#include <stdio.h>
#include <math.h>

int main(void) {
int a, b,c;
scanf("%d",&a);
scanf("%d",&b);
scanf("%d",&c);
printf("%d",(int)pow(a,b)%c);
return 0;
}
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Accenture Off-Campus Drive | 🎖2020 2021 batch | BE ME MCA MSc | 💰4.5LPA

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25025125225325401
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✅ Wipro Elite phase-2 off-campus drive

Position: Project Engineer

Qualification: B.E/B.Tech/M.E/M.Tech

Batch: 2020/2021/2022

Salary: Rs 3.5 LPA

Last Date to register: 31 January 2022

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awk 'BEGIN{FS="|";OFS=",";count=0}
(NR>1){
print $1,$3
count = count + 1
}END{
if(count == 0){
print "No records found."
}
}'

Painter code
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Client and number
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*InterntextEditor*


int n=scn.nextInt();

String a[]=new String[n];

String k="",kk="";;
for(int i=0;i<n;i++)
{
a[i]=scn.nextLine();
}

for(int i=0;i<n;i++)
{
String z[]=a[i].split(" ");
if(Integer.parseInt(z[0])==1)
{
kk=k;
k=k+z[1];
}
else if(Integer.parseInt(z[0])==2)
{
kk=k;
k=k.substring(0,k.length()-Integer.parseInt(z[1]));
}
else if(Integer.parseInt(z[0])==3)
{
System.out.println(k.charAt(Integer.parseInt(z[1])));
}
else if(Integer.parseInt(z[0])==4)
{
k=kk;
}
}

INTERN TEXT EDITOR
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EPAM EXAM 3PM SOLUTION GROUP
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Java
Fish in a fish tank code
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arr = [1, 2, 3, 4, 2, 7, 8, 8, 3];   

   

print("Duplicate elements in given array: ");  

#Searches for duplicate element  

for i in range(0, len(arr)):  

    for j in range(i+1, len(arr)):  

        if(arr[i] == arr[j]):  

            print(arr[j]);  
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TCS NQT & CAPGEMINI EXAM TOMORROW SOLUTION GROUP
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https:- https://t.me/good_coders

1. D(6)
2. 3.1746341
3.
4.
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Aptitude
1. D(6)
2. 3.1746341
3.
4.2
5.
6.

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Aptitude
1. D(6)
2. 3.1746341
3.5.5
4.2
5.12 years
6.9


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