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القناة الأساسية
@stepbystep001

ومـما زادني شـرفـاً وتـيــهـاً
وكدت بأخمصي أطأ الـثريا
دخولي تحت قولك يا عبادي
وأن صـيَّرت أحمد لي نـبيـا
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|x| > a ⇔ x < -a or x > a
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المحاضرة التالتة 👇
linear function's degree can be
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0
18%
1
57%
A & B
2%
None of these
constant function's degree can be
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0
19%
1
22%
A & B
8%
None of these
y = x^2 + 1
y is called
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dependent variable
22%
independent variable
y = x^2 + 1
x is called
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dependent variable
84%
independent variable
(f+g)(x) = f(x) + g(x) = h(x)
Domain of h(x) =
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Df U Dg
58%
Df ∩ Dg
(f.g)(x) = f(x) . g(x) = h(x)
Domain of h(x) =
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51%
Df U Dg
49%
Df ∩ Dg
(f-g)(x) = f(x) - g(x) = h(x)
Domain of h(x) =
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Df U Dg
74%
Df ∩ Dg
(f/g)(x) = f(x) / g(x) = h(x)
Domain of h(x) =
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14%
Df U Dg - {x:g(x) != 0}
86%
Df ∩ Dg - {x:g(x) != 0}
a/b < c/d is equal to ad < cb
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T
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a/b = c/d is equal to ad = cb
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T
25%
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we say that the function isn't one to one when we prove that
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x1 ≠ x2 ⇒ f(x1) = f(x2)
13%
x1 = x2 ⇒ f(x1) = f(x2)
34%
x1 ≠ x2 ⇒ f(x1) ≠ f(x2)
we say that the function is one to one when we prove that
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x1 = x2 ⇒ f(x1) = f(x2)
19%
x1 ≠ x2 ⇒ f(x1) ≠ f(x2)
4%
x1 = x2 ⇒ f(x1) ≠ f(x2)
f(x) = √|x|
Domain of f =
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R+
2%
R-
58%
R
13%
R-{0}
علشان نثبت ان الدالة one to one ممكن بطريقتين
f(x1) = f(x2) ⇒ x1=x2
x1 ≠ x2 ⇒ f(x1) ≠ f(x2)
علشان نثبت ان الدالة مش one to one
x1 ≠ x2 ⇒ f(x1) = f(x2)
Z = Z' U 0 U Z+

(العلامة دي ' أقصد بيها الأس السالب ودي (+Z)أقصد بيها Z الموجبة )
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