for the following linear system, first equation: x + y = 1  , second equation: 4x + 4y = 4    there is

Performing algebraic operations on the system alter the solution set

A homogeneous system always has at least one solution

In EchelonForms, if there are any rows consists entirely of zeros, they are groubed at the top of the matrix

A matrix in reduced row-echelon form is of necessity in row-echelon form and vice versa

zero matrix is in reduced row-echelon form

The homogeneous linear system has only two possibilities for its solutions

The homogeneous linear system can only have a trivial solution

The homogeneous linear system can have nontrivial solutions

The homogeneous linear system can have no solution

in scalar multiplication we multiply a row vector by a column vector

when we multiply a number to a matrix of linear system, we multiply it to either one row or one column

To multiply two matrices A and B, the number of columns of A must be the same number of rows of B

The resulting matrix for multiplying A and B has the same number of rows as A and the same number of columns as B

With matrices, multiplication is not commutative

Zero matrix can't come in all different shapes and sizes

Identity matrix can come in all different shapes and sizes

If AX = I (identity matrix), then A is called invertible

If AX = I (identity matrix), We can get the value of X if we do this operation (1/A)

which sentence is true

if A is a n x n matrix, then the reduced row echelon form of A is I (identity matrix)