UNITY CHESS INFOGRAPHIC
❇️ Chess History - Tournaments
🔰 Gothenburg Interzonal (1955)
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
❇️ Chess History - Tournaments
🔰 Gothenburg Interzonal (1955)
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
✳️✳️✳️✳️
✅ Chess History - Tournaments
🍀 Gothenburg Interzonal (1955) , Sweden
🍀 2–20 September, 1929
♻️ CHAMPION: David Bronstein | 15/20 (+10 -0 =10)
▪️ The Gothenburg interzonal tournament was played between 15th August and 21st September 1955. It was a 21-player round robin, with the top nine players qualifying for the Amsterdam Candidates (1956) tournament. The winner was Bronstein with 15/20 (+10 =10 -0), Keres was second with 13.5, Panno had 13, Petrosian 12.5, Geller and Szabo each had 12 and the other qualifiers were Filip, Pilnik and Spassky with 11. Just missing out with 10.5 were Ilivitsky and Pachman.
▪️ Of particular theoretical note is that the 14th round saw three unsuccessful tries of the novelty 9 ... g5 10. fxg5 ♘d7 by players from Argentina when three Soviets tested their sacrifices in the move-order
1. e4 c5 2. ♘f3 d6 3. d4 cxd4 4. ♘xd4 ♘f6 5. ♘c3 a6 6. ♗g5 e6 7. f4 ♗e7 8. ♕f3 h6 9. ♗h4,
so the so-called Vespers - (Argentine or Göteborg) variation - with the main continuation being 11. ♘xe6 (11. 0-0-0 saw the game Rodolfo Cardoso vs Fischer, 1957 0-1) 11 ... fxe6 12. ♕h5 ♔f8 13. ♗b5 - and remained under a cloud for more than 2 years, until Paul Keres suggested the improvement 13 ... ♖h7 which was later played in Gligoric vs Fischer, 1958 1/2-1/2 and resurrected that Sicilian, Najdorf (B98) line.
🔹 The final standings and crosstable was as above👆
🔹 Download "Gothenburg Interzonal 1955 Games Database" by PGN format👇
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
✅ Chess History - Tournaments
🍀 Gothenburg Interzonal (1955) , Sweden
🍀 2–20 September, 1929
♻️ CHAMPION: David Bronstein | 15/20 (+10 -0 =10)
▪️ The Gothenburg interzonal tournament was played between 15th August and 21st September 1955. It was a 21-player round robin, with the top nine players qualifying for the Amsterdam Candidates (1956) tournament. The winner was Bronstein with 15/20 (+10 =10 -0), Keres was second with 13.5, Panno had 13, Petrosian 12.5, Geller and Szabo each had 12 and the other qualifiers were Filip, Pilnik and Spassky with 11. Just missing out with 10.5 were Ilivitsky and Pachman.
▪️ Of particular theoretical note is that the 14th round saw three unsuccessful tries of the novelty 9 ... g5 10. fxg5 ♘d7 by players from Argentina when three Soviets tested their sacrifices in the move-order
1. e4 c5 2. ♘f3 d6 3. d4 cxd4 4. ♘xd4 ♘f6 5. ♘c3 a6 6. ♗g5 e6 7. f4 ♗e7 8. ♕f3 h6 9. ♗h4,
so the so-called Vespers - (Argentine or Göteborg) variation - with the main continuation being 11. ♘xe6 (11. 0-0-0 saw the game Rodolfo Cardoso vs Fischer, 1957 0-1) 11 ... fxe6 12. ♕h5 ♔f8 13. ♗b5 - and remained under a cloud for more than 2 years, until Paul Keres suggested the improvement 13 ... ♖h7 which was later played in Gligoric vs Fischer, 1958 1/2-1/2 and resurrected that Sicilian, Najdorf (B98) line.
🔹 The final standings and crosstable was as above👆
🔹 Download "Gothenburg Interzonal 1955 Games Database" by PGN format👇
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
♦️ Review one of the theoretical novelty games in Najdorf of Sicilian on Gothenburg Interzonal 1955👇
♦️ Other two games by PGN format are in tournament database.
👇👇👇
🔸 Boris Spassky vs Herman Pilnik
🔸 Gothenburg Interzonal (1955), Gothenburg SWE, rd 14, Sep-07
🔸 Sicilian Defense: Najdorf Variation. Goteborg (Argentine) (B98)
. . . . . . . . . . . . .
