Answer to Q54
A rectangle and a square both has the same area. Which one of them has the highest perimeter?
To answer this question let's imagine a square of length and breath 4m. The area will be L x B = 4 x 4 = 16m²
The perimeter is said square is L+L+B+B = 4 + 4 + 4 + 4 = 16m
Now imagine a rectangle with the same area 16m² which has a side as 2m. The other side will be L x 2 = 16m²
L = 16 ÷ 2 = 8m
Perimeter of the rectangle is L+L+B+B = 8 + 8 + 2 + 2 = 20m
So, the perimeter of a rectangle will be large than that of a square with equal area.
Answer: Rectangle
A rectangle and a square both has the same area. Which one of them has the highest perimeter?
To answer this question let's imagine a square of length and breath 4m. The area will be L x B = 4 x 4 = 16m²
The perimeter is said square is L+L+B+B = 4 + 4 + 4 + 4 = 16m
Now imagine a rectangle with the same area 16m² which has a side as 2m. The other side will be L x 2 = 16m²
L = 16 ÷ 2 = 8m
Perimeter of the rectangle is L+L+B+B = 8 + 8 + 2 + 2 = 20m
So, the perimeter of a rectangle will be large than that of a square with equal area.
Answer: Rectangle
Answer to Q55
During a banquest, I finished a 18cm diameter pizza and my wife finished two 12cm diameter pizza. Who ate the most?
Let's start by calculating the surface area of the pizza I ate. πr²
Diameter = 18cm. Radius = 18 ÷ 2 = 9cm
A = π x 9²
A = 254.47cm²
And my wife ate two 12cm diameter pizzas
Diameter = 12cm. Radius = 12 ÷ 2 = 6cm
A = π x 6²
A = 113.10cm²
But she ate 2 so,
A = 113.10 x 2 = 226.20cm²
I ate 254.47cm² of pizza and she ate 226.20cm²
Answer: Me
[Moral of the question: there are more pizza in a single 18cm diameter than in two 12cm diameter]
During a banquest, I finished a 18cm diameter pizza and my wife finished two 12cm diameter pizza. Who ate the most?
Let's start by calculating the surface area of the pizza I ate. πr²
Diameter = 18cm. Radius = 18 ÷ 2 = 9cm
A = π x 9²
A = 254.47cm²
And my wife ate two 12cm diameter pizzas
Diameter = 12cm. Radius = 12 ÷ 2 = 6cm
A = π x 6²
A = 113.10cm²
But she ate 2 so,
A = 113.10 x 2 = 226.20cm²
I ate 254.47cm² of pizza and she ate 226.20cm²
Answer: Me
[Moral of the question: there are more pizza in a single 18cm diameter than in two 12cm diameter]
Answer to Q56
There are 4 numbers w, x, y & z. w + x = 14, w + y = 15, x + z = 16 and y - z = 10. What is x and y?
w + x = 14
w + y = 15
x + z = 16
y - z = 10
y = 10 + z
w = 15 - y
Then,
w = 15 - (10 + z)
w = 15 - 10 - z
w = 5 - z
But,
w + x = 14
5 - z + x = 14
x = 14 - 5 + z
x = 9 + z
And,
x + z = 16
9 + z + z = 16
9 + 2z = 16
2z = 16 - 9
2z = 7
z = 7 ÷ 2 = 3.5
z = 3.5
x = 9 + z = 9 + 3.5
x = 12.5
w = 5 - z = 5 - 3.5
w = 1.5
y = 10 + z = 10 + 3.5
y = 13.5
So, w = 1.5, x = 12.5, y = 13.5 and z = 3.5
Answer: x = 12.5 and y = 13.5
There are 4 numbers w, x, y & z. w + x = 14, w + y = 15, x + z = 16 and y - z = 10. What is x and y?
