π―πβππΌβπππΌπ πππβ πΎπΈππΌβπΌ ππββπΌβ- π»βπΈππΈπ βπΈππΌπ, πΈπβ#ππ, πΎπΈππΌ-πππππππππ
π―Dhaval Patel, GATE 2020 Topper secured AIR 13 in Petroleum Engineering. He credits his success to his parents and friends who supported him through the difficult times. I always focused on planned study, revising topics, said Dhaval.
Ace Petroleum Admin interacted with Dhaval regarding the GATE 2020 to know how he achieved this feat.
Read the full GATE 2020 topper interview to know his preparation strategy and more. ππ
https://m.facebook.com/story.php?story_fbid=151112013186136&id=100048620142075
π―Dhaval Patel, GATE 2020 Topper secured AIR 13 in Petroleum Engineering. He credits his success to his parents and friends who supported him through the difficult times. I always focused on planned study, revising topics, said Dhaval.
Ace Petroleum Admin interacted with Dhaval regarding the GATE 2020 to know how he achieved this feat.
Read the full GATE 2020 topper interview to know his preparation strategy and more. ππ
https://m.facebook.com/story.php?story_fbid=151112013186136&id=100048620142075
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Which of the following factors is more important to hole cleaning?
Anonymous Poll
32%
a) Flow rate
49%
b) Rheology
11%
c) Pipe Rotation
7%
d) Drilling rate
There r 3 bags containing 2 green+4 blue ball; 5 green+ 4 blue balls; 3 green+6 blue balls. Find the probability that the ball chosen randomly from any of the bags is a green ball ?
Anonymous Poll
50%
11/27
31%
5/12
15%
16/27
4%
5/16
Dear all, If you have any kind of doubts regarding questions and concept, you can direct message me, open search in telegram @Acepetroadmin and direct message me your doubts.
API- Ace Petroleum Engineering
There r 3 bags containing 2 green+4 blue ball; 5 green+ 4 blue balls; 3 green+6 blue balls. Find the probability that the ball chosen randomly from any of the bags is a green ball ?
#MathsSolution
Correct answer is GIVEN,
.
.
.
.
.
.
.
.
.
.
.
There will be 3 cases.
Case 1 : Ball is chosen from 1st bag.
Probability of green ball from 1st bag = (1/3)Γ(2/6)
= 1/9
Case 2 : Ball is chosen from 2nd bag.
Probability of green ball from 2nd bag = (1/3)Γ(5/9)
= 5/27
Case 3 : Ball is chosen from 3rd bag.
Probability of green ball from 3rd bag
= (1/3)Γ(3/9)
= 1/9
So required probability
= 1/9 + 5/27 + 1/9
= 11/27
Correct answer is GIVEN,
.
.
.
.
.
.
.
.
.
.
.
There will be 3 cases.
Case 1 : Ball is chosen from 1st bag.
Probability of green ball from 1st bag = (1/3)Γ(2/6)
= 1/9
Case 2 : Ball is chosen from 2nd bag.
Probability of green ball from 2nd bag = (1/3)Γ(5/9)
= 5/27
Case 3 : Ball is chosen from 3rd bag.
Probability of green ball from 3rd bag
= (1/3)Γ(3/9)
= 1/9
So required probability
= 1/9 + 5/27 + 1/9
= 11/27
π΄Key of questions from 11th June onwardsπ΄
a,d,b,a,c,b,a,b
a,d,b,a,c,b,a,b
Dear Petroleum Engineers,
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If 15 women and 9 men finish a job in 10 days, then how much time will 6 men and 10 women take for it.?
Anonymous Quiz
42%
15
30%
12
18%
20
10%
10
Brown coal that has high moisture content and commonly retains many of the original wood fragments is called
Anonymous Poll
12%
(A) Anthracite
22%
(B) Bituminous coal
26%
(C) Lignite
39%
(D) Peat
A clastic rock dominantly composed of feldspar grains is
Anonymous Poll
28%
(A) shale
20%
(B) arenite
21%
(C) greywacke
31%
(D) arkose
