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Next permutation in c#(Leetcode, Optimal one)

public void NextPermutation(int[] nums) {

int ind = -1;
int n = nums.Length;
@Coding_human
for(int i=n-2; i>=0; i--)
{
if(nums[i]<nums[i+1])
{
ind =i;
break;
}
}
if(ind==-1)
{
Array.Reverse(nums,0,n);
return;
}
for(int i=n-1; i>ind; i--)
{
if(nums[i]>nums[ind])
{
int swap=0;
swap = nums[i];
nums[i]=nums[ind];
nums[ind]=swap;
break;
}
}



Array.Reverse(nums,0+ind+1,nums.Length-1-ind);

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