COGNIZANT EXAM HELP GROUP
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All placement help available
#Hashdln #Shortlisted #Interview
def cleanupDataset(dataset, x, y):  
    cc = {} 
    for char in dataset: 
        cc[char] = cc.get(char, 0) + 1 

    idc = sum(count // 2 * x for count in cc.values()) 
    rm = sum(count % 2 for count in cc.values())
    for _ in range(1):pass
    dc = (rm // 2) * y 

    tc = idc + dc 
   
    return min(tc, (len(dataset) // 2) * y)

12/15 passed Amazon βœ…
ValueMomentum βœ…{java}
ValueMomentum βœ… round 2 {office mode}

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#ValueMomentum #Coding #JavaπŸ‘Œ
Starium round 2 results are out
Re check βœ…
❀3
⛔️the biggest scam in telegram...⛔️

2025 Batch  // Be alert

some  people are charged a high price between 4k to 5k Accenture { on // off campus} they started help 1k and now demanding 4k to 5k πŸ₯΅πŸ€¬πŸ€¬

they are well knowing group admins

if anyone ask 4k to 5k just ignore that

we know well about that work

compare to they we will do absolutely low price

some 2025 batch students send that chat conversation with us

don't go  that loop

#Scam #Alert #AccentureScam #ScamBatch #2024batchhelpers πŸ˜‚ #Fakepromotions

Expose soon stay tuned & alert βœ…

https://t.me/code_alphix/3626
πŸ”₯3🫑2πŸ‘Œ1
COGNIZANT EXAM HELP GROUP pinned «⛔️the biggest scam in telegram...⛔️ 2025 Batch  // Be alert some  people are charged a high price between 4k to 5k Accenture { on // off campus} they started help 1k and now demanding 4k to 5k πŸ₯΅πŸ€¬πŸ€¬ they are well knowing group admins if anyone ask 4k to…»
Cognizant sending technical assessment { reschedule}

Msb-v36😳

Check your mails βœ…

https://t.me/code_alphix/3357
Google Codes are available

Beautiful string πŸ‘
Good partitions πŸ‘

Dm-@mrtrueliving_ix
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Cognizant mock test done βœ…

Updated MSBπŸ””β–ΆοΈ


Cognizant slots are available

Limited slots available

DM for OA help with success @mrtrueliving_ix▢️
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Amazon all Codes available

Verfied codes available πŸ‘πŸ“£

Dm-@mrtrueliving_ix πŸ‘

Don't depend on free codes

πŸ’― Plag Free codes available πŸ‘
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def solve(N, A):
prefix_freq = [{} for _ in range(N)]
freq = {}

for q in range(N):
prefix_freq[q] = freq.copy()
freq[A[q]] = freq.get(A[q], 0) + 1

count = 0
for r in range(2, N - 1):
for s in range(r + 1, N):
if A[r] == 0:
if A[s] == 0:
count += (r * (r - 1)) // 2
continue

for q in range(1, r):
if A[q] == 0 and A[s] == 0:
count += prefix_freq[q].get(0, 0)
continue

qs = A[q] * A[s]
if qs % A[r] != 0:
continue

target = qs // A[r]
count += prefix_freq[q].get(target, 0)

return count

Count ways // Google πŸ‘
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Google Codes Available

β–ͺ️ Array and queries
β–ͺ️ Break and add

DM @mrtrueliving_ixπŸ‘
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Cgi sending interview mail's check πŸ‘

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@mrtrueliving_ix πŸ‘

Test Clearance ❀️
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All exams help available πŸ“―

β€’Accenture{ On Campus // Off campus}       


https://t.me/code_alphix/3524?single
β€’Wipro      
β€’Cognizant (cluster 1 & 2)            
β€’Capgemini
β€’Ge aerospace
β€’Phone pay
β€’Oracle
β€’Delta X
β€’Flipkart
β€’Amazon        
β€’IBM        
β€’Deloitte

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πŸ’― % success rate

DM for OA help:β†’
@mrtrueliving_ix

https://t.me/code_alphix

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@mrtrueliving_ix

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Successfully cleared round 2 πŸ“£

Tech Mahindra πŸ€—

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#Tech-Mahindra #shortlisted #Communication
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