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𝐔𝐧𝐥𝐨𝐜𝐤 𝐲𝐨𝐮𝐫 𝐥𝐞𝐚𝐫𝐧𝐢𝐧𝐠 𝐩𝐨𝐭𝐞𝐧𝐭𝐢𝐚𝐥 𝐰𝐢𝐭𝐡 𝐄𝐚𝐫𝐧𝐲𝐐𝐮𝐢𝐳! 🚀🧠 𝐃𝐚𝐢𝐥𝐲 𝐪𝐮𝐢𝐳𝐳𝐞𝐬, 𝐫𝐞𝐚𝐥 𝐫𝐞𝐰𝐚𝐫𝐝𝐬. 𝐉𝐨𝐢𝐧 𝐧𝐨𝐰: https://www.earnyquiz.in/ 🌟 https://t.me/+wDV6hLEouWI1MWU1


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INFOSYS exam 👇👇👨‍💻

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The Infosys online test for the SP role has been scheduled for Sunday,
 21st January, 2024 from 2:30 PM to 5:30 PM. 
The test window is stuck and the team is working from backend and it will be sorted in next 10 minutes 
Don't refresh and close the window. Stay there.
The test will be starting soon and the time will be extended.

#include <bits/stdc++.h>
using namespace std;
#define ll long long
ll dp[10005][2];
const int mod = (1e9 + 7);

ll solve(ll i, ll o, ll n, ll k, vector<ll> &v) {
    if (i > n) {
        return 0;
    }
    if (dp[i][o] != -1)
        return dp[i][o];
    ll ans = 0;
    if (o == 0) {
        for (int j = i; j < min(n + 1, i + k); j++) {
            ans = max(ans, solve(j + 1, 1 - o, n, k, v)) % mod;
        }
    } else {
        ll ta = 0;
        ll mx = 0;
        for (int j = i; j < min(n + 1, i + k); j++) {
            if (ta + v[j] >= 0) {
                ta += v[j];
                mx = max(mx, ta);
            } else {
                ta = 0;
            }
            ll c = solve(j + 1, 1 - o, n, k, v) % mod;
            ans = max(ans, ((j - i + 1) * mx) % mod + c % mod);
        }
    }
    return dp[i][o] = ans;
}

int main() {
    ll n, k;
    cin >> n >> k;
    vector<ll> v;
    ll neg = 0;
    for (int i = 0; i < n; i++) {
        ll x;
        cin >> x;
        v.push_back(x);
        if (x <= 0)
            neg++;
    }

    if (neg == v.size()) {
        cout << 0 << endl;
        return 1;
    }
    memset(dp, -1, sizeof(dp));
 
    cout << max(solve(0, 0, v.size() - 1, k, v), solve(0, 1, v.size() - 1, k, v)) << endl;
}

Array Segment
Infosys ✅

#include <iostream>
#include <vector>
#include <deque>
#include <unordered_map>

using namespace std;

int smartTaxiDriver(int N, int K, vector<int>& T, vector<int>& P, vector<int>& C) {
    unordered_map<int, vector<pair<int, int>>> g;

    for (int i = 0; i < N - 1; ++i) {
        g[P[i] - 1].push_back({i + 2, C[i]});
    }

    int mpc = 0;

    for (int sn = 1; sn <= N; ++sn) {
        vector<int> d(N + 1, -1);
        d[sn] = 0;
        deque<pair<int, int>> q = {{sn, 0}};

        while (!q.empty()) {
            auto [cn, cd] = q.front();
            q.pop_front();

            for (auto& [ne, rd] : g[cn]) {
                if (d[ne] == -1 || d[ne] > cd + rd) {
                    d[ne] = cd + rd;
                    q.push_back({ne, d[ne]});
                }
            }
        }

        int pc = 0;
        for (int des : T) {
            if (d[des] <= K) {
                pc++;
            }
        }

        mpc = max(mpc, pc);
    }

    return mpc - 1;
}

int main() {
    int N, K;
    cin >> N >> K;

    vector<int> T(N - 1), P(N - 1), C(N - 1);
    for (int i = 0; i < N - 1; ++i) {
        cin >> T[i];
    }
    for (int i = 0; i < N - 1; ++i) {
        cin >> P[i];
    }
    for (int i = 0; i < N - 1; ++i) {
        cin >> C[i];
    }

    int res = smartTaxiDriver(N, K, T, P, C);
    cout << res << endl;

    return 0;
}

Smart Taxi Driver ✅
Infosys @coding_000❤️

#include <bits/stdc++.h>
using namespace std;

void solve(vector<vector<int>> vv, int operation, int xx, int yy, int &res)
{

    for (int i = 1; i < 3; i++)
    {
        int sum1 = 0;
        for (int j = 0; j < vv.size(); j++)
        {
            sum1 += vv[j][i - 1];
        }
        int sum2 = 0;
        for (int j = 0; j < vv.size(); j++)
        {
            sum2 += vv[j][i];
        }
        if (sum1 == sum2)
        {
            res = min(res, operation);
        }

        return;
    }
    for (int i = 0; i < vv.size(); i++)
    {
        solve(vv, operation, xx, yy, res);
        vector<int> p1 = vv[i];
        reverse(p1.begin(), p1.end());
        solve(vv, operation + yy, xx, yy, res);
        vector<int> p2 = vv[i];
        int temp1 = p2[0];
        int temp2 = p2[1];
        int temp3 = p2[2];
        p2[2] = temp1;
        p2[1] = temp3;
        p2[0] = temp2;
        solve(vv, operation + xx, xx, yy, res);
        vector<int> p3 = vv[i];
        temp1 = p2[0];
        temp2 = p2[1];
        temp3 = p2[2];
        p2[2] = temp2;
        p2[1] = temp1;
        p2[0] = temp3;
        solve(vv, operation + xx, xx, yy, res);
    }
    return;
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int t = 1;

    while (t--)
    {
        int n = 0, m = 0, a = 0, b = 0, c = 0, d = 0, sum = 0, diff = 0, maxN = 0, minN = 0, count = 0, temp = 0;
        bool flag = false;
        cin >> n;

        cin >> m;
        int xx;
        cin >> xx;
        int yy;
        cin >> yy;
        vector<vector<int>> vv(n, vector<int>(m));
        for (int i = 0; i < n; i++)
        {
            for (int j = 0; j < m; j++)
            {
                cin >> vv[i][j];
            }
        }
        if (n == 1)
        {
            cout << -1 << endl;
            continue;
        }
        int res = INT_MAX;
        solve(vv, 0, xx, yy, res);
        cout << res << endl;
    }
    return 0;
}

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