Hcl Help done ✅.. || Offcampus -s2
Test accomplished ❤️✓
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#Hcl #Offcampus #R1
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Revature { virtusa} - slots Are Available
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Accenture ONCAMPUS placement help available
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✅ College Computer Lab Access 🖥️
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30 Oct - 9 am & 12 pm
31 oct - 9 am & 12 pm
1 Nov - 9 am & 12 pm
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https://t.me/Code_alphix/8509
https://t.me/Code_alphix/8516
Successfully cleared Accenture ONCAMPUS ✓
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Preview ™ : https://t.me/Code_alphix/8314
💼 Accenture ONCAMPUS — My Experience & Tips! 💼
👉 https://t.me/Code_alphix
✨ Round 1 (Behaviour + Gaming Test):
🧩 Behaviour Test:
➡️ Take your time — spend 10–15 seconds on each question.
➡️ Think carefully; consistency matters more than speed.
👉 https://t.me/Code_alphix
🎮 Gaming Test:
🔥 Plan Route: Try to solve 2 out of 3 (I completed all 3 ✅)
🔥 Low to High: Aim for 20+ scores
🔥 Collect Keys: At least 2 out of 3 (I did 3/3 😎)
👉 https://t.me/Code_alphix
💬 Pro Tip: If you clear Round 1, the next rounds will feel much smoother and easier!
Stay patient, stay focused — you’ll make it too! 💪
📩 Join our community for placement help:
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🤝You will definitely shortlist for next round 🎉
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#!/bin/python3
def splitintoTwo(arr_count, arr):
if arr_count < 2:
return 0
total = sum(arr)
left = 0
count = 0
for i in range(arr_count - 1):
left += arr[i]
right = total - left
if left > right:
count += 1
return count
Splitintotwo ✓
🏆1
#!/bin/python3
def getAllowedRequests(user, timestamp, k):
from collections import defaultdict, deque
log = defaultdict(deque)
res = []
for u, t in zip(user, timestamp):
q = log[u]
while q and q[0] <= t - 60:
q.popleft()
if len(q) < k:
res.append(1)
q.append(t)
else:
res.append(0)
return res
👌1
import bisect
from collections import defaultdict
def getMinimunCost(s, t):
n, m = len(s), len(t)
if m > n:
return -1
pos = defaultdict(list)
for i, c in enumerate(s):
pos[c].append(i)
p = n
sm = 0
for k in range(m - 1, -1, -1):
c = t[k]
if c not in pos:
return -1
lst = pos[c]
i = bisect.bisect_left(lst, p)
if i == 0:
return -1
j = lst[i - 1]
p = j
sm += j
tot = n * (n - 1) // 2
rem = tot - sm
r = n - m
sh = r * (r - 1) // 2
return rem - sh
IBM help ✅ // plagfree ✓
DM for any placement Help
@Mrtrueliving_ix @Mrtrueliving_ix
from collections import defaultdict
def getMinimunCost(s, t):
n, m = len(s), len(t)
if m > n:
return -1
pos = defaultdict(list)
for i, c in enumerate(s):
pos[c].append(i)
p = n
sm = 0
for k in range(m - 1, -1, -1):
c = t[k]
if c not in pos:
return -1
lst = pos[c]
i = bisect.bisect_left(lst, p)
if i == 0:
return -1
j = lst[i - 1]
p = j
sm += j
tot = n * (n - 1) // 2
rem = tot - sm
r = n - m
sh = r * (r - 1) // 2
return rem - sh
IBM help ✅ // plagfree ✓
DM for any placement Help
@Mrtrueliving_ix @Mrtrueliving_ix
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Accenture ONCAMPUS placement help available
✅ Own Laptop 💻
✅ College Computer Lab Access 🖥️
💯 Guaranteed Test Clearance Support 👣
Slots timings:
30 Oct - 9 am & 12 pm
31 oct - 9 am & 12 pm
1 Nov - 9 am & 12 pm
DM for 💯 test Clearance ❤️
@Mrtrueliving_ix @Mrtrueliving_ix
Review proof 🧾
https://t.me/Code_alphix/8509
https://t.me/Code_alphix/8516
R4- communication ✓
https://t.me/Code_alphix/8539
Successfully cleared IBM - CIC ✓
DM FOR ANY PLACEMENT HELP
@Mrtrueliving_ix @Mrtrueliving_ix
#IBM #CIC #R1
https://t.me/Code_alphix/8549
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