.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Flowchart ena pseudocode ke tinish seat bewal post adergewalew
👍6
C++ Basics
Flowchart ena pseudocode ke tinish seat bewal post adergewalew
I'll do it tomorrow zare ke exam sle wexaw my brain is not functioning well.🙏🙏
🤩6❤3🙏1
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Pseudocode
1.Start
2.Accept Input From user
3.Convert String to Lowercase
lowercase_string = convert string to lowercase
4.Variable Initialization
Vowel_count = 0
i = 0
5.Loop through the string
WHILE i < length of lowercase_string:
current_char = lowercase_string[i]
IF current_char is 'a' OR current_char is 'e' OR current_char is 'i' OR current_char is 'o' OR current_char is 'u' THEN
Vowel_count = Vowel_count + 1
END IF
i = i + 1
END WHILE
6.Output the Result
Print "Number of vowels: ", Vowel_count
7.End
1.Start
2.Accept Input From user
Input string3.Convert String to Lowercase
lowercase_string = convert string to lowercase
4.Variable Initialization
Vowel_count = 0
i = 0
5.Loop through the string
WHILE i < length of lowercase_string:
current_char = lowercase_string[i]
IF current_char is 'a' OR current_char is 'e' OR current_char is 'i' OR current_char is 'o' OR current_char is 'u' THEN
Vowel_count = Vowel_count + 1
END IF
i = i + 1
END WHILE
6.Output the Result
Print "Number of vowels: ", Vowel_count
7.End
👍4🥰2🔥1
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Bexam sry sle koyew🙏🙏🙏🙏
🤝4
Life is fleeting if you die you'll be forgotten in a week. so live fully and pursue what you love.
@ProgrammingWithFaith
👍4🔥2
Hey, what's up? 😄
I'm really sorry 🙁 I won't have notes ready for today's class because this week has been tough 💪—mid-term exams got me! 📚 I don't think we'll kick off chapter 3 today, but I'm going to whip up a quiz 📝 on chapters 1 and 2 to see how much you all understand! 🤔✨
@ProgrammingWithFaith
I'm really sorry 🙁 I won't have notes ready for today's class because this week has been tough 💪—mid-term exams got me! 📚 I don't think we'll kick off chapter 3 today, but I'm going to whip up a quiz 📝 on chapters 1 and 2 to see how much you all understand! 🤔✨
@ProgrammingWithFaith
🔥2
The quiz will cover last year's mid-term exam and some important concepts.
Should I prepare for it today?
Should I prepare for it today?
👍10
C++ Basics via @QuizBot
🎲 Quiz 'C++ Basics chapter 1 & 2' 🖊 10 questions · ⏱ 1 min
Hey guys ezi quiz lay and teyak wrong nw ena delete adergewalew......but sry confuse sle aderkuwachu....prepare saderg nw mistake happen yadergew🙏🙏🙏🙏🙏
👍1
3. Which of the following is NOT a characteristic of a well-defined algorithm?
a) Unambiguous instructions.
b) A finite number of steps.
c) The use of random numbers at every step.
d) A clear starting and ending point.
Answer C.
Use of random numbers at every step make it the algorithm unpredictable and unreliable.
a) Unambiguous instructions.
b) A finite number of steps.
c) The use of random numbers at every step.
d) A clear starting and ending point.
Answer C.
Use of random numbers at every step make it the algorithm unpredictable and unreliable.
🙏2
Join Jimma University’s Biggest TechFusion Club!
🔥 Membership Registration is Open Now—Network, Learn & Innovate with the Best!
📢 Limited Spots! Apply Today ➡️ Registration link
#TechFusionJU #JoinNow
🔥 Membership Registration is Open Now—Network, Learn & Innovate with the Best!
📢 Limited Spots! Apply Today ➡️ Registration link
#TechFusionJU #JoinNow
🔥3👍2
Anyone who is interested can apply.
Don't miss this opportunity.🙏
Don't miss this opportunity.🙏
Question:
Given:
int x = 7;
int y = 3;
int z = x & y;
What is the value of z?
Explanation:
The question is asking us to determine the value of z after performing a bitwise AND operation between x and y.
Remember: z = x & y means z will store the result of a bitwise AND between x and y.
The bitwise AND operation works by comparing the corresponding bits of two numbers. It takes the bits one by one and the rules is:
• If both bits are 1, the result is 1.
• Otherwise, the result is 0.
First, we need to convert x (7) and y (3) into their binary representations:
• 7 = 0111 (Binary)
• 3 = 0011 (Binary)
Now, let's perform the bitwise AND operation:
0111 (x = 7)
& 0011 (y = 3)
0011 (z)
• Bit 0 (rightmost): 1 AND 1 = 1
• Bit 1: 1 AND 1 = 1
• Bit 2: 1 AND 0 = 0
• Bit 3 (leftmost): 0 AND 0 = 0
So, the result of the bitwise AND operation is 0011 in binary.
Finally, we convert the binary result (0011) back to decimal:
• 0011 (Binary) = 3 (Decimal)
Therefore, the value of z is 3.
Answer: z = 3👍5
QUIZ
Topic: Increment and Decrement
1. int a=5;
int x=++a + ++a;
cout<<x;
2. int a=5;
int b=6;
Cout<< ++a + b++;
Cout<<b;
3. int x, a, b, c;
a = 2;
b = 4;
c = 5;
x = a--+ b++ -++c;
cout<<x;
4. int x, a;
a = 2;
x = ++a *--a *++a;
cout<<x;
5. int x, a = 4;
x = ++a + ++a + ++a;
cout<<x;
Provide the output of each code snippets and justify your answer with a detailed explanation .
@ProgrammingWithFaith
👍4🔥2
C++ Basics pinned «QUIZ Topic: Increment and Decrement 1. int a=5; int x=++a + ++a; cout<<x; 2. int a=5; int b=6; Cout<< ++a + b++; Cout<<b; 3. int x, a, b, c; a = 2; b = 4; c = 5; x = a--+ b++ -++c; cout<<x; 4. int x, a; a = 2; x = ++a *--a *++a; cout<<x;…»