Congratulations to Levon Aronian! πππ
He scores his second impressive #speedchess win, pulling away in the 3|1 blitz control!
He scores his second impressive #speedchess win, pulling away in the 3|1 blitz control!
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Checkmate on the board! And that after a mere 18 moves. Trickster Levon Aronian indahouse! #SpeedChess
π Today is birthday of Mariya Muzychuk !!
Ukrainian chess grandmaster
ππ·πΊπΈπΈβ€οΈ Happy birthday!! ππππ
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@unitychess
Ukrainian chess grandmaster
ππ·πΊπΈπΈβ€οΈ Happy birthday!! ππππ
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@unitychess
UNITY CHESS INFOGRAPHIC
βοΈ Chess History - Tournaments
π° Gothenburg Interzonal (1955)
#chess_history_tornaments
#Gothenburg_1955
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@unitychess
βοΈ Chess History - Tournaments
π° Gothenburg Interzonal (1955)
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
β³οΈβ³οΈβ³οΈβ³οΈ
β Chess History - Tournaments
π Gothenburg Interzonal (1955) , Sweden
π 2β20 September, 1929
β»οΈ CHAMPION: David Bronstein | 15/20 (+10 -0 =10)
βͺοΈ The Gothenburg interzonal tournament was played between 15th August and 21st September 1955. It was a 21-player round robin, with the top nine players qualifying for the Amsterdam Candidates (1956) tournament. The winner was Bronstein with 15/20 (+10 =10 -0), Keres was second with 13.5, Panno had 13, Petrosian 12.5, Geller and Szabo each had 12 and the other qualifiers were Filip, Pilnik and Spassky with 11. Just missing out with 10.5 were Ilivitsky and Pachman.
βͺοΈ Of particular theoretical note is that the 14th round saw three unsuccessful tries of the novelty 9 ... g5 10. fxg5 βd7 by players from Argentina when three Soviets tested their sacrifices in the move-order
1. e4 c5 2. βf3 d6 3. d4 cxd4 4. βxd4 βf6 5. βc3 a6 6. βg5 e6 7. f4 βe7 8. βf3 h6 9. βh4,
so the so-called Vespers - (Argentine or GΓΆteborg) variation - with the main continuation being 11. βxe6 (11. 0-0-0 saw the game Rodolfo Cardoso vs Fischer, 1957 0-1) 11 ... fxe6 12. βh5 βf8 13. βb5 - and remained under a cloud for more than 2 years, until Paul Keres suggested the improvement 13 ... βh7 which was later played in Gligoric vs Fischer, 1958 1/2-1/2 and resurrected that Sicilian, Najdorf (B98) line.
πΉ The final standings and crosstable was as aboveπ
πΉ Download "Gothenburg Interzonal 1955 Games Database" by PGN formatπ
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
β Chess History - Tournaments
π Gothenburg Interzonal (1955) , Sweden
π 2β20 September, 1929
β»οΈ CHAMPION: David Bronstein | 15/20 (+10 -0 =10)
βͺοΈ The Gothenburg interzonal tournament was played between 15th August and 21st September 1955. It was a 21-player round robin, with the top nine players qualifying for the Amsterdam Candidates (1956) tournament. The winner was Bronstein with 15/20 (+10 =10 -0), Keres was second with 13.5, Panno had 13, Petrosian 12.5, Geller and Szabo each had 12 and the other qualifiers were Filip, Pilnik and Spassky with 11. Just missing out with 10.5 were Ilivitsky and Pachman.
βͺοΈ Of particular theoretical note is that the 14th round saw three unsuccessful tries of the novelty 9 ... g5 10. fxg5 βd7 by players from Argentina when three Soviets tested their sacrifices in the move-order
1. e4 c5 2. βf3 d6 3. d4 cxd4 4. βxd4 βf6 5. βc3 a6 6. βg5 e6 7. f4 βe7 8. βf3 h6 9. βh4,
so the so-called Vespers - (Argentine or GΓΆteborg) variation - with the main continuation being 11. βxe6 (11. 0-0-0 saw the game Rodolfo Cardoso vs Fischer, 1957 0-1) 11 ... fxe6 12. βh5 βf8 13. βb5 - and remained under a cloud for more than 2 years, until Paul Keres suggested the improvement 13 ... βh7 which was later played in Gligoric vs Fischer, 1958 1/2-1/2 and resurrected that Sicilian, Najdorf (B98) line.
