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✅DUOLINGO - 125+🔥
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✅TOEFL - 90+
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TECH Mahindra Exam
Round 2
Help available.👨💻
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https://t.me/Coding_000/5567?single
https://t.me/Coding_000/5563?single
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Round 2
Help available.👨💻
100% Clearance GUARANTEE.✅
Check our past Results. 👇👇
https://t.me/Coding_000/5567?single
https://t.me/Coding_000/5563?single
Contact @ILOVEU_143 ✅
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Dm @ILOVEU_143✅
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𝐇𝐞𝐥𝐥𝐨 𝐄𝐯𝐞𝐫𝐲𝐨𝐧𝐞,
𝐔𝐧𝐥𝐨𝐜𝐤 𝐲𝐨𝐮𝐫 𝐥𝐞𝐚𝐫𝐧𝐢𝐧𝐠 𝐩𝐨𝐭𝐞𝐧𝐭𝐢𝐚𝐥 𝐰𝐢𝐭𝐡 𝐄𝐚𝐫𝐧𝐲𝐐𝐮𝐢𝐳! 🚀🧠 𝐃𝐚𝐢𝐥𝐲 𝐪𝐮𝐢𝐳𝐳𝐞𝐬, 𝐫𝐞𝐚𝐥 𝐫𝐞𝐰𝐚𝐫𝐝𝐬. 𝐉𝐨𝐢𝐧 𝐧𝐨𝐰: https://www.earnyquiz.in/ 🌟 https://t.me/+wDV6hLEouWI1MWU1
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😁😅Earn money by solving questions
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For Coding Help or Any Exam Help 😄
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Check the previous proofs 👆👆
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The Infosys online test for the SP role has been scheduled for Sunday,
21st January, 2024 from 2:30 PM to 5:30 PM.
The test window is stuck and the team is working from backend and it will be sorted in next 10 minutes
Don't refresh and close the window. Stay there.
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21st January, 2024 from 2:30 PM to 5:30 PM.
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#include <bits/stdc++.h>
using namespace std;
#define ll long long
ll dp[10005][2];
const int mod = (1e9 + 7);
ll solve(ll i, ll o, ll n, ll k, vector<ll> &v) {
if (i > n) {
return 0;
}
if (dp[i][o] != -1)
return dp[i][o];
ll ans = 0;
if (o == 0) {
for (int j = i; j < min(n + 1, i + k); j++) {
ans = max(ans, solve(j + 1, 1 - o, n, k, v)) % mod;
}
} else {
ll ta = 0;
ll mx = 0;
for (int j = i; j < min(n + 1, i + k); j++) {
if (ta + v[j] >= 0) {
ta += v[j];
mx = max(mx, ta);
} else {
ta = 0;
}
ll c = solve(j + 1, 1 - o, n, k, v) % mod;
ans = max(ans, ((j - i + 1) * mx) % mod + c % mod);
}
}
return dp[i][o] = ans;
}
int main() {
ll n, k;
cin >> n >> k;
vector<ll> v;
ll neg = 0;
for (int i = 0; i < n; i++) {
ll x;
cin >> x;
v.push_back(x);
if (x <= 0)
neg++;
}
if (neg == v.size()) {
cout << 0 << endl;
return 1;
}
memset(dp, -1, sizeof(dp));
cout << max(solve(0, 0, v.size() - 1, k, v), solve(0, 1, v.size() - 1, k, v)) << endl;
}
Array Segment
Infosys ✅
using namespace std;
#define ll long long
ll dp[10005][2];
const int mod = (1e9 + 7);
ll solve(ll i, ll o, ll n, ll k, vector<ll> &v) {
if (i > n) {
return 0;
}
if (dp[i][o] != -1)
return dp[i][o];
ll ans = 0;
if (o == 0) {
for (int j = i; j < min(n + 1, i + k); j++) {
ans = max(ans, solve(j + 1, 1 - o, n, k, v)) % mod;
}
} else {
ll ta = 0;
ll mx = 0;
for (int j = i; j < min(n + 1, i + k); j++) {
if (ta + v[j] >= 0) {
ta += v[j];
mx = max(mx, ta);
} else {
ta = 0;
}
ll c = solve(j + 1, 1 - o, n, k, v) % mod;
ans = max(ans, ((j - i + 1) * mx) % mod + c % mod);
}
}
return dp[i][o] = ans;
}
