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C++👆

def authentication (n):
A=list(range(1,n+1))
i=2
While i<len(A):
A= A[j for j in range(len(A)) if j%i !=0]
i+=1
return ("Yes" if len(A)>0 else "No")

print(authentication(int(input()))

Python3
strong number

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TATA ELXSI EXAM SOLUTION
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TCS NQT Solution ❤️🚀

https://t.me/TcsNqt_solution
https://t.me/TcsNqt_solution
https://t.me/TcsNqt_solution

✅ TCS solutions

1.8
2.49
3.90
4.1596
5.4
6.5.14
7.4784
8.17.25
9.20
10.75.9
11.20

✅Telegram- https://t.me/Coding_solution_0

✅ TCS solutions

1.8
2.49
3.90
4.1596
5.4
6.5.14
7.4784
8.17.25
9.20
10.75.9
11.20
12.B

✅Telegram- https://t.me/Coding_solution_0

TCS NQT (04/02/22)
NUMERICAL..
----------------------
1.)8
2.)49
3.)90
4.)1596
5.)4
6.)5.14
7.)4784
8.)6.25
9.)20
10.)74.8 nanograms
11.)20%
12.)10 & 11
13.)45
14.)40
15.)4 Days
16.)-1/3
17.12.2

✅Telegram-https: //t.me/Coding_solution_0
t.me/Coding_solution_0
t.me/Coding_solution_0

---------------------
1.)8
2.)49
3.)90
4.)1596
5.)4
6.)5.14
7.)4784
8.)6.25
9.)20
10.)74.8 nanograms
11.)20%
12.)10 & 11
13.)45
14.)40
15.)4 Days
16.)-1/3
17.)12.2
18.)both I and II
19.)12.3
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http://t.me/Coding_solution_0

TCS NQT (05/02/22)
NUMERICAL..
----------------------
1.)8
2.)49
3.)90
4.)1596
5.)4
6.)5.14
7.)4784
8.)6.25
9.)20
10.)74.8 nanograms
11.)20%
12.)10 & 11
13.)45
14.)40
15.)4 Days
16.)-1/3
17.)12.2
18.)both I and II
19.)13.1
20.)18

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Add your 5 friends here Will Provide all the solution 🚀🚀

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http://t.me/Coding_solution_0
http://t.me/Coding_solution_0

1.8
2.49
3.90
4.1596
5.4
6.7.14
7.4784
8.17.25
9.20
10.75.9 nanog
11.20
12.10&11
13.69
14.80
15.4days
16.-1/3
17.12.2
18.both 1 and 2
19.13.1
20.18
21.3,2
22.the data is tri mode
23.2019
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http://t.me/Coding_solution_0
http://t.me/Coding_solution_0