w + x = 14
w + y = 15
x + z = 16
y - z = 10
y = 10 + z
w = 15 - y
Then,
w = 15 - (10 + z)
w = 15 - 10 - z
w = 5 - z
But,
w + x = 14
5 - z + x = 14
x = 14 - 5 + z
x = 9 + z
And,
x + z = 16
9 + z + z = 16
9 + 2z = 16
2z = 16 - 9
2z = 7
z = 7 ÷ 2 = 3.5
z = 3.5
x = 9 + z = 9 + 3.5
x = 12.5
w = 5 - z = 5 - 3.5
w = 1.5
y = 10 + z = 10 + 3.5
y = 13.5
So, w = 1.5, x = 12.5, y = 13.5 and z = 3.5
Answer: x = 12.5 and y = 13.5
Answer to Q57
Mr Brown was killed on a Sunday afternoon. The wife said she was reading a book. The butler said he was taking a walk. The chef said he was making breakfast. The maid said she was folding clothes. The gardener said he was planting herbs. Who did it?
All but one had genuine excuses. The chef lied, he said he was cooking breakfast when it was actually afternoon so he is most likely the killer.
Answer: Chef
Mr Brown was killed on a Sunday afternoon. The wife said she was reading a book. The butler said he was taking a walk. The chef said he was making breakfast. The maid said she was folding clothes. The gardener said he was planting herbs. Who did it?
All but one had genuine excuses. The chef lied, he said he was cooking breakfast when it was actually afternoon so he is most likely the killer.
Answer: Chef
Answer to Q58
How many months in the year have 28 days?
All the months of the year has atleast 28 days!
Answer: 12
How many months in the year have 28 days?
All the months of the year has atleast 28 days!
Answer: 12
Answer to Q59
There are 120 people at a party and everyone shook hands. How many handshake will there be?
If you got Q34 right or atleast studied the answer, you should get this question right!
It is known that the number of handshake within a group of people is the sum of integer between 1 and (number of people in the group - 1). Say there are persons A, B, C, D and E (5 people) in a group and all shook hands, the number of handshakes will be sum of integers between 1 and (5-1) i.e. 1 + 2 + 3 + 4 = 10.
Let's confirm this:
- Person A shakes B, C, D, and E (4 handshakes)
- Person B shakes C, D, and E (no need to shake A again because A already shook him) (3 handshakes)
- Person C shakes D and E (2 handshakes)
- Person D shakes E (1 handshake)
- Person E don't have to shake anybody, they have all shook him
So, 4 + 3 + 2 + 1 = 10
And also we know that the sum of 1 to n = (n(n+1)) ÷ 2. Say you want to add 1 to 10 that will be
= (10 x (10 + 1)) ÷ 2
= (10 x 11) ÷ 2
= 110 ÷ 2
= 55 (also try it with your calculator)
With this information, we now know the number of handshakes in a group of 120 people will be 1 + 2 + 3 + ... + 119
But we don't have to add sequentially like that, we just do (119 x 120) ÷ 2
= 14280 ÷ 2
= 7140
Answer: 7140
There are 120 people at a party and everyone shook hands. How many handshake will there be?
If you got Q34 right or atleast studied the answer, you should get this question right!
It is known that the number of handshake within a group of people is the sum of integer between 1 and (number of people in the group - 1). Say there are persons A, B, C, D and E (5 people) in a group and all shook hands, the number of handshakes will be sum of integers between 1 and (5-1) i.e. 1 + 2 + 3 + 4 = 10.
Let's confirm this:
- Person A shakes B, C, D, and E (4 handshakes)
- Person B shakes C, D, and E (no need to shake A again because A already shook him) (3 handshakes)
- Person C shakes D and E (2 handshakes)
- Person D shakes E (1 handshake)
- Person E don't have to shake anybody, they have all shook him
So, 4 + 3 + 2 + 1 = 10
And also we know that the sum of 1 to n = (n(n+1)) ÷ 2. Say you want to add 1 to 10 that will be
= (10 x (10 + 1)) ÷ 2
= (10 x 11) ÷ 2
= 110 ÷ 2
= 55 (also try it with your calculator)
With this information, we now know the number of handshakes in a group of 120 people will be 1 + 2 + 3 + ... + 119
But we don't have to add sequentially like that, we just do (119 x 120) ÷ 2
= 14280 ÷ 2
= 7140
Answer: 7140
Answer to Q60
Who did Matthew Perry play in 'Friends'?
