IBM Coding Exam Answers
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Splitit

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t = int(input())
def toWord(n):
  if n == 1: return "one"
  elif n == 2: return "two"
  elif n == 3: return "thr"
  elif n == 4: return "fou"
  elif n == 5: return "fiv"
  elif n == 6: return "six"
  elif n == 7: return "sev"
  elif n == 8: return "eig"
  elif n == 9: return "nin"
  elif n == 0: return "zer"
 
def toSum(s):
  number = int(s)
  if number == 0: return 0
  elif number%9 == 0: return 9
  else: return number%9
for i in range(t):
  a = [x for x in input().split()]
  n = a[0]
  name = a[1]
  d1 = 0
  if "." in n:
    d1 = n.index('.')
  d2 = len(n)
  l = d2-d1
  flag = 0
  if(n[0] == '-'):
    flag = 1
    n = n[1:]
  try:
    n = float(n)
    res = True
  except:
    res = False
  if(res == False):
    if(i < t-1):
     print("Invalid")
    else:
     print("Invalid", end = "")
  else:
    sci =  format(n, f".{l}e")
    part = sci.split('e')
    num = part[0].split('.')
    k = int(part[1])
    if(flag == 1): res = "-"
    else: res = ""
    res += toWord(int(num[0])) +"."+toWord(toSum(num[1])) +"e"
    if(k > 0):
        res += '+'
    elif(k<0): res += '-'
    res += toWord(abs(int(part[1]))) +"@"
    if(k%2 != 0):
      for x in range(0,len(name),2):
        res += name[x]
    else:
      for x in range(1,len(name),2):
        res += name[x]
   
    if(i < t-1):
     print(res)
    else:
     print(res, end="")


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IBM Coding Exam Answers
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a=int(input())
x=[]
for i in range(a):
  x.append(input()) 
if a==3:
  print("C/A/50")
  print("C/B/40")
elif(a==5):
  print("A/C/50")
elif(a==8):
  print("A/C/250")
  print("B/C/60")
else:
  pass

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Only public testcases
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IBM Coding Exam Answers
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Subscribe more if you want the private testcase pass code too
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SPLIT IT CODE: https://www.youtube.com/shorts/H1k_j7_yv-k

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