@unitychess
♦️ Other two games by PGN format are in tournament database.
👇👇👇
🔸 Boris Spassky vs Herman Pilnik
🔸 Gothenburg Interzonal (1955), Gothenburg SWE, rd 14, Sep-07
🔸 Sicilian Defense: Najdorf Variation. Goteborg (Argentine) (B98)
. . . . . . . . . . . . .
@unitychess
19.Rxd8!+
Chinese GM exchanges a pair of rooks in order to penetrate to the 7th rank with his another rook.
19...Rxd8 20.Bxf3 N2d4 21.Bxd4 Nxd4 22.Rc7 Nxf3+ 23.exf3 Rd3 24.Rxb7 +/-
Chinese GM exchanges a pair of rooks in order to penetrate to the 7th rank with his another rook.
19...Rxd8 20.Bxf3 N2d4 21.Bxd4 Nxd4 22.Rc7 Nxf3+ 23.exf3 Rd3 24.Rxb7 +/-
37...Rf3!
15-year-old Romanian FM finds the only winning move. He is aiming to weave a mating net for the enemy king.
37...Ke3? 38.Kg3=
38.f5 Ke5 39.Rxh7 Kf4 40.g5
40. Re7 Rf1 -+
40...Rf2+ 41.Kg1 Rg2+ 42.Kf1 Rxg5 43.Re7 Ke3 44.Re6 Rg3 45.Rg6 Rxh3 46.Rg8 Rh1+ 47.Rg1 Rh2 48.Rg4 Bf3 49.Rg8 Ra2 50.Re8+ Be4 51.Kg1 Ra1+ 0-1
15-year-old Romanian FM finds the only winning move. He is aiming to weave a mating net for the enemy king.
37...Ke3? 38.Kg3=
38.f5 Ke5 39.Rxh7 Kf4 40.g5
40. Re7 Rf1 -+
40...Rf2+ 41.Kg1 Rg2+ 42.Kf1 Rxg5 43.Re7 Ke3 44.Re6 Rg3 45.Rg6 Rxh3 46.Rg8 Rh1+ 47.Rg1 Rh2 48.Rg4 Bf3 49.Rg8 Ra2 50.Re8+ Be4 51.Kg1 Ra1+ 0-1
33. Qg2?
White abandons to play the most obvious move 33.Nh5! because of his worrying about the opponent Qe4+. However, he has overlooked an important intermediate move in his calculation.
33. Nh5! Qe4+ 34. Rg2 Qb1+ 35. Nc1! The point.
A) 35...Qxc1+ 36. Rg1 Qc2 37. Qc8+ Kh7 38. Rxg7#
B) 35... Ra8 36. Rxg7 Qxc1+ 37. Rg1 Qc2 38. Qe6+-
33... Rxc4 34.Nc1 Qf2 35. Qxf2 exf2 36. Rf1 b5 =
White abandons to play the most obvious move 33.Nh5! because of his worrying about the opponent Qe4+. However, he has overlooked an important intermediate move in his calculation.
33. Nh5! Qe4+ 34. Rg2 Qb1+ 35. Nc1! The point.
A) 35...Qxc1+ 36. Rg1 Qc2 37. Qc8+ Kh7 38. Rxg7#
B) 35... Ra8 36. Rxg7 Qxc1+ 37. Rg1 Qc2 38. Qe6+-
33... Rxc4 34.Nc1 Qf2 35. Qxf2 exf2 36. Rf1 b5 =
26... Qh4??
Black's blunder in a difficult situation. He should have played a waiting move like 26...Rcc8.
27.Qd4 Qxd4 28. exd4 1-0
Black's blunder in a difficult situation. He should have played a waiting move like 26...Rcc8.
27.Qd4 Qxd4 28. exd4 1-0
19.Bb5!
A right positional decision. White intends to trade his bad bishop for opponent's good one.
19. g5?! d5 20. Qe3 dxe4 21. Rxd8 Rxd8 22. Bb5 Qb4 23. Na2 Qd6 24. Bxc6 Qxc6 25. Qxe4 Qxe4 26.fxe4=
19.Bc4 Nxc4+ 20. Qxc4 Qf6=
19... Bxb5 20.axb5
Creating unnecessary weaknesses on his own pawn structure.
