QUIZ

Topic: Increment and Decrement

1. int a=5;
  int  x=++a + ++a;
  cout<<x;


2. int a=5;
   int b=6;
   Cout<< ++a + b++;
   Cout<<b;

3. int x, a, b, c;
a = 2;
b = 4;
c = 5;
x = a--+ b++ -++c;
cout<<x;

4. int x, a;
a = 2;
x = ++a *--a *++a;
cout<<x;

5. int x, a = 4;
x = ++a + ++a + ++a;

cout<<x;


Provide the output of each code snippets and justify your answer with a detailed explanation .

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Hint:

One variable can't store two value at the same time.

1.int a=5;
int x=++a + ++a;
(6+ ++a)
(7+7) coz one variable can't hold two different value , (6 and 7 ) at the same time so it become 7.

7+7=14

Answer 14

2.int a=5;
   int b=6;
   
   Cout<<++a +b++// post and pre increment .
  6+6 // after this line b will be 7
Cout<<++a +b++;  (6+6)
=12
Cout<<b;
=7

answer=12 and 7

3.int x,a,b,c;
a=2;
b=4;
c=5;
x=a-- + b++ - ++c;

(2+4)-6
=6-6=0
cout<<x;  

Answer 0

4.int x,a;
a=2
x=++a *--a* ++a
(3*2) * ++a , but one variable can't hold two values at the same time.

So, (2*2)*++a
    (4*3)=12

cout<<x;// 12

Answer 12


5.int x,a=4;
x=++a + ++a + ++a;

(++a + ++a) + ++a
(5+6) + ++a but we can't store two value at one variable at the same time.

So,
(6+6)+ ++a
(12)+ 7

Answer 19

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Updated

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