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TCS Numerical:
27th Feb Slot:10:00AM


1)2.17
2)5:8
3)48
4)117%
5)b
6)k+20
7)c -18
8)d- 7.235
9) a -250
10)c
11.5%
12.495
14 10240

βœ…Telegram- t.me/codingsolution_0
TCS Numerical:
27th Feb Slot:10:00AM


1)2.17
2)5:8
3)48
4)117%
5)b
6)k+20
7)c -18
8)d- 7.235
9) a -250
10)c
11.5%
12.495
13.july2
14.10240
15.50days

βœ…Telegram- https://t.me/coding_solution_0
16. C
Today Coding Solution Available here ❀️

https://t.me/offcampusjobs_0
https://t.me/offcampusjobs_0
TCS Numerical:
27th Feb Slot:10:00AM


1)2.17
2)5:8
3)48
4)117%
5)b
6)k+20
7)c -18
8)d- 7.235
9) a -250
10)c
11.5%
12.495
13. July 2
14. 10240
15. 50days
16. 8:15
17. 10 25 30 44

βœ…Telegram- https://t.me/coding_solution_0
18. 36
TCS Numerical:
27th Feb Slot:10:00AM


1)2.17
2)5:8
3)48
4)117%
5)b
6)k+20
7)c -18
8)d- 7.235
9) a -250
10)c
11.5%
12.495
13. July 2
14. 10240
15. 50days
16. 8:15
17. 10 25 30 44
18. 36
19. 10 5/7
20. 44 and 48

Telegram - https://t.me/coding_solution_0
21 4755
Verbal ability

1.DBEAC
2. Option 1(Yesterday)
3. Option 4 (a4,b2,c1,d3)
4. D - QRPS
5. C
6. RQ
7. A-3 B-1 c-2
8.B
9.encrypt
10.c
11.3 4 12
12.A
13.disrupt
14.Bi

TCS exam Ans 27/2/22

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2021/ 2022/ job Updates Available here ❀️

https://t.me/offcampusjobs_0
https://t.me/offcampusjobs_0
R=int(input())
C=int(input())
N=int(input())
matrix=[]
for i in range(R):
a =[]
for j in range(C):
a.append(int(input()))
matrix.append(a)
i=0
j=0
flag=0
for i in range(0,R):
for j in range(0,C):
if matrix[i][j]==N:
flag=1
break
if flag==1:
break
print(str(i)+","+str(j))

Python 3
Cab rental code
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https://t.me/coding_solution_0
Python 3
Cab rental code
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C language
Cab rental code
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Binary
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Job Job Job Updates πŸ“£
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Tcs 5th march solutions

1.C - tan-¹(3√2-3)
2.166.43
3. Increases by 5.6%
4. 143750
5. 6%
Or
5-15%
6- 3,00,000
7-34 & 35
8-200
9) 54
10) 4
11)3.2
12) 10
13) 960
14.10.5
15.C
16.7
17.11,200
18.18
19.25
20.8972
21.114
22.3856
23.6.25

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Channel name was changed to Β«TCS NQT Infytq Wipro Exam SolutionΒ»
βœ…Tcs verbal

1.EBACD
2.C
3.the incidents

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Coding Solution Available here ❀️

https://t.me/offcampusjobs_0
https://t.me/offcampusjobs_0
TCS NQT


1.b - tan-¹(3√2-3)
2.166.43
3. Increases by 5.6%
4. 143750
5) 15%
6.300000
7. 34 and 55
8. 200
9. 54
10. 4
11. 3.2
12. 10
13 960
14. 12.5
15 12.1
16 7
17 11200
18 16.41
19 25
20 8972
21 114
22 3856
23. 6.25
24 92
25 7.5
26 4.65

βœ…Tcs verbal

1.EBACD
2.C
3.the incidents

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