🔹 Today Tata Steel 2018 , Round 6 will played
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📘 54...Kf7??
There are three reasons that the Black king has been placed in an improper position:
1- The f-file has blocked for the Black rook.
2- Black will also lose a tempo with the sequence e6.
3- The king moves away from h6-pawn and gives a tactical opportunity to the opponent.
[54...Kg7!
A)55.Ra8 Rf4! 56.e6 Rf8=
B)55.e6 Rh3 56.d4 Re3 57.Kd6 g4 = ]
55.Rh8! Rh3
(55...Kg7 56.e6! +-)
56.e6 Kf6 57.Rf8+ Ke7 58.Rf7+ Ke8 59.d4 g4 60.Rh7 Kf8 61.e7+ 1-0
There are three reasons that the Black king has been placed in an improper position:
1- The f-file has blocked for the Black rook.
2- Black will also lose a tempo with the sequence e6.
3- The king moves away from h6-pawn and gives a tactical opportunity to the opponent.
[54...Kg7!
A)55.Ra8 Rf4! 56.e6 Rf8=
B)55.e6 Rh3 56.d4 Re3 57.Kd6 g4 = ]
55.Rh8! Rh3
(55...Kg7 56.e6! +-)
56.e6 Kf6 57.Rf8+ Ke7 58.Rf7+ Ke8 59.d4 g4 60.Rh7 Kf8 61.e7+ 1-0
📘 17...Nh7!
An instructive idea to exchange a bad bishop for a good one. Also, the f5-lever will be available in the future.
18.Qd2 Bf6 19.Kf2 Bg5 20.B×g5 Q×g5 21.Q×g5 N×g5 =
Artashes Minasian won the Armenian Chess Championship six times, in 1990, 1992, 1993, 1995, 2004 and 2006.
An instructive idea to exchange a bad bishop for a good one. Also, the f5-lever will be available in the future.
18.Qd2 Bf6 19.Kf2 Bg5 20.B×g5 Q×g5 21.Q×g5 N×g5 =
Artashes Minasian won the Armenian Chess Championship six times, in 1990, 1992, 1993, 1995, 2004 and 2006.
📘 7...Ne7!
A multi-purpose move:
1- Clearing the long diagonal for the bishop.
2- Preventing White from playing d5.
3- Attacking the f4-bishop by playing Ng6.
A multi-purpose move:
1- Clearing the long diagonal for the bishop.
2- Preventing White from playing d5.
3- Attacking the f4-bishop by playing Ng6.
📘 55...Kc6??
Hou Yifan's miscalculation. She must not have blocked the c6-pawn.
(55...Kd6!
A)56.c4 d×c4 57.K×c4 c6! 58.Kd4 Kd7 59.Kc5 Kc7 =
B)56.b5 (The best try) a×b5 57.Kb4 c6 58.a6 Kc7 59.Kc5 b4 60.K×b4 Kb6 61.a7 K×a7 62.Kc5 Kb7 63.Kd6 d4 64.Ke7 c5 65.K×f7 c4 =
55...Kc6?? 56.c4! d4
(56.d×c4 57.K×c4 Kb7 58.b5! +-)
57.Kc2 Kd6 58.Kd2! c6 59.Ke2! Kd7 60.Kd3 +-
Hou Yifan's miscalculation. She must not have blocked the c6-pawn.
(55...Kd6!
A)56.c4 d×c4 57.K×c4 c6! 58.Kd4 Kd7 59.Kc5 Kc7 =
B)56.b5 (The best try) a×b5 57.Kb4 c6 58.a6 Kc7 59.Kc5 b4 60.K×b4 Kb6 61.a7 K×a7 62.Kc5 Kb7 63.Kd6 d4 64.Ke7 c5 65.K×f7 c4 =
55...Kc6?? 56.c4! d4
(56.d×c4 57.K×c4 Kb7 58.b5! +-)
57.Kc2 Kd6 58.Kd2! c6 59.Ke2! Kd7 60.Kd3 +-
📕 1.Nxd5!
The position of the black pawn on b6 is important for assessing the position because its advance has weakened the light squares on the queenside.
1.Ne5 Nxc3 2.bxc3 Nxe5 3.Rxe5 Bb7 Black is fine.
1.a4? weakening the b4-square.1...Ndb4+/=.
The position of the black pawn on b6 is important for assessing the position because its advance has weakened the light squares on the queenside.
1.Ne5 Nxc3 2.bxc3 Nxe5 3.Rxe5 Bb7 Black is fine.
1.a4? weakening the b4-square.1...Ndb4+/=.
📕 1.Qg5!
White strives to transpose into the ending by exchanging queens. In the ending, the weakness of the d4 pawn is of utmost importance.
White strives to transpose into the ending by exchanging queens. In the ending, the weakness of the d4 pawn is of utmost importance.
📕Unity Chess Multiple Choice 231
B: Qd5 – 7
👍👍👍👍👍👍👍 70%
C: Ne7 – 2
👍👍 20%
A: Rd8 – 1
👍 10%
👥 10 people voted so far.
B: Qd5 – 7
👍👍👍👍👍👍👍 70%
C: Ne7 – 2
👍👍 20%
A: Rd8 – 1
👍 10%
👥 10 people voted so far.
📕Unity Chess Multiple Choice 232
B: R×c3 – 6
👍👍👍👍👍👍👍 43%
A: Nd5 – 4
👍👍👍👍👍 29%
C: Rb6 – 4
👍👍👍👍👍 29%
👥 14 people voted so far.
B: R×c3 – 6
👍👍👍👍👍👍👍 43%
A: Nd5 – 4
👍👍👍👍👍 29%
C: Rb6 – 4
👍👍👍👍👍 29%
👥 14 people voted so far.