Quick electro trick/shortcut
Finding electric field from finite length wire so
Replace a uniformly charged finite straight wire by an equivalent circular arc centered at the observation point
You can get it quickly
Without getting into mess of E = [ Ex² + Ey² ]^½
I guess everyone knows this
Finding electric field from finite length wire so
Replace a uniformly charged finite straight wire by an equivalent circular arc centered at the observation point
You can get it quickly
Without getting into mess of E = [ Ex² + Ey² ]^½
I guess everyone knows this
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Reason why many of us is here in jee grp
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Hey wondering that should we start some daily question solving series If anyone interested in solving questions
Think we can solve and dicuss classic test papers. We would do only maths section and find better ways methods and approaches
Think we can solve and dicuss classic test papers. We would do only maths section and find better ways methods and approaches
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The analemma is the annual apparent motion of the Sun across the celestial sphere. Its shape and tilt are determined by the tilt of the Earth's axis, its orientation, and the ellipticity of the Earth's orbit. The highest and lowest points correspond to the summer and winter solstices.
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