Better is 20.Nxb5 Rc8 21. Nc3 Qe5 22. Qd2 Qc5 23. h5+/=
20...Ra8 21. Ra1 Rec8 22. h5 c5 23. bxc6 Rxc6 24. h6 Qe5 25. Nb5 gxh6
25... Qxb5?? 26. Qxg7#
26. Rh5 Qf4 27. Rah1! Rac8 28. R1h2?
28. c3! Qxf3 29. R1h2 d5 30. exd5 Rg6 31. d6+/-
28... Nc4+ $4 29. bxc4 Rxc4 30.Qd2 Rb4+
30... Rxc2+ 31.Qxc2 Rxc2+ 32. Rxc2 Qxf3 33. Nxd6+-
31. Ka2 Ra4+ 32. Kb2 Rb4+ 33. Ka2 Ra4+ 34. Kb3 Rb4+ 35. Ka3 Qxf3+ 36. c3 Rb1 37. Ka2 Qf1 38. Rh1 Qxh1 39. Rxh1 Rxh1 40. Nxd6 Rd8 41. Qf4 Rd7 42. Qe5
1-0
A right positional decision. White intends to trade his bad bishop for opponent's good one.
19. g5?! d5 20. Qe3 dxe4 21. Rxd8 Rxd8 22. Bb5 Qb4 23. Na2 Qd6 24. Bxc6 Qxc6 25. Qxe4 Qxe4 26.fxe4=
19.Bc4 Nxc4+ 20. Qxc4 Qf6=
19... Bxb5 20.axb5
Creating unnecessary weaknesses on his own pawn structure.
Better is 20.Nxb5 Rc8 21. Nc3 Qe5 22. Qd2 Qc5 23. h5+/=
20...Ra8 21. Ra1 Rec8 22. h5 c5 23. bxc6 Rxc6 24. h6 Qe5 25. Nb5 gxh6
25... Qxb5?? 26. Qxg7#
26. Rh5 Qf4 27. Rah1! Rac8 28. R1h2?
28. c3! Qxf3 29. R1h2 d5 30. exd5 Rg6 31. d6+/-
28... Nc4+ $4 29. bxc4 Rxc4 30.Qd2 Rb4+
30... Rxc2+ 31.Qxc2 Rxc2+ 32. Rxc2 Qxf3 33. Nxd6+-
31. Ka2 Ra4+ 32. Kb2 Rb4+ 33. Ka2 Ra4+ 34. Kb3 Rb4+ 35. Ka3 Qxf3+ 36. c3 Rb1 37. Ka2 Qf1 38. Rh1 Qxh1 39. Rxh1 Rxh1 40. Nxd6 Rd8 41. Qf4 Rd7 42. Qe5
1-0
36.Kf3 [36.Rd7+! Kh6 37.Kf3 Rf8+ 38.Ke4 Rf2 39.Kd5 Rf3 (39...Rd2+ 40.Kc6 Rxc2 41.b3 Rh2 42.Kxc5 Rxh3 43.Kxb4 Rxg3 44.c5 Rg4+ 45.Kb5 h4 46.c6 Rg5+ 47.Kb4 Rg4+ 48.Kc5 Rg5+ 49.Kd6 Rg3 50.c7 Rd3+ 51.Kc6 Rc3+ 52.Kb7 h3 53.Rd8 Kh7 54.Rd3 Rxd3 (54...h2 55.Rxc3 h1Q+ 56.Rc6+–) 55.c8Q h2 56.Qc7++–) 40.Kxc5 Rxg3 41.Rd3 h4 42.Kxb4 Rxd3 43.cxd3 g5 44.c5 g4 45.hxg4 h3 46.c6 h2 47.c7 h1Q 48.c8Q Qb1 49.Qh8+ Kg5 50.Qh5+ Kf4 51.Qf5+ Kg3 52.Ka3; 36.Kf3 Rf8+ 37.Kg2 a5 (37...Re8 38.Rd7+ Kh6 39.Kf3 Rf8+ 40.Ke4± Rf2 41.Kd5 a5 42.Kxc5 Rxc2 43.b3 Rxa2 44.Kb5+–) 38.Rd5 Re8 39.Kf3 Rf8+ 40.Ke3 Re8+ 41.Kf2 Rc8 42.b3 Kf6 43.h4±; 36.Rd2 Re4 37.b3 Re3 38.Rd6 Rc3 39.Ra6 g5!]½–½