COGNIZANT EXAM HELP GROUP
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πŸš€ Placement Preparation Hub

πŸŽ“ From Preparation to Placement

⚑ OA Support β€’ Coding β€’ Aptitude β€’ Technical β€’ HR

🌟 Trusted by Hundreds of Students

πŸ† 372+ Placement Successes βœ…

πŸ“© DM: @Mrtrueliving_ix

πŸ’™ Turning Aspirations into Offer Letters.
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🌟 Why You Should Join:

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Preview:
https://t.me/Code_alphix/8434?single
Google Help done βœ…


def solve(S, Q, Queries) βœ“

def solve (N, M, matrix, Q, query):βœ“

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Deloitte hiring HELP done βœ“


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All sections are done βœ“

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πŸ“© DM now for complete guidance & preparation support!

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πŸ’» Google
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πŸ’‘ Netcore
πŸ”₯ Virtusa Hackathon (SD–R2)
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πŸ’« From Aptitude ➜ Coding ➜ Interviews, we’ve got you covered πŸ’ͺ

Complete OA to Onboarding Process Available 🎯 πŸ”₯

πŸ“Œ Check the pinned message πŸ“„ to see success stories & proofs of our past placement assistance πŸ’―πŸš€


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Netcore Help βœ…


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Google Help done βœ…


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Netcore apply now

https://t.me/Code_alphix/8435

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πŸ“’ Accenture ONCAMPUS 2026 Test Pattern


Round 1: Aptitude / Personal / Logical


1️⃣ Personal Feedback – 54 questions (psychometric / behavioral)

2️⃣ Route the Plan – 3 questions (logic / flow-based reasoning)

3️⃣ Select Low to High Value – 25 questions
4️⃣ Escape Room – 3 questions (advanced logic / puzzle)

Round 2: Technical MCQs


πŸ“ 45 questions | 4-option MCQs
Topics: Programming, DBMS, OOP, Networking, Data Structures, Algorithms

Round 3: Coding & Simulation


πŸ’» Coding Question – Python / Java / C++

πŸ—„οΈ SQL Question – Queries on a given DB schema

🌐 Simulation – HTML, CSS, JS (UI / DOM logic)

πŸ”₯ Preparation Tip:

Focus on logic puzzles and coding practice

Revise database queries and front-end fundamentals

Be ready for behavioral/psychometric assessment


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Special Shoes Problem – Python Solution βœ…


πŸ’» Placement Practice: Netcore

def solve(N, K, L, R, Sn, Sk):
s, pre, res = set(Sk), [0]*(N+1), 0
for i in range(N): pre[i+1] = pre[i] + (Sn[i] in s)
j1 = j2 = 0
for i in range(N):
while j1 < N and pre[j1+1]-pre[i] < L: j1 += 1
while j2 < N and pre[j2+1]-pre[i] <= R: j2 += 1
res += max(0, j2 - j1)
return res

Stay tuned & share with your friends

https://t.me/Code_alphix

πŸ’― Verified codes βœ“ // netcore β„’
πŸ‘€1