int main() {
ll n, k;
cin >> n >> k;
vector<ll> v;
ll neg = 0;
for (int i = 0; i < n; i++) {
ll x;
cin >> x;
v.push_back(x);
if (x <= 0)
neg++;
}
if (neg == v.size()) {
cout << 0 << endl;
return 1;
}
memset(dp, -1, sizeof(dp));
cout << max(solve(0, 0, v.size() - 1, k, v), solve(0, 1, v.size() - 1, k, v)) << endl;
}
Array Segment
Infosys ✅
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#include <iostream>
#include <vector>
#include <deque>
#include <unordered_map>
using namespace std;
int smartTaxiDriver(int N, int K, vector<int>& T, vector<int>& P, vector<int>& C) {
unordered_map<int, vector<pair<int, int>>> g;
for (int i = 0; i < N - 1; ++i) {
g[P[i] - 1].push_back({i + 2, C[i]});
}
int mpc = 0;
for (int sn = 1; sn <= N; ++sn) {
vector<int> d(N + 1, -1);
d[sn] = 0;
deque<pair<int, int>> q = {{sn, 0}};
while (!q.empty()) {
auto [cn, cd] = q.front();
q.pop_front();
for (auto& [ne, rd] : g[cn]) {
if (d[ne] == -1 || d[ne] > cd + rd) {
d[ne] = cd + rd;
q.push_back({ne, d[ne]});
}
}
}
int pc = 0;
for (int des : T) {
if (d[des] <= K) {
pc++;
}
}
mpc = max(mpc, pc);
}
return mpc - 1;
}
int main() {
int N, K;
cin >> N >> K;
vector<int> T(N - 1), P(N - 1), C(N - 1);
for (int i = 0; i < N - 1; ++i) {
cin >> T[i];
}
for (int i = 0; i < N - 1; ++i) {
cin >> P[i];
}
for (int i = 0; i < N - 1; ++i) {
cin >> C[i];
}
int res = smartTaxiDriver(N, K, T, P, C);
cout << res << endl;
return 0;
}
Smart Taxi Driver ✅
Infosys @coding_000❤️
#include <vector>
#include <deque>
#include <unordered_map>
using namespace std;
int smartTaxiDriver(int N, int K, vector<int>& T, vector<int>& P, vector<int>& C) {
unordered_map<int, vector<pair<int, int>>> g;
for (int i = 0; i < N - 1; ++i) {
g[P[i] - 1].push_back({i + 2, C[i]});
}
int mpc = 0;
for (int sn = 1; sn <= N; ++sn) {
vector<int> d(N + 1, -1);
d[sn] = 0;
deque<pair<int, int>> q = {{sn, 0}};
while (!q.empty()) {
auto [cn, cd] = q.front();
q.pop_front();
for (auto& [ne, rd] : g[cn]) {
if (d[ne] == -1 || d[ne] > cd + rd) {
d[ne] = cd + rd;
q.push_back({ne, d[ne]});
}
}
}
int pc = 0;
for (int des : T) {
if (d[des] <= K) {
pc++;
}
}
mpc = max(mpc, pc);
}
return mpc - 1;
}
int main() {
int N, K;
cin >> N >> K;
vector<int> T(N - 1), P(N - 1), C(N - 1);
for (int i = 0; i < N - 1; ++i) {
cin >> T[i];
}
for (int i = 0; i < N - 1; ++i) {
cin >> P[i];
}
for (int i = 0; i < N - 1; ++i) {
cin >> C[i];
}
int res = smartTaxiDriver(N, K, T, P, C);
cout << res << endl;
return 0;
}
Smart Taxi Driver ✅
Infosys @coding_000❤️
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#include <bits/stdc++.h>
using namespace std;
void solve(vector<vector<int>> vv, int operation, int xx, int yy, int &res)
{
for (int i = 1; i < 3; i++)
{
int sum1 = 0;
for (int j = 0; j < vv.size(); j++)
{
sum1 += vv[j][i - 1];
}
int sum2 = 0;
for (int j = 0; j < vv.size(); j++)
{
sum2 += vv[j][i];
}
if (sum1 == sum2)
{
res = min(res, operation);
}
return;
}
for (int i = 0; i < vv.size(); i++)
{
solve(vv, operation, xx, yy, res);
vector<int> p1 = vv[i];
reverse(p1.begin(), p1.end());
solve(vv, operation + yy, xx, yy, res);
vector<int> p2 = vv[i];
int temp1 = p2[0];
int temp2 = p2[1];
int temp3 = p2[2];
p2[2] = temp1;
p2[1] = temp3;
