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Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
#include<iostream>
#include<string>
using namespace std;
int main()
{
string name;
cout << "Enter A text " << endl;
getline(cin,name);
int count=0;
for(int i=0; i<name.length(); i++) {
switch(name[i])
{
case 97:
case 65:
count++;
break;
case 101:
case 69:
count++;
break;
case 105:
case 73:
count++;
break;
case 111:
case 79:
count++;
break;
case 117:
case 85:
count++;
break;
}
}
if(count==0) {
cout << "There is no vowels" << endl;
}
else {
cout << "There are "<<count<<" vowels" << endl;
}
return 0;
}
π5
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Flowchart ena pseudocode ke tinish seat bewal post adergewalew
π6
C++ Basics
Flowchart ena pseudocode ke tinish seat bewal post adergewalew
I'll do it tomorrow zare ke exam sle wexaw my brain is not functioning well.ππ
π€©6β€3π1
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Pseudocode
1.Start
2.Accept Input From user
3.Convert String to Lowercase
lowercase_string = convert string to lowercase
4.Variable Initialization
Vowel_count = 0
i = 0
5.Loop through the string
WHILE i < length of lowercase_string:
current_char = lowercase_string[i]
IF current_char is 'a' OR current_char is 'e' OR current_char is 'i' OR current_char is 'o' OR current_char is 'u' THEN
Vowel_count = Vowel_count + 1
END IF
i = i + 1
END WHILE
6.Output the Result
Print "Number of vowels: ", Vowel_count
7.End
1.Start
2.Accept Input From user
Input string3.Convert String to Lowercase
lowercase_string = convert string to lowercase
4.Variable Initialization
Vowel_count = 0
i = 0
5.Loop through the string
WHILE i < length of lowercase_string:
current_char = lowercase_string[i]
IF current_char is 'a' OR current_char is 'e' OR current_char is 'i' OR current_char is 'o' OR current_char is 'u' THEN
Vowel_count = Vowel_count + 1
END IF
i = i + 1
END WHILE
6.Output the Result
Print "Number of vowels: ", Vowel_count
7.End
π4π₯°2π₯1
.
Input a string and count the vowels(a,e,I,o,u) . Algorithm,pseudocode and flowchart.please do me this .
Bexam sry sle koyewππππ
π€4
Life is fleeting if you die you'll be forgotten in a week. so live fully and pursue what you love.
@ProgrammingWithFaith
π4π₯2
Hey, what's up? π
I'm really sorry π I won't have notes ready for today's class because this week has been tough πͺβmid-term exams got me! π I don't think we'll kick off chapter 3 today, but I'm going to whip up a quiz π on chapters 1 and 2 to see how much you all understand! π€β¨
@ProgrammingWithFaith
I'm really sorry π I won't have notes ready for today's class because this week has been tough πͺβmid-term exams got me! π I don't think we'll kick off chapter 3 today, but I'm going to whip up a quiz π on chapters 1 and 2 to see how much you all understand! π€β¨
@ProgrammingWithFaith
π₯2
The quiz will cover last year's mid-term exam and some important concepts.
Should I prepare for it today?
Should I prepare for it today?
π10
C++ Basics via @QuizBot
π² Quiz 'C++ Basics chapter 1 & 2' π 10 questions Β· β± 1 min
Hey guys ezi quiz lay and teyak wrong nw ena delete adergewalew......but sry confuse sle aderkuwachu....prepare saderg nw mistake happen yadergewπππππ
π1
3. Which of the following is NOT a characteristic of a well-defined algorithm?
a) Unambiguous instructions.
b) A finite number of steps.
c) The use of random numbers at every step.
d) A clear starting and ending point.
Answer C.
Use of random numbers at every step make it the algorithm unpredictable and unreliable.
a) Unambiguous instructions.
b) A finite number of steps.
c) The use of random numbers at every step.
d) A clear starting and ending point.
Answer C.
Use of random numbers at every step make it the algorithm unpredictable and unreliable.
π2
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Don't miss this opportunity.π
Question:
Given:
int x = 7;
int y = 3;
int z = x & y;
What is the value of z?
Explanation:
The question is asking us to determine the value of z after performing a bitwise AND operation between x and y.
Remember: z = x & y means z will store the result of a bitwise AND between x and y.
The bitwise AND operation works by comparing the corresponding bits of two numbers. It takes the bits one by one and the rules is:
β’ If both bits are 1, the result is 1.
β’ Otherwise, the result is 0.
First, we need to convert x (7) and y (3) into their binary representations:
β’ 7 = 0111 (Binary)
β’ 3 = 0011 (Binary)
Now, let's perform the bitwise AND operation:
0111 (x = 7)
& 0011 (y = 3)
0011 (z)
β’ Bit 0 (rightmost): 1 AND 1 = 1
β’ Bit 1: 1 AND 1 = 1
β’ Bit 2: 1 AND 0 = 0
β’ Bit 3 (leftmost): 0 AND 0 = 0
So, the result of the bitwise AND operation is 0011 in binary.
Finally, we convert the binary result (0011) back to decimal:
β’ 0011 (Binary) = 3 (Decimal)
Therefore, the value of z is 3.
Answer: z = 3π5