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NECO CHEMISTRY OBJ
01-10: BCCCADDACE
11-20: DDECADBEAD
21-30: ACADCBDBAB
31-40: BDCCECACBB
41-50: CABACAEBDD
51-60: BBDDCCCBCC
COMPLETED.
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01-10: BCCCADDACE
11-20: DDECADBEAD
21-30: ACADCBDBAB
31-40: BDCCECACBB
41-50: CABACAEBDD
51-60: BBDDCCCBCC
COMPLETED.
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NECO CHEMISTRY ANSWERS.
3a ii)
Reactant concentration
Temperature
Catalyst
iii)
Concentration of ions
Mobility of ions
Overpotential
3 c i). Reduction in terms of oxidation number can be defined as the process in which the oxidation state of an atom, ion, or molecule is reduced, i.e., it gains electrons or loses oxygen.
Ii)Br2
III)
I) Organic compounds typically contain carbon-hydrogen bonds, which provide the molecules with their characteristic properties and reactivities.
Ii) Organic compounds often contain functional groups, which are specific structural units that impart specific chemical properties to the molecule.
III) Organic compounds exhibit a wide range of molecular structures and properties due to the diverse ways in which carbon atoms can bond with other atoms and functional groups.
Iv)
I) Animal source
Ii) plants source
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3a ii)
Reactant concentration
Temperature
Catalyst
iii)
Concentration of ions
Mobility of ions
Overpotential
3 c i). Reduction in terms of oxidation number can be defined as the process in which the oxidation state of an atom, ion, or molecule is reduced, i.e., it gains electrons or loses oxygen.
Ii)Br2
III)
I) Organic compounds typically contain carbon-hydrogen bonds, which provide the molecules with their characteristic properties and reactivities.
Ii) Organic compounds often contain functional groups, which are specific structural units that impart specific chemical properties to the molecule.
III) Organic compounds exhibit a wide range of molecular structures and properties due to the diverse ways in which carbon atoms can bond with other atoms and functional groups.
Iv)
I) Animal source
Ii) plants source
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Neco Chemistry solutions 👇👇
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Chemistry Essay
ANSWER FOUR(4) QUESTIONS ONLY
(1a)
(i) Hydrogen gas is colorless and odorless.
(ii) Hydrogen is highly flammable, which means it can easily catch fire when exposed to a flame or spark.
(iii) Hydrogen gas has low density, making it lighter than air.
(1b)
(I) Group 17 (halogens)
(II) lodine
(III) lodine
(1ci)
I. Calcium (Ca²⁺)
II. Magnesium (Mg²⁺)
(1cii)
I. lon exchange method
II. Lime-soda method
(1di)
(I) Methyl orange is used in the titration of a strong acid with a strong base.
(II) Phenolphthalein is used in the titration of a strong base with a strong acid.
(1dii)
(I) Hydrated salt: Copper(II) sulfate pentahydrate (CuSO₄.5H₂O)
(II) Acidic salt: Ammonium chloride (NH₄Cl)
(III) Basic salt: Sodium carbonate (Na₂CO₃)
(1ei)
2-methylbutane >>> pentane >>> 2,2-dimethylpropane
(1eii)
(I) 1-bromo-3-methylbutane
(II) 2-methylpentane
(1eiii)
Benzene is used as a starting material in the production of various important chemicals such as ethylbenzene, cumene, cyclohexane, and nitrobenzene.
(1eiv)
Saponification is a process in which ester molecules are hydrolyzed in the presence of a strong base (such as sodium hydroxide or potassium hydroxide) to form alcohol and the salt of the carboxylic acid.
(1f)
Given, Vapour density = 77
molecular mass of XCl₄ = Molecular mass = Vapour density x 2 = 77 x 2 = 154
Molecular mass of XCl₄ = X + 4(Atomic mass of Cl)
154 = X + 4(35.5)
X = 154 - 142
X = 12
:. The relative atomic mass of X is 12.
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ANSWER FOUR(4) QUESTIONS ONLY
(1a)
(i) Hydrogen gas is colorless and odorless.
(ii) Hydrogen is highly flammable, which means it can easily catch fire when exposed to a flame or spark.
(iii) Hydrogen gas has low density, making it lighter than air.
(1b)
(I) Group 17 (halogens)
(II) lodine
(III) lodine
(1ci)
I. Calcium (Ca²⁺)
II. Magnesium (Mg²⁺)
(1cii)
I. lon exchange method
II. Lime-soda method
(1di)
(I) Methyl orange is used in the titration of a strong acid with a strong base.
(II) Phenolphthalein is used in the titration of a strong base with a strong acid.
(1dii)
(I) Hydrated salt: Copper(II) sulfate pentahydrate (CuSO₄.5H₂O)
(II) Acidic salt: Ammonium chloride (NH₄Cl)
(III) Basic salt: Sodium carbonate (Na₂CO₃)
(1ei)
2-methylbutane >>> pentane >>> 2,2-dimethylpropane
(1eii)
(I) 1-bromo-3-methylbutane
(II) 2-methylpentane
(1eiii)
Benzene is used as a starting material in the production of various important chemicals such as ethylbenzene, cumene, cyclohexane, and nitrobenzene.
(1eiv)
Saponification is a process in which ester molecules are hydrolyzed in the presence of a strong base (such as sodium hydroxide or potassium hydroxide) to form alcohol and the salt of the carboxylic acid.
(1f)
Given, Vapour density = 77
molecular mass of XCl₄ = Molecular mass = Vapour density x 2 = 77 x 2 = 154
Molecular mass of XCl₄ = X + 4(Atomic mass of Cl)
154 = X + 4(35.5)
X = 154 - 142
X = 12
:. The relative atomic mass of X is 12.
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