IBM Coding Exam Answers
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def minVehicles(weights, limit):
weights.sort() # Sort the weights in ascending order
left, right = 0, len(weights) - 1
vehicles = 0

while left <= right:
if weights[left] + weights[right] <= limit:
left += 1
right -= 1
vehicles += 1

return vehicles

# Python 3 compatibility
try:
# Python 3
raw_input = input
except NameError:
# Python 2
pass

weights = list(map(int, raw_input().split()))
limit = int(raw_input())
result = minVehicles(weights, limit)

# Output the result without extra spaces or newline characters
print(result, end="")


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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <limits.h>
typedef struct {
int x, y;
} Point;
typedef struct {
char name[20];
Point location;
} Passenger;
typedef struct {
char number[20];
Point location;
} Vehicle;
int manhattanDistance(Point p1, Point p2) {
return abs(p1.x - p2.x) + abs(p1.y - p2.y);
}
Vehicle* findNearestVehicle(Passenger passenger, Vehicle* vehicles, int m, int* assigned) {
int i;
int minDistance = INT_MAX;
Vehicle* nearestVehicle = NULL;
for (i = 0; i < m; i++) {
if (!assigned[i]) {
int distance = manhattanDistance(passenger.location, vehicles[i].location);
if (distance < minDistance || (distance == minDistance && strcmp(vehicles[i].number, nearestVehicle->number) < 0)) {
minDistance = distance;
nearestVehicle = &vehicles[i];
}
}
}
assigned[nearestVehicle - vehicles] = 1;
return nearestVehicle;
}
int main() {
int n, m,i;
scanf("%d %d", &n, &m);
Passenger passengers[n];
for ( i = 0; i < n; i++) {
scanf("%s %d %d", passengers[i].name, &passengers[i].location.x, &passengers[i].location.y);
}
Vehicle vehicles[m];
for ( i = 0; i < m; i++) {
scanf("%s %d %d", vehicles[i].number, &vehicles[i].location.x, &vehicles[i].location.y);
}
int assigned[m];
memset(assigned, 0, sizeof(assigned));
int totalDistance = 0;
for ( i = 0; i < n; i++) {
Vehicle* assignedVehicle = findNearestVehicle(passengers[i], vehicles, m, assigned);
totalDistance += manhattanDistance(passengers[i].location, assignedVehicle->location);
}
printf("%d\n", totalDistance);
return 0;
}
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