Successfully cleared Infosys Sp ๐
Test accomplished ๐ช๐ค
DM @Mrtrueliving_ix for ๐ฏ test Clearance
#Infosys #Sp #ONCAMPUS #upgrade
Review
https://t.me/code_alphix/6301?single
Test accomplished ๐ช๐ค
DM @Mrtrueliving_ix for ๐ฏ test Clearance
#Infosys #Sp #ONCAMPUS #upgrade
Review
https://t.me/code_alphix/6301?single
All placement help available
With ๐ฏ test Clearance โค๏ธ
๐1๐ฅ1
https://registration.techmahindra.com/Candidate/RegDefault.aspx
Tech Mahindra.....๐ค
Asap apply....
Batch : 2025 & 2026
Tech Mahindra.....๐ค
Asap apply....
Batch : 2025 & 2026
COGNIZANT EXAM HELP GROUP pinned ยซCognizant Technical Help available โ All cluster available ยฎ Python ยฎ Java ยฎ Csharp โ All timings Available โ only plagfree coding โ High success rate ๐ค DM @Mrtrueliving_ix for Help Those who need ๐ฏ test Clearance Reviewโฆยป
All placement help available
DM @Mrtrueliving_ix for test clearance ๐ฏ
No doubt for clearance ๐ฏ๐
DM @Mrtrueliving_ix for test clearance ๐ฏ
Final call for Cognizant - Technical
No doubt for clearance ๐ฏ๐
Cognizant 12pm Slots available ๐
Pics sharing || remote access available
๐ฏ Plagfree coding || test clearance ๐ฏ
DM @Mrtrueliving_ix...
Don't miss the opportunity ๐๐
Cognizant Help done โ
12 pm || test accomplished โค๏ธ
DM @Mrtrueliving_ix for test clearance ๐ฏ
#Cts #Offcampus #R3
12 pm || test accomplished โค๏ธ
DM @Mrtrueliving_ix for test clearance ๐ฏ
#Cts #Offcampus #R3
3pm cognizant Help AVAILABLE
Cognizant Help done โ
3 pm || test accomplished โค๏ธ๐ค
DM for Help
@Mrtrueliving_ix @Mrtrueliving_ix
#Cts #Offcampus #R3
3 pm || test accomplished โค๏ธ๐ค
DM for Help
All placement help available
@Mrtrueliving_ix @Mrtrueliving_ix
#Cts #Offcampus #R3
LG I hiring
Eligibility Criteria:
โข Education: B.E/B.Tech (IT/CS/ECE/EEE)
โข Passout Year: 2023/2024 / 2025
โขPassing Score: 65% and above throughout academics
โข Location: Bangalore
โข Mandate: Based out of Bangalore
โข CTC: 4.90 LPA
Apply Link:
https://chat.whatsapp.com/D2OGKtVfaHZ7XcAyzeBXMg
https://t.me/jobUpdatesclub/505
https://chat.whatsapp.com/K5I2JqrGT500M3Nt0rM6As
Test mail confirm
Eligibility Criteria:
โข Education: B.E/B.Tech (IT/CS/ECE/EEE)
โข Passout Year: 2023/2024 / 2025
โขPassing Score: 65% and above throughout academics
โข Location: Bangalore
โข Mandate: Based out of Bangalore
โข CTC: 4.90 LPA
Apply Link:
https://chat.whatsapp.com/D2OGKtVfaHZ7XcAyzeBXMg
https://t.me/jobUpdatesclub/505
https://chat.whatsapp.com/K5I2JqrGT500M3Nt0rM6As
Test mail confirm
SELECT
d.Driver_ID,
d.First_Name,
d.Last_Name,
d.Rating
FROM
driver d
WHERE
LOWER(d.First_Name) LIKE '%o%'
AND d.Rating >= 4.5
ORDER BY
d.Rating ASC;
Share with your friends too
https://t.me/code_alphix
Follow us for more codes
d.Driver_ID,
d.First_Name,
d.Last_Name,
d.Rating
FROM
driver d
WHERE
LOWER(d.First_Name) LIKE '%o%'
AND d.Rating >= 4.5
ORDER BY
d.Rating ASC;
Share with your friends too
https://t.me/code_alphix
Follow us for more codes
๐1
SELECT Vehicle_ID, Model, Capacity
FROM vehicle
WHERE Status = 'Available'
AND Vehicle_ID >= 2003
AND Vehicle_ID <= 2008;
https://t.me/code_alphix
FROM vehicle
WHERE Status = 'Available'
AND Vehicle_ID >= 2003
AND Vehicle_ID <= 2008;
https://t.me/code_alphix
import java.util.*;
class UserMainCode {
public int findCommonSubstrings(int input1, String input2, String input3) {
int k = input1;
if (input2.length() < k || input3.length() < k) return 0;
Set<String> substrings1 = new HashSet<>();
Set<String> substrings2 = new HashSet<>();
for (int i = 0; i <= input2.length() - k; i++) {
substrings1.add(input2.substring(i, i + k));
}
for (int i = 0; i <= input3.length() - k; i++) {
substrings2.add(input3.substring(i, i + k));
}
substrings1.retainAll(substrings2);
return substrings1.size();
}
}
class UserMainCode {
public int findCommonSubstrings(int input1, String input2, String input3) {
int k = input1;
if (input2.length() < k || input3.length() < k) return 0;
Set<String> substrings1 = new HashSet<>();
Set<String> substrings2 = new HashSet<>();
for (int i = 0; i <= input2.length() - k; i++) {
substrings1.add(input2.substring(i, i + k));
}
for (int i = 0; i <= input3.length() - k; i++) {
substrings2.add(input3.substring(i, i + k));
}
substrings1.retainAll(substrings2);
return substrings1.size();
}
}
โค2
Mahindra Rise Help done โ
Only coding ๐
DM @Mrtrueliving_ix for test clearance ๐ฏ
#Mahindra #Rise #Offcampus #Java
Only coding ๐
DM @Mrtrueliving_ix for test clearance ๐ฏ
#Mahindra #Rise #Offcampus #Java