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import sys
try:
n = int(sys.stdin.readline().strip() or exit())
m = int(sys.stdin.readline().strip() or exit())
sys.stdin.readline()
adj = [[] for _ in range(n + 1)]
for _ in range(m):
u, v = map(int, sys.stdin.readline().strip().split())
adj[u].append(v)
adj[v].append(u)
res = 0
for i in range(1, n + 1):
d = len(adj[i])
if d == 1: res += 1
elif d > 1: res += sum(i % j == 0 or j % i == 0 for j in adj[i])
print(res)
except (IOError, ValueError, IndexError): pass
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def solution(word, skeletons):
ms = []
for skl in skeletons:
cf = True
sksc = set(c for c in skl if c != '-')
for i in range(len(word)):
wc = word[i]
skc = skl[i]
if skc == '-':
if wc not in sksc:
cf = False
break
elif wc != skc:
cf = False
break
if cf:
ms.append(skl)
return ms
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2 Programming Questions

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#include <iostream>
#include <vector>
#include <queue>
#include <cmath>
using namespace std;

bool is_perfect_square(long long n) {
long long sqrt_n = static_cast<long long>(std::sqrt(static_cast<double>(n)));
return sqrt_n * sqrt_n == n;
}

int solve(int n, vector<int>& val, vector<vector<int>>& edge) {
vector<vector<int>> adj_list(n);
for (const auto& e : edge) {
adj_list[e[0]].push_back(e[1]);
adj_list[e[1]].push_back(e[0]);
}

vector<int> parent(n, -1);
queue<int> q;
q.push(0);
vector<bool> visited(n, false);
visited[0] = true;
while (!q.empty()) {
int node = q.front();
q.pop();
for (int neighbor : adj_list[node]) {
if (!visited[neighbor]) {
parent[neighbor] = node;
q.push(neighbor);
visited[neighbor] = true;
}
}
}

int total_sum = 0;
for (int v = 0; v < n; v++) {
int t_v = 0;
if (is_perfect_square(2LL * val[v])) {
t_v++;
}
int current = v;
while (parent[current] != -1) {
int ancestor = parent[current];
long long sum = static_cast<long long>(val[v]) + val[ancestor];
if (is_perfect_square(sum)) {
t_v++;
}
current = ancestor;
}
total_sum += t_v;
}
return total_sum;
}


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