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IBM Hiring

Role : Associate System Engineer

Eligible : 2024 only

Apply Link
https://ibmglobal.avature.net/en_US/careers/JobDetail/Associate-System-Engineer/7789
Amazon SDE help done

Test accomplished ❤️

All placement help available

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#AMAZON #SDE
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Wipro help available

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https://t.me/code_alphix/2890

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Uniqode Codes are available

Common prefix ❤️

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Uniqode Help done

All MCQs+ Coding are done


15 - McQs

2 - Coding 📱

Test accomplished


All placement help available ( 💯 test Clearance)

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@MRTRUELIVING_IX

#Uniqode #Summer #Done #2025
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Uniqode free answers

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Need coding help? We're here to assist you!

#coding #programming #codingsolutions
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def lcp_len(s1, s2):
m = min(len(s1), len(s2))
for i in range(m):
if s1[i] != s2[i]:
return i
return m

def max_lcp_len(strs):
if not strs:
return 0

max_len = 0
n = len(strs)

for i in range(n):
for j in range(i + 1, n):
len_lcp = lcp_len(strs[i], strs[j])
max_len = max(max_len, len_lcp)

return max_len

def solve(N, arr):
res = []
for i in range(N):
rem_strs = arr[:i] + arr[i+1:]
max_len = max_lcp_len(rem_strs)
res.append(max_len)

return res

Common prefix // uniqode
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def solve(n, nums, k, q, queries):
from collections import deque
dp = [0] * n
dq = deque()

for i in range(n):
while dq and dq[0] < i - k:
dq.popleft()
if dq:
dp[i] = max(nums[i], dp[dq[0]] + nums[i])
else:
dp[i] = nums[i]
while dq and dp[dq[-1]] < dp[i]:
dq.pop()
dq.append(i)

return [dp[q-1] for q in queries]

Alice in boderland // uniqode
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