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C++ Basic 2018 (Batch-2)
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2. Output: The product displays only if i+1 is an even number, unless there is no output. The array size is 5, but it has only 4 elements; therefore, 0 is automatically added as the fifth element. ๐งฎ
(product = product * value[i])
- If i=0: product = 1 * 21 = 21. 0 + 1 = 1 is odd, so 21 will not be displayed. โ
- If i=1: product = 21 * 3 = 63. 1 + 1 = 2 is even, so 63 will be displayed. โ
- If i=2: product = 63 * 7 = 441. 2 + 1 = 3 is odd, so 441 will not be displayed. โ
- If i=3: product = 441 * 5 = 2205. 3 + 1 = 4 is even, so 2205 will be displayed. โ
- If i=4: product = 2205 * 0 = 0. 4 + 1 = 5 is odd, so there will be no output. โ
- If i=5: the condition will be false and it will not enter the loop. ๐
FINAL OUTPUT: 63 2205 ๐
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(product = product * value[i])
- If i=0: product = 1 * 21 = 21. 0 + 1 = 1 is odd, so 21 will not be displayed. โ
- If i=1: product = 21 * 3 = 63. 1 + 1 = 2 is even, so 63 will be displayed. โ
- If i=2: product = 63 * 7 = 441. 2 + 1 = 3 is odd, so 441 will not be displayed. โ
- If i=3: product = 441 * 5 = 2205. 3 + 1 = 4 is even, so 2205 will be displayed. โ
- If i=4: product = 2205 * 0 = 0. 4 + 1 = 5 is odd, so there will be no output. โ
- If i=5: the condition will be false and it will not enter the loop. ๐
FINAL OUTPUT: 63 2205 ๐
@ProgrammingWithFaith2018
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C++ Basic 2018 (Batch-2)
2. Output: The product displays only if i+1 is an even number, unless there is no output. The array size is 5, but it has only 4 elements; therefore, 0 is automatically added as the fifth element. ๐งฎ (product = product * value[i]) - If i=0: product = 1 * 21โฆ
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