📌Tech Mahindra Interview Experience

1) Asked my I'd card
2) Self intro
3) mentioned basics of Java
So he asked basics
4) Data types
5) Inheritance
6) Polymorphism
7) Exception
8) Are u willing to relocate
9) Are u comfortable with any
shifts
10) Are u interested in learning new
language

Telegram - @Coding_human

DCA java answer's


1. BC
D

2. {0,2,6,8}

3. public void addCrossMappings (CorsRegistry registry)

4. Failed

5. Display all the computer parts in ascending orders...

6. Larger Number: 25

7. There will be two errors....

8. A
9. 02
03
04
@Coding_human
10. -32767

11. 01
02

12. 5
D
1
4

13. Only i and ii

14. IT
Technical

15. Error

16. 25 days

telegram:- @Coding_human
https://t.me/Coding_human

n=int(input())
arr=[]
count=0
for x in range(n):
temp=list(map(int,input().split("/")))https://t.me/Coding_human
arr.append(temp)
if temp[1] in [1,3,5,7,8,10,12]:
count+=1
if count!=0:
print(count)
else:
for x in arr:
if x[2]%2==0:
count+=1
print(count)

DOB lucky draw code Python
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https://t.me/Coding_human

Amazon ,Flipkart loot deals (must check)
You will save your money definitely.

https://t.me/DMAD_Discussion

public class Main
{


public static void main(String[] args) {
int [] students = {4,9,5,3,2,10};
int counter;
for(int i=0; i<6; i++){
counter = 0;
for(int j=0; j<i; j++){
if (students[j] > students[i]){
counter += 1;
}

}
System.out.print(counter+" ");
}

}
}


University everywhere code in java

Telegram:-https://t.me/Coding_human

Harold and his homework

Python 3

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https://t.me/Coding_human
https://t.me/Coding_human

def solve(input1):
res=""
for i in input1:
if(i.isupper()):
res+="_"+i.lower()
else:
res+=i
print(res)

Modify Variable Names
Python 3✅

Telegram:-https://t.me/Coding_human

Anagrams code
Python
https://t.me/Coding_human
https://t.me/Coding_human

def change(input1):
# WRITE FROM BELOW
s=input1
if '_' in s:
t = s.split('_')
res = t[0]
for i in range(1,len(t)):
res+=t[i][0].upper()+t[i][1:]
return res
else:
res = [s[0]]
for c in s[1:]:
if c in ('ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
res.append('_')
res.append(c.lower())
else:
res.append(c)
return ''.join(res)
# NO NEED TO WRITE INPUT AND PRINT COMMANDS
# lANGUAGE PYTHON3
s=input()
print(change(s))

Modify Variable Code

TG : https://t.me/Coding_human

⚡ How Much SALARY Do You Expect?

✅ As a fresher, My 1st priority is to gain knowledge enhance my skills to be more productive for the company & also I need to become financially independent.

✅ So, I will accept what you offered as per the company norms which will fulfill my economical needs.

Telegram - https://t.me/Coding_human

1)240
2)78
3)
5- mother in law
7- 27 may Thursday cooking
9- only conclusion 2 3 and 4 follows
10-Both A and R are true and R is the correct explanation of A

Telegram - https://t.me/Coding_human

Some codes are already in the channel/group, you can search the code by their names.

Platinum airways code
Telegram : https://t.me/Coding_human
https://t.me/Coding_human
https://t.me/Coding_human

⚡What are your strengths and weaknesses?

✅ My strength is I am self-motivated, I can adjust myself to any environment, I don't wait for the deadline, I finish my work before the deadline.

✅ My weakness is I just can't keep any work pending. I wanted to complete my work on time, otherwisw it Disturbs my routine also.

Telegram - https://t.me/Coding_human

⚡What is the difference between confidence and over confidence?

I can do it because I am well prepared, this is confidence & I can do it easily and I don't need to prepare, this is overconfidence.

Telegram - https://t.me/Coding_human

def countPalin(str):
count = 0

# splitting each word as spaces as
# delimiter and storing it into a list
listOfWords = str.split(" ")

# Iterating every element from list
# and checking if it is a palindrome.
for elements in listOfWords:
if (checkPalin(elements)):

# if the word is a palindrome
# increment the count.
count += 1
print (count)

# Driver code
countPalin("Madam Arora teaches malayalam")
countPalin("Nitin speaks malayalam")

Python
Palindrome count
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Missing braces
Python
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n=input()
m=input()

if m in n:
print("yes")

else:
print("No")

Python
String within String Code
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n = int(input())
A = int(input())
A1 = []
A2= []
A3= []
ans = 0
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for i in range(n):
A1.append(int(input()))
for j in range(n):
A2.append(int(input()))
for k in range(n):
A2.append([p[k], b[k]])
a.sort()
for z in a:
if a[0] > N:
break
N += a[1]
ans += 1
print(ans)


Try this code for this question... Python 3

Telegram:-https://t.me/Coding_human
https://t.me/infosys_sp_dsp_all_code