Ok, we can't be always serious here 😀. Friends is one of the greatest TV shows of all time and who ever watched that show would surely enjoy Chandler Bing's (played by Matthew Perry) humor!
Answer: Chandler Bing
Who did Matthew Perry play in 'Friends'?
Ok, we can't be always serious here 😀. Friends is one of the greatest TV shows of all time and who ever watched that show would surely enjoy Chandler Bing's (played by Matthew Perry) humor!
Answer: Chandler Bing
Answer to Q61
You were handed a rectangle of 2m x 3m and asked to cut out a circle from it.
The diameter of the largest circle you can cut out of a rectangle will be the shortest side of the rectangle. With a rectangle of 2m x 3m, the diameter of the circle will be 2m
Area of a circle = πr²
And radius = diameter ÷ 2
r = 2m ÷ 2 = 1m
A = π x 1² = π
Answer: π
You were handed a rectangle of 2m x 3m and asked to cut out a circle from it.
The diameter of the largest circle you can cut out of a rectangle will be the shortest side of the rectangle. With a rectangle of 2m x 3m, the diameter of the circle will be 2m
Area of a circle = πr²
And radius = diameter ÷ 2
r = 2m ÷ 2 = 1m
A = π x 1² = π
Answer: π
Answer to Q62
If D + E = G and C + G = H. What is A + C?
Let A = 1, B = 2, C = 3, etc
D + E = G i.e. 4 + 5 = 9 but G is not 9 but 7
C + G = H i.e. 3 + 7 =10 but H is not 10 but 8
So the pattern is A + B - 2
4 + 5 - 2 = 7
3 + 7 - 2 = 8
So, A + C = 1 + 3 - 2 = 2 (B)
Answer: B
If D + E = G and C + G = H. What is A + C?
Let A = 1, B = 2, C = 3, etc
D + E = G i.e. 4 + 5 = 9 but G is not 9 but 7
C + G = H i.e. 3 + 7 =10 but H is not 10 but 8
So the pattern is A + B - 2
4 + 5 - 2 = 7
3 + 7 - 2 = 8
So, A + C = 1 + 3 - 2 = 2 (B)
Answer: B
Answer to Q63
Complete this series 3.8.13, 9.14.19 and 6.11.?
The series is an Arithmetic Progression with difference of 5
See, 8 - 3 = 5; 13 - 8 =5; 14 - 9 = 5, 19 - 14 = 5; 11 - 6 = 5
x - 11 = 5
x = 5 + 11 = 16
Answer: 16
Complete this series 3.8.13, 9.14.19 and 6.11.?
The series is an Arithmetic Progression with difference of 5
See, 8 - 3 = 5; 13 - 8 =5; 14 - 9 = 5, 19 - 14 = 5; 11 - 6 = 5
x - 11 = 5
x = 5 + 11 = 16
Answer: 16
Answer to Q63
4-9-10-15, 7-12-3-8, 14-7-9-?
With A-B-C-D, the pattern is A + D = B + C
4-9-10-15: 4 + 15 = 9 + 10 = 19
7-12-3-8: 7 + 8 = 12 + 3 =15
So, 14-7-9-x = 14 + x = 7 + 9 = 16
14 + x = 16
x = 16 - 14
x = 2
Answer: 2
4-9-10-15, 7-12-3-8, 14-7-9-?
With A-B-C-D, the pattern is A + D = B + C
4-9-10-15: 4 + 15 = 9 + 10 = 19
7-12-3-8: 7 + 8 = 12 + 3 =15
So, 14-7-9-x = 14 + x = 7 + 9 = 16
14 + x = 16
x = 16 - 14
x = 2
Answer: 2
Answer to Q64
If and equals et, is equals est. What is an?
A clever code or puzzle can be hiding in plain sight and that's the case for this one. It's actually no code or encryption of any kind, it's just English to French translation!
English = French
and = et
is = est
a(n) = un
Answer: un
If and equals et, is equals est. What is an?
