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🕊️ Remembering Ratan Tata Sir


A true legend who inspired millions through his kindness, humility, and vision.
You taught us that success means nothing without compassion and honesty.
Your legacy will live forever in every heart you touched. ❤️

Gone from our sight, but never from our hearts.💔🫡🙏
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🚀 Form Alternating String – TCS CodeVita Round 1 (Zone 1)


---

#include <bits/stdc++.h>
using namespace std;

int main() {
string s;
cin >> s;
int n = s.length(), mrtrueliving_ix = 0;
vector<int> v(n);
for (int i = 0; i < n; ++i) cin >> v[i];

// 🔥 Join Telegram Channel for more codes: https://t.me/Code_alphix 🔥

int le = s[0] - '0', pl = v[0];
for (int i = 1; i < n; ++i) {
if (s[i] - '0' == le) {
mrtrueliving_ix += min(pl, v[i]);
pl = max(pl, v[i]);
} else {
le = s[i] - '0';
pl = v[i];
}
}
cout << mrtrueliving_ix;
return 0;
}


--
100% Correct Solution (C++)
💬 @Mrtrueliving_ix
📚 More codes: @Code_alphix
import heapq
from collections import defaultdict

def roll_e(t, l, f):
b = 7 - t
e = 7 - l
w = l
n = 7 - f
s = f
nt = w
nw = b
ne = t
nb = e
nn = n
ns = s
nl = nw
nf = ns
return (nt, nl, nf)

def roll_w(t, l, f):
b = 7 - t
e = 7 - l
w = l
n = 7 - f
s = f
nt = e
nw = t
ne = b
nb = w
nn = n
ns = s
nl = nw
nf = ns
return (nt, nl, nf)

def roll_s(t, l, f):
b = 7 - t
e = 7 - l
w = l
n = 7 - f
s = f
nt = n
nb = s
nn = b
ns = t
ne = e
nw = w
nl = nw
nf = ns
return (nt, nl, nf)

def roll_n(t, l, f):
b = 7 - t
e = 7 - l
w = l
n = 7 - f
s = f
nt = s
nb = n
nn = t
ns = b
ne = e
nw = w
nl = nw
nf = ns
return (nt, nl, nf)

def main():
n = int(input().strip())
pl = []
for _ in range(n):
a, b, d = input().strip().split()
pl.append((int(a), int(b), d))

pl.sort(key=lambda x: (x[0], x[1]))

pid = {1: (0, 0)}
idp = {(0, 0): 1}

dr = {"right": (1, 0), "left": (-1, 0), "top": (0, 1), "down": (0, -1)}

for a, b, d in pl:
if a not in pid:
continue
x, y = pid[a]
dx, dy = dr[d]
nx, ny = x + dx, y + dy
if (nx, ny) in idp:
oid = idp[(nx, ny)]
del pid[oid]
idp[(nx, ny)] = b
pid[b] = (nx, ny)

g = defaultdict(list)
for c, (x, y) in pid.items():
for d, (dx, dy) in dr.items():
nx, ny = x + dx, y + dy
if (nx, ny) in idp:
g[c].append((idp[(nx, ny)], d))

s, d = map(int, input().strip().split())
t, l, f = map(int, input().strip().split())

pq = []
heapq.heappush(pq, (0, s, t, l, f))
dist = defaultdict(lambda: float('inf'))
dist[(s, t, l, f)] = 0

while pq:
cst, u, t, l, f = heapq.heappop(pq)
if u == d:
print(cst)
return
if cst > dist[(u, t, l, f)]:
continue
for v, dr in g[u]:
if dr == "right":
nt, nl, nf = roll_e(t, l, f)
elif dr == "left":
nt, nl, nf = roll_w(t, l, f)
elif dr == "top":
nt, nl, nf = roll_n(t, l, f)
elif dr == "down":
nt, nl, nf = roll_s(t, l, f)
nc = cst + nt
if nc < dist[(v, nt, nl, nf)]:
dist[(v, nt, nl, nf)] = nc
heapq.heappush(pq, (nc, v, nt, nl, nf))

print(-1)

if __name__ == "__main__":
main()


Roll the dice ✓
Codevita all Codes available 😍
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#include <bits/stdc++.h>
using namespace std;

map<char,int> led={{'0',0b1111110},{'1',0b0110000},{'2',0b1101101},{'3',0b1111001},{'4',0b0110011},
{'5',0b1011011},{'6',0b1011111},{'7',0b1110000},{'8',0b1111111},{'9',0b1111011}};

bool valid(string t){
int h=stoi(t.substr(0,2)),m=stoi(t.substr(3,2));
return h>=1&&h<=12&&m>=0&&m<60;
}

int diffCost(string a,string b,int X,int Y){
int h1=stoi(a.substr(0,2)),m1=stoi(a.substr(3,2));
int h2=stoi(b.substr(0,2)),m2=stoi(b.substr(3,2));
int hd=abs(h1-h2);hd=min(hd,12-hd);
int md=abs(m1-m2);md=min(md,60-md);
return hd*60*X+md*Y;
}

int main(){
string time;cin>>time;
int X,Y;cin>>X>>Y;
vector<int> idx={0,1,3,4};
string best="";int bestCost=INT_MAX;
for(int i:idx){
char c=time[i];
for(int d='0';d<='9';d++){
if(d==c!led.count(c)!led.count(d))continue;
int x=led[c]^led[d];
if(__builtin_popcount(x)==1){
string t=time;t[i]=d;
if(valid(t)){
int cost=diffCost(time,t,X,Y);
if(cost<bestCost||(cost==bestCost&&t<best)){
best=t;bestCost=cost;
}
}
}
}
}
if(best=="")cout<<"No closest valid time possible";
else cout<<best;
return 0;
}

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