Python minimum operation Code

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Replace diagonal c++ code accenture

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Accenture

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ACCENTURE EXAM ALL SLOTS SOLUTION GROUP:

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https://t.me/accenture_all_slots_exam_code

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N = int(raw_input().strip())

if N % 2 != 0:
print "Weird" @Coding_human
else:
if N >= 2 and N <= 5:
print "Not Weird"
elif N >= 6 and N <= 20:
print "Weird"
elif N > 20:
print "Not Weird"

Tg : @Coding_human

N = int(raw_input().strip())

if N % 2 != 0:
print "Weird" @Coding_human
else:
if N >= 2 and N <= 5:
print "Not Weird"
elif N >= 6 and N <= 20:
print "Weird"
elif N > 20:
print "Not Weird"

Accenture exam ans
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#include <bits/stdc++.h>
using namespace std;

int main() {
int n;
cin>>n;
set<int> s;
for(int i=0;i<=n;i++)
{
int x;
cin>>x;
s.insert(x);
}
cout<<s.size();
return 0;
}


Primes with a twist Code


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Numerical

1. 5.505
2.9.99hrs
3.2:5
4.6002
5.25
6.83.25
7. 70, 71
8. I and II but not III
9.only ll
10.820
11) 91

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def flip( ch):
return '1' if (ch == '0') else '0'

# Utility method to get minimum flips when
# alternate string starts with expected char
def getFlipWithStartingCharcter(str, expected):

flipCount = 0
for i in range(len( str)):

# if current character is not expected,
# increase flip count
if (str[i] != expected):
flipCount += 1

# flip expected character each time
expected = flip(expected)
return flipCount

# method return minimum flip to make binary
# string alternate
def minFlipToMakeStringAlternate(str):

# return minimum of following two
# 1) flips when alternate string starts with 0
# 2) flips when alternate string starts with 1
return min(getFlipWithStartingCharcter(str, '0'),
//allcoding1 getFlipWithStartingCharcter(str, '1'))

# Driver code to test above method
if name == "main":

str = "0001010111"
print(minFlipToMakeStringAlternate)

Python
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Infosys ans
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https://t.me/DMAD_Discussion
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10AM slot

@Coding_human
1)some bats
Only conclusion 1 folows
D

2)jitin at present
The data in both
A

3)some parks
Nethier consluion 1.


4)ram's brother.
The data in both satesment

5)graph
C
125 per

6)percentage of accidents
B
35000

7)deperments
C
100

8)all men are strong
Neither consluion.
A

9)class 6th grpah
D
100




1)some bats
Only conclusion 1 folows
D

2)jitin at present
The data in both
A

3)some parks
Nethier consluion 1.


4)ram's brother.
The data in both satesment

5)graph
C
125 per

6)percentage of accidents
B
35000

7)deperments
C
100

8)all men are strong
Neither consluion.
A

9)class 6th grpah
D
100

10)some pencil
Neither consluion
D

11)slipa
B
Is nessecary


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1)some bats
Only conclusion 1 folows
D

2)jitin at present
The data in both
A

3)some parks
Nethier consluion 1.


4)ram's brother.
The data in both satesment
@Coding_human
5)graph
C
125 per

6)percentage of accidents
B
35000
https://t.me/DMAD_Discussion
7)deperments
C
100

8)all men are strong
Neither consluion.
A

9)class 6th grpah
D
100

10)some pencil
Neither consluion
D

11)slipa
B
Is necessary



Telegram @Coding_human

Infosys ans⚡👆👆

Infosys result declared.

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Quadra coding python

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Parse file permission code c++
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for t in range(int(input())):
n=int(input())
i=1
s=0
while(s<n):
s=s+i*i
i=i+1
i=i-1
print(i)

Python
Healthy candies Code
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Unique character code python
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