#include<stdio.h>
int main(){
int a,b[20];
@Coding_human
scanf("%d",&a);
scanf("%d",&b);
if(a==5){
printf("No");
else
printf("Yes");
return 0;
}
C programming


John code @Coding_human

#include<stdio.h>
int main()@Coding_human
{
int a,b[20];
scanf("%d",&a);
scanf("%d",&b);
if(a==5){
printf("No");
else
printf("Yes");
return 0;
}

C programming
Research Lab
👇
@Coding_human
@Coding_human

Python
John code

@Coding_human
@Coding_human
@Coding_human
@Coding_human
@Coding_human

Reasoning 10 am slot

1 197
2 341
3 304
4 73
5. 858
6. 1122

Telegram: @Coding_human
@Coding_human
@Coding_human

Infosys exam EXAM 10.00 am

Telegram - @Coding_human
@Coding_human
------------------------------------------
Verbal ability Answers
-------------------------------------
1.)BADCE
2.)2,4,1,3
3.)imposing
4.)QSRP
5.)RP
@Coding_human
6.)plumbled....
7.)a successful...
8)parity
9.) vulnerable
10)Option D
11.)A-ii
12.)RS
13.)demure


Share in this format........Infosys exam EXAM 10.00 am

Telegram - @Coding_human
------------------------------------------
Verbal ability Answers
-------------------------------------
1.)BADCE
2.)2,4,1,3
3.)imposing
@Coding_human
4.)QSRP
5.)RP
6.)plumbled....
7.)a successful...
8)parity
9.) vulnerable
10)Option D
11.)A-ii
12.)RS
13.)demure


Telegram - @Coding_human

Infosys Answers

Telegram :
@Coding_human
@Coding_human
@Coding_human

LEE

D4 or 19

6G

6

D
@Coding_human

✅Infosys solutions

Keywords with answers


The line graph given. - X
192000
@Coding_human
Determine avg number -232
Graph -601
The gicen pie chart -31:32



100,20.......... Ans:40

✅Telegram- @Coding_human

LEE

D4 or 19. @Coding_human

6G

6

25

LEE

D4 or 19. @Coding_human

6G

6

25

14.66 per litre

Jack n james

9 litre

3F

Lee

D4 or 19. @Coding_human

6G

6

25

14.66 per litre

Jack n james

9 litre

3F

130
6/4
40

l9
215
100 second

Five
25
30 ways

Infosys exam EXAM 10.00 am

Telegram - @Coding_human
@Coding_human
------------------------------------------
Verbal ability Answers
-------------------------------------
1.)BADCE
2.)2,4,1,3
3.)imposing
4.)QSRP
5.)RP
@Coding_human
6.)plumbled....
7.)a successful...
8)parity
9.) vulnerable
10)Option D
11.)A-ii
12.)RS
13.)demure


Share in this format........Infosys exam EXAM 10.00 am

Telegram - @Coding_human
------------------------------------------
Verbal ability Answers
-------------------------------------
1.)BADCE
2.)2,4,1,3
3.)imposing
@Coding_human
4.)QSRP
5.)RP
6.)plumbled....
7.)a successful...
8)parity
9.) vulnerable
10)Option D
11.)A-ii
12.)RS
13.)demure


Telegram - @Coding_human

MINDTREE & Tcs IRA EXAM SOLUTION GROUP:
@Coding_human
@Coding_human
@DMAD_Discussion
@infosys_mindtree_exam_code

✅ Share post in ur college Whatsapp grps.

Max min prime code

Telegram :
@Coding_human
@Coding_human
@Coding_human

A in the string code java
@Coding_human
@Coding_human
@Coding_human

WIPRO EXAM ALL SLOTS SOLUTION GROUP:

@Coding_human
@Coding_human
@DMAD_Discussion
@wipro_exam_all_slots_code
https://t.me/wipro_exam_all_slots_code

✅ Share post in ur college Whatsapp grps.

E commerce code (@Coding_human)
C language. @Coding_human @Coding_human @Coding_human @Coding_human
@Coding_human
@Coding_human
@Coding_human

int main() {
char s[100];
int i;
@Coding_human
printf("\nEnter a string : ");
gets(s);
for (i = 0; s[i]!='\0'; i++) {
if(s[i] >= 'a' && s[i] <= 'z') {
s[i] = s[i] - 32;
}
}
printf("\nString in Upper Case = %s", s);
return 0;
}

Warehouse Code


Wipro EXAM answer's


Telegram👇
@Coding_human
@Coding_human

def getprime(n):
sum = 0
for digit in str(n):
num=int(n)
@Coding_human
if num > 1:
for i in range(2, int(num/2)+1):
if (num% i) == 0:
break
else:
sum += int(num)

Return sum


n = input()
Print (getprime(n))

Telegram👇
@Coding_human
@Coding_human
@Coding_human