p2[0] = temp2;
solve(vv, operation + xx, xx, yy, res);
vector<int> p3 = vv[i];
temp1 = p2[0];
temp2 = p2[1];
temp3 = p2[2];
p2[2] = temp2;
p2[1] = temp1;
p2[0] = temp3;
solve(vv, operation + xx, xx, yy, res);
}
return;
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t = 1;
while (t--)
{
int n = 0, m = 0, a = 0, b = 0, c = 0, d = 0, sum = 0, diff = 0, maxN = 0, minN = 0, count = 0, temp = 0;
bool flag = false;
cin >> n;
cin >> m;
int xx;
cin >> xx;
int yy;
cin >> yy;
vector<vector<int>> vv(n, vector<int>(m));
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
cin >> vv[i][j];
}
}
if (n == 1)
{
cout << -1 << endl;
continue;
}
int res = INT_MAX;
solve(vv, 0, xx, yy, res);
cout << res << endl;
}
return 0;
}
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using namespace std;
void solve(vector<vector<int>> vv, int operation, int xx, int yy, int &res)
{
for (int i = 1; i < 3; i++)
{
int sum1 = 0;
for (int j = 0; j < vv.size(); j++)
{
sum1 += vv[j][i - 1];
}
int sum2 = 0;
for (int j = 0; j < vv.size(); j++)
{
sum2 += vv[j][i];
}
if (sum1 == sum2)
{
res = min(res, operation);
}
return;
}
for (int i = 0; i < vv.size(); i++)
{
solve(vv, operation, xx, yy, res);
vector<int> p1 = vv[i];
reverse(p1.begin(), p1.end());
solve(vv, operation + yy, xx, yy, res);
vector<int> p2 = vv[i];
int temp1 = p2[0];
int temp2 = p2[1];
int temp3 = p2[2];
p2[2] = temp1;
p2[1] = temp3;
p2[0] = temp2;
solve(vv, operation + xx, xx, yy, res);
vector<int> p3 = vv[i];
temp1 = p2[0];
temp2 = p2[1];
temp3 = p2[2];
p2[2] = temp2;
p2[1] = temp1;
p2[0] = temp3;
solve(vv, operation + xx, xx, yy, res);
}
return;
}
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t = 1;
while (t--)
{
int n = 0, m = 0, a = 0, b = 0, c = 0, d = 0, sum = 0, diff = 0, maxN = 0, minN = 0, count = 0, temp = 0;
bool flag = false;
cin >> n;
cin >> m;
int xx;
cin >> xx;
int yy;
cin >> yy;
vector<vector<int>> vv(n, vector<int>(m));
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
cin >> vv[i][j];
}
}
if (n == 1)
{
cout << -1 << endl;
continue;
}
int res = INT_MAX;
solve(vv, 0, xx, yy, res);
cout << res << endl;
}
return 0;
}
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#include <iostream>
#include <vector>
const int MOD = 1000000007;
using namespace std;
int countBeautifulSequences(int n) {
if (n == 1) {
return 1;
}
vector<int> dp(n + 1, 0);
dp[1] = 1;
for (int i = 1; i <= n; ++i) {
for (int j = i; j <= n; ++j) {
dp[j] = (dp[j] + dp[j - i]) % MOD;
}
}
return (dp[n] - 1 + MOD) % MOD;
}
int main() {
int n;
cin >> n;
int result = countBeautifulSequences(n);
cout << result << endl;
return 0;
}
Count Beautiful sequence✅
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#include <vector>
const int MOD = 1000000007;
using namespace std;
int countBeautifulSequences(int n) {
if (n == 1) {
return 1;
}
vector<int> dp(n + 1, 0);
dp[1] = 1;
for (int i = 1; i <= n; ++i) {
for (int j = i; j <= n; ++j) {
dp[j] = (dp[j] + dp[j - i]) % MOD;
}
}
return (dp[n] - 1 + MOD) % MOD;
}
int main() {
int n;
cin >> n;
int result = countBeautifulSequences(n);
cout << result << endl;
return 0;
}
Count Beautiful sequence✅
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