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👩🎨Applied mathematics one 📐
Derivative Question ❓
Let F(x)=f(2(g(x))) f(x)=x^4+x^3+1; 0<=x<=3
find F'(3)=? 🧮
Hint: 💡
g(x)=inverse of f(x) 🔄
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Derivative Question ❓
Let F(x)=f(2(g(x))) f(x)=x^4+x^3+1; 0<=x<=3
find F'(3)=? 🧮
Hint: 💡
g(x)=inverse of f(x) 🔄
@ProgrammingWithFaith2018
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✥Applied 📐
Derivative of inverse csc functions. 📉
Y=csc⁻¹(secx) find dy/dx? 🤔
Hint:
csc⁻¹ means inverse of csc 💡
@ProgrammingWithFaith2018
Derivative of inverse csc functions. 📉
Y=csc⁻¹(secx) find dy/dx? 🤔
Hint:
csc⁻¹ means inverse of csc 💡
@ProgrammingWithFaith2018
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C++ Basic 2018 (Batch-2)
👩🎨Applied mathematics one 📐 Derivative Question ❓ Let F(x)=f(2(g(x))) f(x)=x^4+x^3+1; 0<=x<=3 find F'(3)=? 🧮 Hint: 💡 g(x)=inverse of f(x) 🔄 @ProgrammingWithFaith2018
✅Explanation👨🏽💼
Hint:
(f⁻)(x)=g(x)
f(a)=c ,(f⁻)'(c)=1/f'(a)
So, c=3 a=?
f(a)=a^4+a^3+1=3
a^4+a^3-2=0
a=1
f(1)=3
g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7
then,
F'(3)=2f'(2g(3))*(g'(3))
=2f'(2)*(1/7)
=88*1/7
=88/7
@ProgrammingWithFaith2018
Hint:
(f⁻)(x)=g(x)
f(a)=c ,(f⁻)'(c)=1/f'(a)
So, c=3 a=?
f(a)=a^4+a^3+1=3
a^4+a^3-2=0
a=1
f(1)=3
g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7
then,
F'(3)=2f'(2g(3))*(g'(3))
=2f'(2)*(1/7)
=88*1/7
=88/7
@ProgrammingWithFaith2018
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C++ Basic 2018 (Batch-2)
✥Applied 📐 Derivative of inverse csc functions. 📉 Y=csc⁻¹(secx) find dy/dx? 🤔 Hint: csc⁻¹ means inverse of csc 💡 @ProgrammingWithFaith2018
✅Explanation
Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))
=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1
@ProgrammingWithFaith2018
Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))
=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1
@ProgrammingWithFaith2018
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applied1_bagashaw_maltot-1.pdf
105.3 MB
➡️Applied Math I - Begashaw
✅Applied Math ኮርስ ለምትወስዱ ተማሪዎች በጣም ወሳኝ የሆነ አጋዥ መፅሐፍ ነው። አብዛኛውን ጊዜ ፈተና የሚወጣበት እንዲሁም Conceptኦችን በደንብ ግልፅ አድርጎ የሚያብራራ ነው።
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