Exception in thread "main" java.lang.ArithmeticException: Access denied at Main.main(Main.java:3)

Output of 13 Syntax:Exception handling 03

//14 Syntax:File Create / write

import java.io.File;
import java.io.FileWriter;
import java.io.IOException;

public class CreateFile {
  public static void main(String[] args) {
  try {
    File Obj = new File("Give Location where to create File");
    if (Obj.createNewFile()) {
      System.out.println("File created: " + Obj.getName());
    FileWriter MWriter = new FileWriter("give Location of file which to write");
    MWriter.write("What am I writting");
    MWriter.close();
     System.out.println("Successfully wrote to the file.");
    } else {
      System.out.println("File already exists.");
    }
  } catch (IOException e) {
    System.out.println("An error occurred.");
    e.printStackTrace();
  }
  }
}
//Note This code can only run in Your PC

Output:
File created: test.txt
Successfully wrote to the file

Output of 14 Syntax:File Create / write

//14 Syntax:File Read / Info

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class ReadFile {
  public static void main(String[] args) {
    File Obj = new File("Location of text File");
        if (Obj.exists()) {
        System.out.println("File name: " + Obj.getName());
        System.out.println("Absolute path: " + Obj.getAbsolutePath());
        System.out.println("Writeable: " + Obj.canWrite());
        System.out.println("Readable " + Obj.canRead());
        System.out.println("File size in bytes " + Obj.length());
       }
        else {
        System.out.println("The file does not exist.");
       }
  try {
        File ObjR = new File("Location of text file");
        Scanner MReader = new Scanner(ObjR);
        while (MReader.hasNextLine()) {
        String data = MReader.nextLine();
          System.out.println(data);
        }
    MReader.close();
    }catch (FileNotFoundException e) {
    System.out.println("An error occurred.");
    e.printStackTrace();
  }
  }
 }
//Note This code can only run in Your PC

Output:
File name: test.txt
Absolute path: /home/runner/compilers/./test/test.txt
Writeable: true
Readable true
File size in bytes 18
What am I writting

Output of 14 Syntax:File Read / Info

//14 Syntax:File Delete and folder

import java.io.File;

public class DeleteFile {
  public static void main(String[] args) {
  try{
     File DObj = new File("Location Of File");
     if (DObj.delete()) {
    System.out.println("Deleted the file: " + DObj.getName());
  } else {
    System.out.println("Failed to delete the file.");
  }
    }catch(Exception e){
        System.out.println("Failed to delete the folder.");
    }
    finally{
        File DFObj = new File("Location of Folder");
  if (DFObj.delete()) {
    System.out.println("Deleted the folder: " + DFObj.getName());
  } else {
    System.out.println("Failed to delete the folder.");
  }
    }
  }
}
//Note This code can only run in Your PC

Output:
Deleted the file: test.txt
Failed to delete the folder.

Output of 14 Syntax:File Delete and folder

Remaining Topics like Inheritance, Polymorphism, Hash Map, Wrapper Classes, Regex, Threads, Lamda will be added soon

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#Taskforyou

Write a Java program that remove the extra spaces from the following string:

' I am learning Java object oriented programming '

Write code on task's comment, which code will be best that code should be posted here with those name

After 8pm today

#TaskAnswer

public class TaskAnswer {
public static void main(String[] args) {
String str = "I am learning Java object oriented programming";

str = str.replaceAll("\\s", "");
System.out.println(str);
}
}

Output:
Iamlearningobjectorientedprogramming

Explanation:

str = str.replaceAll("\\s", "") : This line replaces all whitespace characters in the string str with an empty string, effectively removing them. The \\s is a regular expression pattern that matches any whitespace character, such as spaces, tabs, or newlines. The double backslash \\ is necessary because \ is an escape character in Java strings, so to represent a single backslash in a regular expression, you need to escape it with another backslash.

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