Tetstack
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any one help why do i have to choose ten ??
Do i put Computer Science in all
Tetstack
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this is one of them by the way
New blog out, sorry for not posting till now, I kind of accidentally deleted the github token that should have managed the post add and delete and was some problem on the code.

https://engineering-logs.pages.dev/post?id=SAUR-Security-Analysis-and-Threat-Engine
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Tetstack
this is one of them by the way
this is a dude by the way.
Channel name was changed to «54 65 74 73 74 61 63 6𝖇»
Tetstack
Channel name was changed to «54 65 74 73 74 61 63 6𝖇»
I wonder if my subs will increase after this, lol
I didn't get hacked I promise just got bored so any one who finds my channel will think it's fishy
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Tetstack
yes
Me seeing linux removing

Windhoe


users reasons not to switch to linux.

@Tetstack
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CHAOS

A randomised 3D art style, that never repeats.

Detail: GitHub

@Tetstack
Good night yall
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Tetstack
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on github
pulling an allnighter and then praying fajr feels like a drunk guy doing the line test.
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Tetstack
CHAOS A randomised 3D art style, that never repeats. Detail: GitHub @Tetstack
well the random seed is generated by " a specific logic.

Every single day, you generate a fresh 256-digit random pool (giving you 10²⁵⁶ possible values), combine it with that day's visitor count (between 1 and 100,000, adding 10⁵ possibilities) and a millisecond-precision timestamp (another 10⁷ variations per day), then feed that entire string into SHA-512 to produce a perfectly distributed hash; you take that hash, reduce it modulo 10¹² to get a valid starting position within your 1-trillion-digit library of Pi, extract 128 consecutive digits from that position, chop those 128 digits into 8 separate seeds of 16 digits each, multiply all 8 seeds together to get a massive product, add all 8 seeds together to get a sum, XOR those two results together to scramble any mathematical relationship between them, and output that final XOR result as your 128-digit code.

Because the SHA-512 hash ensures that even microscopic changes in the pool, visitor count, or time produce completely different indices, and because your final output has 10¹²⁸ possible values, the Birthday Paradox says you would need to generate roughly the square root of that 10⁶⁴ codes before hitting a 50% chance of repetition, which at one code per day equals 10⁶⁴ days or approximately 10⁶¹ years, meaning this system will take a hundred quintillion trillion trillion trillion trillion times longer than the current age of the universe to produce the same number twice, making repetition effectively impossible for all practical and astronomical timescales.