undefined8 FUN_001011f0(void) {
  int iVar1;
  ostream *poVar2;
  long in_FS_OFFSET;
  int local_7c;
  undefined1 *local_78;
  long local_70;
  undefined1 local_68 [16];
  string local_58 [40];
  long local_30;
  
  local_30 = *(long *)(in_FS_OFFSET + 0x28);
  local_78 = local_68;
  local_68[0] = 0;
  local_70 = 0;
  poVar2 = std::operator<<((ostream *)std::cout,"Enter a string of characters (no spaces): ");
  FUN_00101430(poVar2);
  std::operator>>((istream *)std::cin,(string *)&local_78);
  if (5 < local_70 - 5U) {
    std::operator<<((ostream *)std::cout,"Bro, what are you trying to do?");
    FUN_00101430();
                    /* WARNING: Subroutine does not return */
    exit(0);
  }
  poVar2 = std::operator<<((ostream *)std::cout,"Enter correct number (no spaces): ");
  FUN_00101430(poVar2);
  std::istream::operator>>((istream *)std::cin,&local_7c);
  std::__cxx11::string::string(local_58,(string *)&local_78);
  iVar1 = FUN_001014b0(local_58);
  std::__cxx11::string::_M_dispose();
  if (local_7c == iVar1) {
    poVar2 = std::operator<<((ostream *)std::cout,"OMG! You did it! :3");
  }
  else {
    poVar2 = std::operator<<((ostream *)std::cout,"Send help pls.");
  }
  FUN_00101430(poVar2);
  std::__cxx11::string::_M_dispose();
  if (local_30 == *(long *)(in_FS_OFFSET + 0x28)) {
    return 0;
  }
                    /* WARNING: Subroutine does not return */
  __stack_chk_fail();
}

so which means I missed smthing here

so I finalized it to this code that's the logic I suppose if you enter any character longer than 5 it exits with that message and then the next one is the number you type must be equal to the checksum of your string..

the check sum is this the comments for simplification ...

time to try it

so wait

ghidra did unsigned substraction so .... local_70 is the string length, the expression length_70 - 5U is unsigned

this underflows to a huge number, which is >5, so the real condition is local_70 <5

so wait

the range is 5 to 10

as 6 or 7, 8, 9, 10 -5 are in range and true on the 5 < (local_70 -5U)

example 6-5 =1 and 1 is less than 5 ...

Give me a bit of time I am done with a and to go for the rest ....

Had to use a calculator

So for the string "abcde" the number is "734". Try it and it works

the value to find table[i] from 15 address

So this is the whole logic of the code revision engineered I will post the full writeup maybe tmrw.

Good night

I am happy today