πΉ The final standings and crosstable was as aboveπ
πΉ Download "Gothenburg Interzonal 1955 Games Database" by PGN formatπ
#chess_history_tornaments
#Gothenburg_1955
. . . . . . . . . . . . .
@unitychess
β¦οΈ Review one of the theoretical novelty games in Najdorf of Sicilian on Gothenburg Interzonal 1955π
β¦οΈ Other two games by PGN format are in tournament database.
πππ
πΈ Boris Spassky vs Herman Pilnik
πΈ Gothenburg Interzonal (1955), Gothenburg SWE, rd 14, Sep-07
πΈ Sicilian Defense: Najdorf Variation. Goteborg (Argentine) (B98)
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@unitychess
β¦οΈ Other two games by PGN format are in tournament database.
πππ
πΈ Boris Spassky vs Herman Pilnik
πΈ Gothenburg Interzonal (1955), Gothenburg SWE, rd 14, Sep-07
πΈ Sicilian Defense: Najdorf Variation. Goteborg (Argentine) (B98)
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@unitychess
19.Rxd8!+
Chinese GM exchanges a pair of rooks in order to penetrate to the 7th rank with his another rook.
19...Rxd8 20.Bxf3 N2d4 21.Bxd4 Nxd4 22.Rc7 Nxf3+ 23.exf3 Rd3 24.Rxb7 +/-
Chinese GM exchanges a pair of rooks in order to penetrate to the 7th rank with his another rook.
19...Rxd8 20.Bxf3 N2d4 21.Bxd4 Nxd4 22.Rc7 Nxf3+ 23.exf3 Rd3 24.Rxb7 +/-
37...Rf3!
15-year-old Romanian FM finds the only winning move. He is aiming to weave a mating net for the enemy king.
37...Ke3? 38.Kg3=
38.f5 Ke5 39.Rxh7 Kf4 40.g5
40. Re7 Rf1 -+
40...Rf2+ 41.Kg1 Rg2+ 42.Kf1 Rxg5 43.Re7 Ke3 44.Re6 Rg3 45.Rg6 Rxh3 46.Rg8 Rh1+ 47.Rg1 Rh2 48.Rg4 Bf3 49.Rg8 Ra2 50.Re8+ Be4 51.Kg1 Ra1+ 0-1
15-year-old Romanian FM finds the only winning move. He is aiming to weave a mating net for the enemy king.
37...Ke3? 38.Kg3=
38.f5 Ke5 39.Rxh7 Kf4 40.g5
40. Re7 Rf1 -+
40...Rf2+ 41.Kg1 Rg2+ 42.Kf1 Rxg5 43.Re7 Ke3 44.Re6 Rg3 45.Rg6 Rxh3 46.Rg8 Rh1+ 47.Rg1 Rh2 48.Rg4 Bf3 49.Rg8 Ra2 50.Re8+ Be4 51.Kg1 Ra1+ 0-1
33. Qg2?
White abandons to play the most obvious move 33.Nh5! because of his worrying about the opponent Qe4+. However, he has overlooked an important intermediate move in his calculation.
33. Nh5! Qe4+ 34. Rg2 Qb1+ 35. Nc1! The point.
A) 35...Qxc1+ 36. Rg1 Qc2 37. Qc8+ Kh7 38. Rxg7#
B) 35... Ra8 36. Rxg7 Qxc1+ 37. Rg1 Qc2 38. Qe6+-
33... Rxc4 34.Nc1 Qf2 35. Qxf2 exf2 36. Rf1 b5 =
White abandons to play the most obvious move 33.Nh5! because of his worrying about the opponent Qe4+. However, he has overlooked an important intermediate move in his calculation.
33. Nh5! Qe4+ 34. Rg2 Qb1+ 35. Nc1! The point.
A) 35...Qxc1+ 36. Rg1 Qc2 37. Qc8+ Kh7 38. Rxg7#
B) 35... Ra8 36. Rxg7 Qxc1+ 37. Rg1 Qc2 38. Qe6+-
33... Rxc4 34.Nc1 Qf2 35. Qxf2 exf2 36. Rf1 b5 =