A clever code or puzzle can be hiding in plain sight and that's the case for this one. It's actually no code or encryption of any kind, it's just English to French translation!
English = French
and = et
is = est
a(n) = un
Answer: un
Answer to Q66
[5, 7, 4], [10, 5, 5], [20, 7, x]. What is x?
[A, B, C]: C = (A + B) ÷ 3
[5, 7, 4]: (5 + 7) ÷ 3 = 12 ÷ 3 = 4
[10, 5, 5]: (10 + 5) ÷ 3 = 15 ÷ 3 = 5
[20, 7, x]: x = (20 + 7) ÷ 3 = 27 ÷ 3 = 9
Answer: 9
[5, 7, 4], [10, 5, 5], [20, 7, x]. What is x?
[A, B, C]: C = (A + B) ÷ 3
[5, 7, 4]: (5 + 7) ÷ 3 = 12 ÷ 3 = 4
[10, 5, 5]: (10 + 5) ÷ 3 = 15 ÷ 3 = 5
[20, 7, x]: x = (20 + 7) ÷ 3 = 27 ÷ 3 = 9
Answer: 9
Answer to Q67
If 73 = 32, 82 = 27 and 10.6 = 77. What is 57?
The pattern
AB = C: (A+1) x (B+1) = C
A.B = C: (A+1) x (B+1) = C
73 = 32: 8 x 4 = 32
82 = 27: 9 x 3 = 27
10.6 = 77: 11 x 7 = 77
57 = 6 x 8 = 48
Answer: 48
If 73 = 32, 82 = 27 and 10.6 = 77. What is 57?
The pattern
AB = C: (A+1) x (B+1) = C
A.B = C: (A+1) x (B+1) = C
73 = 32: 8 x 4 = 32
82 = 27: 9 x 3 = 27
10.6 = 77: 11 x 7 = 77
57 = 6 x 8 = 48
Answer: 48
Answer to Q68
141₅ = x ₁₀. What is x?
Converting from base 5 to base 10
141₅ becomings 1² 4¹ 1°
= (1 x 5²) + (4 x 5¹) + (1 x 5°)
= 25 + 20 + 1
= 46
Answer: 46
141₅ = x ₁₀. What is x?
Converting from base 5 to base 10
141₅ becomings 1² 4¹ 1°
= (1 x 5²) + (4 x 5¹) + (1 x 5°)
= 25 + 20 + 1
= 46
Answer: 46
Answer to Q69
If 1 = 0, 10 = 1 and 100 = 2. What is 63?
At first glance, you would have thought we are counting the numbers of zeros but a smart people will know it can't be as simple as that.
Any one good at math will notice a pattern immediately though logarithm
Log 1 base 10 is 0
Log 10 base 10 is 1
Log 100 base 10 is 2
So, log 63 base 10 is 1.799
Answer: 1.799
If 1 = 0, 10 = 1 and 100 = 2. What is 63?
At first glance, you would have thought we are counting the numbers of zeros but a smart people will know it can't be as simple as that.
Any one good at math will notice a pattern immediately though logarithm
Log 1 base 10 is 0
Log 10 base 10 is 1
Log 100 base 10 is 2
So, log 63 base 10 is 1.799
Answer: 1.799
Answer to Q70
[3,42,1] [5,82,3] [6,84,2] [4,x,1]. What is x?
[A,B,C]: B = (A+C)(A-C)
[3,42,1] (3+1)(3-1) = 42
[5,82,3] (5+3)(5-3) = 82
[6,84,2] (6+2)(6-2) = 84
[4,x,1] x = (4+1)(4-1) = 53
Answer: 53
[3,42,1] [5,82,3] [6,84,2] [4,x,1]. What is x?
[A,B,C]: B = (A+C)(A-C)
[3,42,1] (3+1)(3-1) = 42
[5,82,3] (5+3)(5-3) = 82
[6,84,2] (6+2)(6-2) = 84
[4,x,1] x = (4+1)(4-1) = 53
Answer: 53
Answer to Q70
There are x oranges and were divided between 2 boys but 1 orange remained so it was divided between 3 boys and again 1 orange remained. Also between 4, 5 and 6 boys, still 1 orange remained. It was however equally divided among 7 boys.
