C++ Basic 2018 (Batch-2)

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C++ Basic 2018 (Batch-2)

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ስለ Compilation እና Interpretation ይበልጥ ለመረዳት ከላይ ያለውን video ተመልከቱ።

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C++ Basic 2018 (Batch-2)

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C++ Basic 2018 (Batch-2)

Jummah Mubarak 🕌✨

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C++ Basic 2018 (Batch-2)

✝ ለመላው የክርስትና እምነት ተከታዮች እንኳን ለጌታችን ለመድኃኒታችን
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በሰላም አደረሳችሁ!

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556 views✞Faith✞, edited 17:00

C++ Basic 2018 (Batch-2)

👩‍🎨Applied mathematics one 📐

Derivative Question ❓

Let F(x)=f(2(g(x))) f(x)=x^4+x^3+1; 0<=x<=3
find F'(3)=? 🧮

Hint: 💡
g(x)=inverse of f(x) 🔄

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2.72K views✞Faith✞, edited 05:51

C++ Basic 2018 (Batch-2)

✥Applied 📐

Derivative of inverse csc functions. 📉

Y=csc⁻¹(secx) find dy/dx? 🤔

Hint:
csc⁻¹ means inverse of csc 💡

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465 views✞Faith✞, edited 05:53

C++ Basic 2018 (Batch-2)

👩‍🎨Applied mathematics one 📐 Derivative Question ❓ Let F(x)=f(2(g(x))) f(x)=x^4+x^3+1; 0<=x<=3 find F'(3)=? 🧮 Hint: 💡 g(x)=inverse of f(x) 🔄 @ProgrammingWithFaith2018

✅Explanation👨🏽‍💼

Hint:

(f⁻)(x)=g(x)

f(a)=c ,(f⁻)'(c)=1/f'(a)

So, c=3 a=?
f(a)=a^4+a^3+1=3
   a^4+a^3-2=0
        a=1

f(1)=3

g(3)=(f⁻)(3)=1
g'(3)=(f⁻)'(3)=1/f'(1)=1/7

then,
F'(3)=2f'(2g(3))*(g'(3))
       =2f'(2)*(1/7)
       =88*1/7
       =88/7

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557 views✞Faith✞, 05:57

C++ Basic 2018 (Batch-2)

✥Applied 📐 Derivative of inverse csc functions. 📉 Y=csc⁻¹(secx) find dy/dx? 🤔 Hint: csc⁻¹ means inverse of csc 💡 @ProgrammingWithFaith2018

✅Explanation

Hint:(csc⁻^1)'=
-f'(x) / f(x)sqrt((f(x)^2+1))

=-(secx)'/secx sqrt((secx)^2+1))
=-(-tanx secx) / secx sqrt(sec^2+1)
=tanx secx / secx tanx
=1

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C++ Basic 2018 (Batch-2)

applied1_bagashaw_maltot-1.pdf

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➡️Applied Math I - Begashaw

✅Applied Math ኮርስ ለምትወስዱ ተማሪዎች በጣም ወሳኝ የሆነ አጋዥ መፅሐፍ ነው። አብዛኛውን ጊዜ ፈተና የሚወጣበት እንዲሁም Conceptኦችን በደንብ ግልፅ አድርጎ የሚያብራራ ነው።

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C++ Basic 2018 (Batch-2)

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C++ Basic 2018 (Batch-2)

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C++ Basic 2018 (Batch-2)

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C++ Basic 2018 (Batch-2)

ለክርስትና እምነት ተከታይ ተማሪዎች በሙሉ!

እንኳን ለጌታችን ለመድኃኒታችን ለኢየሱስ ክርስቶስ የትንሳኤ በዓል በሰላም አደረሳችሁ አደረሰን። በዓሉ የሰላም፤ የፍቅር፤የስኬት፤ የመተሳሰብና የይቅርታ እንዲሆን እንመኛለን።

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C++ Basic 2018 (Batch-2)