No, because after 1...e4! 2 dxe4 dxe4 3 Ng5 Black gets a fine initiative with the Spielmann idea, 3 … e3!. Then comes 4 fxe3 h6 5 Nge4 Ng4!.

Black would be winning after 6 Nf3? Qxd1+ 7 Kxd1 f5! (8 Nc3 Nf2+). The game turned in his favor after:

After 1 d5! Black loses with 1 … Nxd5?? 2 Qxh7+ and 3 Qh8 mate. So 1 … exd5 and 2 Bg5 were played.

The threat of 3 Bxf6 and Qxh7+ is powerful.

2 …Ne4 (2 … g6? 3 Rxe7! Nxe7 4 Rxf6 +-) 3 Nxe4 dxe4 4 Qxe4 g6 5Qh4 +-

Black got play with 1 … Nf4!. White can’t accept the pawn because 2 Nxf4 exf4 threatens … Bxc3 (and 3 Kb2? Na4+! 4 bxa4? Qb4+ is death).

2 h5! Nxh5

2 … gxh5 would allow 3 Bxf4! exf4 4 Rhg1! and Rxg7+ with an attack.

Threatening Nf6+. A fighting draw followed:

1.h7?? A fatal blunder that costs White the game.

Instead, he should have played: 1.Kd2! Rh3 2.h7 with an easy draw.