What is X?
To answer this, let's first arrange the options in desending order: 7, 33, 49, 301
The question simply put says the correct number when divided by 2 to 6 must always have 1 as it reminder and must be exactly divisible by 7
7:
Divided by 2: 3 rem 1
Divided by 3: 2 rem 1
Divided by 4: 1 rem 3
So not our answer
33:
Divided by 2: 16 rem 1
Divided by 3: 11 rem 0
So not our answer
49:
Divided by 2: 24 rem 1
Divided by 3: 16 rem 1
Divided by 4: 12 rem 1
Divided by 5: 9 rem 4
So not our answer
301:
Divided by 2: 150 rem 1
Divided by 3: 100 rem 1
Divided by 4: 75 rem 1
Divided by 5: 60 rem 1
Divided by 6: 50 rem 1
Divided by 7: 43 rem 0
Our answer!
Answer 301
There are x oranges and were divided between 2 boys but 1 orange remained so it was divided between 3 boys and again 1 orange remained. Also between 4, 5 and 6 boys, still 1 orange remained. It was however equally divided among 7 boys.
What is X?
To answer this, let's first arrange the options in desending order: 7, 33, 49, 301
The question simply put says the correct number when divided by 2 to 6 must always have 1 as it reminder and must be exactly divisible by 7
7:
Divided by 2: 3 rem 1
Divided by 3: 2 rem 1
Divided by 4: 1 rem 3
So not our answer
33:
Divided by 2: 16 rem 1
Divided by 3: 11 rem 0
So not our answer
49:
Divided by 2: 24 rem 1
Divided by 3: 16 rem 1
Divided by 4: 12 rem 1
Divided by 5: 9 rem 4
So not our answer
301:
Divided by 2: 150 rem 1
Divided by 3: 100 rem 1
Divided by 4: 75 rem 1
Divided by 5: 60 rem 1
Divided by 6: 50 rem 1
Divided by 7: 43 rem 0
Our answer!
Answer 301
Answer to Q71
What is the smallest number that can be exactly divided by all the numbers from 1 to 10.
First we have to find out the prime factors of each of the numbers between 1 and 10.
1 = 1 x 1
2 = 2 x 1
3 = 3 x 1
4 = 2 x 2
5 = 5 x 1
6 = 2 x 3
7= 7 x 1
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
Then we check the prime numbers for their highest occurance.
2: Highest occurance 3 times (8 = 2 x 2 x 2)
3: Highest occurance 2 times (9 = 3 x 3)
5: Highest occurance 1 time (5 = 5 x 1)
7: Highest occurance 1 time (7 = 7 x 1)
So, we have 2³ x 3² x 5¹ x 7¹ = 2520
Answer: 2520
What is the smallest number that can be exactly divided by all the numbers from 1 to 10.
First we have to find out the prime factors of each of the numbers between 1 and 10.
1 = 1 x 1
2 = 2 x 1
3 = 3 x 1
4 = 2 x 2
5 = 5 x 1
6 = 2 x 3
7= 7 x 1
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
Then we check the prime numbers for their highest occurance.
2: Highest occurance 3 times (8 = 2 x 2 x 2)
3: Highest occurance 2 times (9 = 3 x 3)
5: Highest occurance 1 time (5 = 5 x 1)
7: Highest occurance 1 time (7 = 7 x 1)
So, we have 2³ x 3² x 5¹ x 7¹ = 2520
Answer: 2520
Answer to Q72
If n > i then cⁿ > cⁱ for all value of c?
cⁿ > cⁱ will be true for c > 0
E.g. 3³ > 3²
cⁿ > cⁱ will not always be true for c ≤ 0
E.g. 0³ = 0²; -3³ < 3²
Answer: False
If n > i then cⁿ > cⁱ for all value of c?
cⁿ > cⁱ will be true for c > 0
E.g. 3³ > 3²
cⁿ > cⁱ will not always be true for c ≤ 0
E.g. 0³ = 0²; -3³ < 3²
Answer: False