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REVATURE Solution
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1.cloud service- all the above
2. DATA loss
3. Enterprise
4. Public cloud
5. Optn 134
6. Plan prepare listen close and clarify
7. If others have ..
8. Always listen to understand
9.it was nice....
10.politely ...
11. ....Print $1...
12. Sed 2 s...
13. Sort -r
14. Tee
18. 32
19. AVERAGE
23.all of the mentioned events
27.2 (overline as well as underline
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l,r=list(map(int,input().split()))
s=0
for i in range(l,r+1):
    dup=[]
    dup=list(map(int,str(i)))
    s=s+sum(dup)
print(s)

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int c = 0;
for(int i = 0; str[i] != '\0'; i++) {
if(str[i] == ch)
c++;
}
return c;




count of specific character

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def Check_Vow(string, vowels):
final = [each for each in string if each in vowels]
print(len(final))

string=input()
vowels = "AaEeIiOoUu"
Check_Vow(string, vowels);

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a=input()
b="aeiou"
c=0
for char in a:
if char in b:
c+=1
Print(c)
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Safe square code
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