different types of questions, these weird questions are my father's questions, if U know how to do these, it proves you can do hots questions..

Answer
now U have 1000 bottles of wine kan

So U number all the bottles 1 to 1000 and make it to binary digits

So Ur 1st bottle is numbered as 0000000001

2nd bottle is 000000010

The 000000011

Then 000000100

Like that

Ok now there are 10 rats kan

So if let's say rat1 U need to feed wine with all the bottles that have 1 at the 10th digit, 2 Nd rat should drink from all the wine bottles that have 1 in 9th place mcm tu, So at the end since 2 to the power of 10 is 1024 and it's lesser than 1000, U can find which bottle is poisoned based on which rats died..

addmath f4 ch 5 progressions

Circular measure+ differentiation

Thanks to TonyCWX

Let x=length of the rectangle
h = height of the rectangle

Black line = h/tan(60°) = (h√3)/3

Using Pythagoras' Theorem,
[(h√3)/3 + x]² + h² = 36
h²/3 + (2xh√3)/3 + x² + h² - 36 = 0
h²(4/3) + [(2x√3)/3]h + (x²-36) = 0
h = [-(2x√3)/3 + √[(4x²/3)-(16/3)(x²-36)]]/(8/3)
h = [-x√3 + 3√(48-x²)]/4

Area of the rectangle, A = xh = x([-x√3 + 3√(48-x²)]/4)

dA/dx = (72-3x²-x√(144-3x²))/(2√(48-x²))

At Maximum, dA/dx = 0
(72-3x²-x√(144-3x²))/(2√(48-x²)) = 0
72-3x²-x√(144-3x²) = 0
=> x=-6 or x=2√3

Max A = 6√3