'𝐄𝐧𝐜𝐫𝐲𝐩𝐭𝐢𝐨𝐧 𝐀𝐬𝐮𝐫𝐚 𝐯𝟒.𝟏'
Title Added Successfully.
And Soon Asura v4.1 test Will be Posted ;)

-- Simple byte formula...

--Encode and decode both...

-- make a function
function enc(x)
-- convert all char to a byte table..
-- like "AaBb" to {65,97,66,98}
x={x:byte(1,-1)}
-- loop in with all the bytes..

for i in pairs(x) do

--[[
Put the formula.. don't be confused with this.. its just a mathematical thing..

for example ABC, now..

A = 65 then (65+(1³+255))%255
(65+255)%255
320%255
65

( bruhh made mistake here...
1^3 + 255 = 1+255 = 256..
so answer will be 66 not 65 )

B = 66 then (66+(2³+255))%255
(66+263)%255
329%255
74

C = 67 then (67+(3³+255))%255
(67+282)%255
349%255
94

So answer will be {65,66,67} to {65,74,94} ( final: {66,74,94} )

Answer in Char = "AJ^" ("BJ^")
]]

x[i]=(x[i]+(i^3+256))%255
end
return string.char(table.unpack(x))
end

function dec(x)
x={x:byte(1,-1)}
for i in pairs(x) do
x[i]=(x[i]-(i^3+256))%255
end
return string.char(table.unpack(x))
end

print(enc("Hello world!"))
print(dec(enc("Hello again!")))

-- Tutorial by @KiranLua

Nice teach me pro

Hello World!
This is Asura v4.1 Encryption

This is a Competition :-

1.What to do to win here?
Decrypt this Script and, you won!
Send file to @YouKnowAsura

2. What do I get if I Decrypt this encryption?
Actually I can't give you Anything...
I am a Kid -_-

3. What are the conditions?
Send ss tool results along with Decrypt
And without any errors

Decrypt through Lasm only
Log, load etc etc will not be acceptable .

4. When competition starts?
Get set go!!! Competition started

5. Duration?
2 days.



++++++++++++++++++++++++
Dm @YouKnowAsura
++++++++++++++++++++++++
Support :-
@LearnEncryptionMaking
++++++++++++++++++++++++

print(os.date('Date: %x\nTime: %r'))

-- Get date and time with 1 line of code ;)

Exams😢

No posts now🤦‍♂

Hello Again.


This is Asura v4.1 or Asura v"cp"

I realised that I'm nothing in Lua Except a big 0.

I'm Sharing My Last Encryption,
This is quite good and I don't Make Anymore. Cause I am leaving Lua.

I have exams and I have a good Career to go with. So good bye Lua. ❤️

God made me this. I shared all my 4 Encryptions Open source. For some or other reason.
Never Forget :-
@YouKnowAsura
@LearnEncryptionMaking

Hey! Im back!!

I forgot that this channel also exists lol😂

Lol

Made for ppl who write code but forgot to indent it 🤦‍♂

( Not 100% working on all type of codes )
( Have some bugs.. )
( Will not work on 1 lined codes.. )

Emjoy! ❤️

Hello all 😉

It's Asura
I'm feeling some kind of good today.
So
I am sharing my Encryption
This is Asura 5.2
I hope you'll learn something
That's why I decided to share all my Encryptions open soure in future😉.
What Bolt said is true
I can't stop myself from sharing it 🙂😘.

I made some Anti Logs and Added detectors for preventing bypassing.

Learn from my Obfuscated Keys 😘.
I started my life here as noob & CP
so I decided to Become pro and teach All people at Begining.


My channel is Created for Teaching People 😏😁.

That's why LearnEncryptionMaking is not a name or and any brand;
return "it's a community helping Itself 🙂" end


Never Forget @YouKnowAsura
And
@LearnEncryptionMaking

See you Guys!

/Kill Kiran

Kiranima x Asurima

...

Never mind.. testing bot..

Hi Guys. It's Asura 🙂

I am Giving my Big lasm tool.

It's on basic principle of MyohSUI .
I had controversy with @T_I_C so I'm posting.

I got one tool from 666.zipv6 . And I studied it.
Proof:-
There will be a coding like
Is size >= maxstr and DATA:sub(i+1(etc etc) == "(Hex code)" then

Go print that code. You will understand.
And secondly i made new features and upgraded my tool.

It can bypass almost all encs from a to z. And 1 to 3. Just i don't know why it can't do SEA enc.
Btw Thank me and Take this tool.

New feature :-
Find root and key of big lasm
Easy to remove big lasm

Tool by MYOHSUI and @YouKnowAsura ( Kid)

A simple python string emcoder..

def enc(x):
x=list(x) # conver string to a list with each key as a char
byte="" # for output
c=0 # to get current index
for i in x: # loop through all keys...
byte+=chr((ord(i)-c+91)%256) # convert char to ascii value then encode that using a simple formula then convert that encoded ascii value back to char..
c=c+1
return byte # now return that encoded value

# And in dec function we just alter the operators...

def dec(x):
x=list(x)
byte=""
c=0
for i in x:
byte+=chr((ord(i)+c-91)%256)
c=c+1
return byte
print(dec(enc("hello")))

#~ By @KiranLua

What did you do