2PM TODAY WAEC
PHYSICS OBJ AND THEORY
#1500 TO GET IT NOW
WHATSAPP 09056863938 ONLY
PHYSICS OBJ AND THEORY
#1500 TO GET IT NOW
WHATSAPP 09056863938 ONLY
β€6π4
*Payment is Done below πππ
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
π5π€¬3
9bii)
Slope = βF/βe
Point 1: (Extension = 10.0 cm, Force = 2.0 N)
Point 2: (Extension = 30.0 cm, Force = 6.0 N)
S = (6.0-2.0)/(30.0-10.0)
S = 4.0/20.0
S = 0.2N/cm
(9biii)
The slope represents the spring constant
k, indicating the stiffness of the spring.
(9c)
Given:
Mass (m) = 40 g = 0.04 kg
Elastic constant (k) = 350 N/m
Extension (x) = 4 cm = 0.04 m
Elastic potential energy stored in the rubber(E) = (1/2)kxΒ²
= (1/2) Γ 35 Γ (0.04)Β²
(1/2) Γ 35 Γ 0.0016
= 0.28 J
This energy is converted to kinetic energy of the stone:
K = (1/2)mvΒ² = E
(1/2)mvΒ² = 0.28 J
(1/2) Γ 0.04 Γ vΒ² = 0.28
vΒ² = (2 Γ 0.28)/0.04
vΒ² = 14
v = β14
v = 3.74 m/s
(9d)
(i) Bulk modulus
Bulk modulus is a measure of a material's resistance to compression under uniform pressure.
(ii) Energy gained by the wire
Given:
Mass (m) = 2.5g = 0.0025kg
Extension (x) = 2cm = 0.02m
g = 10m/sΒ²
Force (F) = mg = 0.0025 Γ 10 = 0.025N
Energy gained (E) = (1/2)Fx
= (1/2) Γ 0.025 Γ 0.02
= 2.5 Γ 10β»β΄ J
Join my telegram channel πππ
https://t.me/ExamkeyNet
Slope = βF/βe
Point 1: (Extension = 10.0 cm, Force = 2.0 N)
Point 2: (Extension = 30.0 cm, Force = 6.0 N)
S = (6.0-2.0)/(30.0-10.0)
S = 4.0/20.0
S = 0.2N/cm
(9biii)
The slope represents the spring constant
k, indicating the stiffness of the spring.
(9c)
Given:
Mass (m) = 40 g = 0.04 kg
Elastic constant (k) = 350 N/m
Extension (x) = 4 cm = 0.04 m
Elastic potential energy stored in the rubber(E) = (1/2)kxΒ²
= (1/2) Γ 35 Γ (0.04)Β²
(1/2) Γ 35 Γ 0.0016
= 0.28 J
This energy is converted to kinetic energy of the stone:
K = (1/2)mvΒ² = E
(1/2)mvΒ² = 0.28 J
(1/2) Γ 0.04 Γ vΒ² = 0.28
vΒ² = (2 Γ 0.28)/0.04
vΒ² = 14
v = β14
v = 3.74 m/s
(9d)
(i) Bulk modulus
Bulk modulus is a measure of a material's resistance to compression under uniform pressure.
(ii) Energy gained by the wire
Given:
Mass (m) = 2.5g = 0.0025kg
Extension (x) = 2cm = 0.02m
g = 10m/sΒ²
Force (F) = mg = 0.0025 Γ 10 = 0.025N
Energy gained (E) = (1/2)Fx
= (1/2) Γ 0.025 Γ 0.02
= 2.5 Γ 10β»β΄ J
Join my telegram channel πππ
https://t.me/ExamkeyNet
π18β€8β1
Join my telegram channel πππ
https://t.me/ExamkeyNet
https://t.me/ExamkeyNet
π8β€2π€2π€2
PHYSICS OBJ
01-10: BBCDACBCBB
11-21: ADBBCCDCBC
21-30: CDABAAADBA
31-40: ABABCCBCDA
41-50: BBACBBCABC
*COMPLETED*β
Join my telegram channel πππ
https://t.me/ExamkeyNet
01-10: BBCDACBCBB
11-21: ADBBCCDCBC
21-30: CDABAAADBA
31-40: ABABCCBCDA
41-50: BBACBBCABC
*COMPLETED*β
Join my telegram channel πππ
https://t.me/ExamkeyNet
π11π―4β€3π€3π«‘3π€2
WAEC UP NEXT 22ND MAY 2025
CHEMISTRY THEORY & OBJ #1500
LITERATURE PROSE & OBJ #1000
GET IT BY 11PM TONIGHT
WHATSAPP 09056863938 ONLY
CHEMISTRY THEORY & OBJ #1500
LITERATURE PROSE & OBJ #1000
GET IT BY 11PM TONIGHT
WHATSAPP 09056863938 ONLY
β€6π6π2
PLS IF YOU HAVE YOUR FRIENDS DOING WAEC AND NECO 2025 SHOULD BE ADDED TO THIS CHANNEL
NO GO GET SCAMMED PLS INVITE AND SHARE THE EXAMKEY CHANNEL LINK !!!π
https://t.me/ExamkeyNet
https://t.me/ExamkeyNet
Join channel for moreπ
https://t.me/ExamkeyNet
Pls let's power share the links π€²βοΈπ.
NO GO GET SCAMMED PLS INVITE AND SHARE THE EXAMKEY CHANNEL LINK !!!π
https://t.me/ExamkeyNet
https://t.me/ExamkeyNet
Join channel for moreπ
https://t.me/ExamkeyNet
Pls let's power share the links π€²βοΈπ.
π6β€3
Chemistry theory and obj question dropped
To get it #1500
WhatsApp 09056863938 only.
Join my telegram channel πππ
https://t.me/ExamkeyNet
To get it #1500
WhatsApp 09056863938 only.
Join my telegram channel πππ
https://t.me/ExamkeyNet
π6π―6β€1
*Payment is Done below πππ
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
β12π2
WAEC UP NEXT 22ND MAY 2025
CHEMISTRY THEORY & OBJ #1500
LITERATURE PROSE & OBJ #1000
GET IT BY 11PM TONIGHT
WHATSAPP 09056863938 ONLY
CHEMISTRY THEORY & OBJ #1500
LITERATURE PROSE & OBJ #1000
GET IT BY 11PM TONIGHT
WHATSAPP 09056863938 ONLY
π2β€1π1
1500
*Payment is Done below πππ
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
Join my telegram channel πππ
https://t.me/ExamkeyNet
*Payment is Done below πππ
Account Number:-9056863938
Bank Name:- Palm pay / Opay
Account Name :- Blessing Amao
Pls drop payment proof after payment is done.
Join my telegram channel πππ
https://t.me/ExamkeyNet
π11β€5β4π€1
CHEMISTRY OBJ ANSWERS
01-10 BCAACBBBCC
11-20 CCAAAABABA
21-30 BBABDADCAC
31-40 ABDBCDBBAA
41-50 BCBACCDDDB
51-60 ADACCCDAAD
COMPLETED β β β
Join my telegram channel πππ
https://t.me/ExamkeyNet
01-10 BCAACBBBCC
11-20 CCAAAABABA
21-30 BBABDADCAC
31-40 ABDBCDBBAA
41-50 BCBACCDDDB
51-60 ADACCCDAAD
COMPLETED β β β
Join my telegram channel πππ
https://t.me/ExamkeyNet
π16β€7π€¬5π―1
Join my telegram channel πππ
https://t.me/ExamkeyNet
https://t.me/ExamkeyNet
π12β€4π―2π€1π1