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Q7 solution

Let's represent the total value of the estate as 'x'.

Since 1/3 of the estate is given to Lamptey, Lamptey's share is (1/3)(x) = x/3.
The remaining estate after giving Lamptey his share is (2/3)(x).

Nadia's share of the remaining estate is (1/3)((2/3)(x)) = (2/9)(x).

The remaining estate after giving Nadia her share is (2/3)(x) - (2/9)(x) = (4/9)(x).

Joyce's share of what still remains is (3/4)((4/9)(x)) = (12/36)(x) = (1/3)(x).

After giving Joyce her share, the remaining estate is (4/9)(x) - (1/3)(x) = (4/9)(x) - (3/9)(x) = (1/9)(x).

The wife's share of the remaining estate is (2/3)((1/9)(x)) = (2/27)(x).
Given that the wife received a total of GHΒ’ 105,000.00, we can write the equation:
(2/27)(x) = GHΒ’ 105,000.00.

To find the answer to (a), we need to solve for 'x':
2/27 = GHΒ’ 105,000.00 / x
2x = 105,000.00 * 27
2x = 2,835,000.00
x = 2,835,000.00 / 2
x = GHΒ’ 1,417,500.00

Therefore, the total value of the estate is GHΒ’ 1,417,500.00.

To find the extended family's share of the estate, we need to subtract the total shares already distributed from the total value of the estate:
Extended Family's share = GHΒ’ 1,417,500.00 - (Lamptey's share + Nadia's share + Joyce's share + Wife's share)
Extended Family's share = GHΒ’ 1,417,500.00 - (x/3 + 2x/9 + x/3 + 2x/27)
Extended Family's share = GHΒ’ 1,417,500.00 - (9x/27 + 6x/27 + 3x/27 + 2x/27)
Extended Family's share = GHΒ’ 1,417,500.00 - (20x/27)

We already know that x = GHΒ’ 1,417,500.00, so substituting this value, we get:
Extended Family's share = GHΒ’ 1,417,500.00 - (20 * 1,417,500.00 / 27)
Extended Family's share = GHΒ’ 1,417,500.00 - GHΒ’ 74,027.78
Extended Family's share = GHΒ’ 1,343,472.22

Therefore, the extended family's share of the estate is GHΒ’ 1,343,472.22.

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