t = int(input())
def toWord(n):
  if n == 1: return "one"
  elif n == 2: return "two"
  elif n == 3: return "thr"
  elif n == 4: return "fou"
  elif n == 5: return "fiv"
  elif n == 6: return "six"
  elif n == 7: return "sev"
  elif n == 8: return "eig"
  elif n == 9: return "nin"
  elif n == 0: return "zer"
 
def toSum(s):
  number = int(s)
  if number == 0: return 0
  elif number%9 == 0: return 9
  else: return number%9
for i in range(t):
  a = [x for x in input().split()]
  n = a[0]
  name = a[1]
  d1 = 0
  if "." in n:
    d1 = n.index('.')
  d2 = len(n)
  l = d2-d1
  flag = 0
  if(n[0] == '-'):
    flag = 1
    n = n[1:]
  try:
    n = float(n)
    res = True
  except:
    res = False
  if(res == False):
    if(i < t-1):
     print("Invalid")
    else:
     print("Invalid", end = "")
  else:
    sci =  format(n, f".{l}e")
    part = sci.split('e')
    num = part[0].split('.')
    k = int(part[1])
    if(flag == 1): res = "-"
    else: res = ""
    res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
    if(k > 0):
        res += '+'
    elif(k<0): res += '-'
    res += toWord(abs(int(part[1]))) +"@"
    if(k%2 != 0):
      for x in range(0,len(name),2):
        res += name[x]
    else:
      for x in range(1,len(name),2):
        res += name[x]
   
    if(i < t-1):
     print(res)
    else:
     print(res, end="")
Pswrd generator

Pswrd generator

What is the next competition now?

How placements are going in your college this year? Ho bhi rhe h kya?

Company – Deloitte

Role – Analyst   

Qualification – Bachelor’s degree

Experience – Freshers/ Experienced

Location – Hyderabad

Apply Link :
https://usijobs.deloitte.com/careersUSI/JobDetail/USI-EH24-EA-AU-MCBD-Digital-Analyst/166885

Vestas hiring Software Developer

Salary: 7 LPA - 15 LPA
Batch - 2024 / 2023 / 2022 / 2021
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P.S. - batch 2024 / 2023 must apply