COGNIZANT EXAM HELP GROUP
3.55K subscribers
5.3K photos
21 videos
10 files
3.22K links
๐Ÿš€ Placement Preparation Hub

๐ŸŽ“ From Preparation to Placement

โšก OA Support โ€ข Coding โ€ข Aptitude โ€ข Technical โ€ข HR

๐ŸŒŸ Trusted by Hundreds of Students

๐Ÿ† 372+ Placement Successes โœ…

๐Ÿ“ฉ DM: @Mrtrueliving_ix

๐Ÿ’™ Turning Aspirations into Offer Letters.
Download Telegram
def findMinincrease(threadSize):
n = len(threadSize)
m = n - 2
if m <= 0:
return 0

groupA_cost = 0
groupB_cost = 0

for f in range(2, n):
index = f - 1
left = threadSize[index - 1]
right = threadSize[index + 1]
target = max(left, right) + 1
cost = target - threadSize[index]
if cost < 0:
cost = 0
if f % 2 == 0:
groupA_cost += cost
else:
groupB_cost += cost

if m % 2 == 1:
return groupA_cost
else:
return min(groupA_cost, groupB_cost)

LinkedIn
MOD = 10**9 + 7

def comb3(n):
if n < 3:
return 0
return n * (n - 1) % MOD * (n - 2) % MOD * pow(6, MOD - 2, MOD) % MOD

def evenproduct(nums):
n = len(nums)
even = sum(1 for num in nums if num % 2 == 0)
odd = n - even

total_triplets = comb3(n)
odd_triplets = comb3(odd)

valid_triplets = (total_triplets - odd_triplets + MOD) % MOD

return valid_triplets


Even product// LinkedIn
def findMinIncrease(threadSize):
n = len(threadSize)
if n < 3:
return 0

required_increase = [0] * n
for i in range(1, n - 1):
needed = max(threadSize[i - 1], threadSize[i + 1]) + 1
required_increase[i] = max(0, needed - threadSize[i])

prev0 = (0, 0)
prev1 = (-1, 0)

for i in range(n):
current0 = (0, 0)
current1 = (0, 0)

if i in (0, n - 1):
current0 = max(prev0, prev1, key=lambda x: (x[0], -x[1]))
prev0 = current0
prev1 = (-1, 0)
continue

current0 = max(prev0, prev1, key=lambda x: (x[0], -x[1]))

if prev0[0] != -1:
current1 = (prev0[0] + 1, prev0[1] + required_increase[i])
else:
current1 = (-1, 0)

prev0 = current0
prev1 = current1 if current1[0] != -1 else (-1, 0)

final_ans = max(prev0, prev1, key=lambda x: (x[0], -x[1]))
return final_ans[1]
This media is not supported in your browser
VIEW IN TELEGRAM
This media is not supported in your browser
VIEW IN TELEGRAM
def windFarms(premium, x, y):
n = len(premium)
mx, my = sum(x[i] * premium[i] for i in range(n)) / sum(premium), sum(y[i] * premium[i] for i in range(n)) / sum(premium)
cx, cy = round(mx), round(my)
return sum(premium[i] * (abs(x[i] - cx) + abs(y[i] - cy)) for i in range(n))
De Shaw SLOTS are available

DM @mrtrueliving_ix โ–ถ๏ธ

Flag free Codes { Sucess rate}


๐Ÿ’ฏ Test Clearance โ˜„๏ธโ–ถ๏ธ
Please open Telegram to view this post
VIEW IN TELEGRAM
getNewPermutation ๐Ÿ“ฃ๐Ÿ‘โ–ถ๏ธ // De Shaw


DM @mrtrueliving_ixโ–ถ๏ธ
Please open Telegram to view this post
VIEW IN TELEGRAM
GetPerfectExecution stringโœ”๏ธ\ De Shaw

DM @mrtrueliving_ix
Please open Telegram to view this post
VIEW IN TELEGRAM
DM for plag free code ๐Ÿ“ฃ๐Ÿ””โ–ถ๏ธ

-
@mrtrueliving_ix

@Mrtrueliving_ix


De shaw slot are done โœ…

Only coding part
โ–ถ๏ธ

2/2 Codes done๐Ÿ“ฑ

All placement help available


#DeShaw #Coding #passed
Please open Telegram to view this post
VIEW IN TELEGRAM
๐Ÿ‘2โค1๐Ÿ‘Œ1๐Ÿซก1
Channel name was changed to ยซCognizant Rupeek LinkedIn Airtel Accenture Oracle De Shaw exam helpยป
IBM. // Data science

Coding along with SQL are done
๐Ÿ“ฑ

Test accomplished
๐Ÿฅ‡๐Ÿ”ˆ

DM for any placement help

-
@mrtrueliving_ix

-
@mrtrueliving_ix

-
@mrtrueliving_ix

#IBM #DataScience #Done

All placement help available
Please open Telegram to view this post
VIEW IN TELEGRAM
Expert Online Assessment Help!
- Cognizant
- Oracle
- Flipkart
- UBS
- Infosys-SP
- Meesho
- PhonePe
- Uber
- Accenture
- Cognizant
- IBM
- Mountblue
- QTIMINDS
- Mitsogo
- Lam Research

On/Off Campus Placement Solutions

All placement help


โœ… Guaranteed Test Clearance
โœ… Expert Guidance
โœ… Personalized Support

Don't Miss Out!

DM for OA Help:
@Mrtrueliving_ix

#PaidHelp #TestClearance
๐Ÿ‘1
RUBRIK OA HELP AVAILABLE โœ…โœ…


DM ME BOOK YOUR SLOT
- โœ…

โœ…DM - @mrtrueliving_ix

Remote Access Available


100% GUNRENTEE
Please open Telegram to view this post
VIEW IN TELEGRAM
Company Name: Paytm
Role: Business Analyst / Data Analyst
YOE:0-3
Branch : Btech/Mtech All branches


Apply Link:
https://docs.google.com/forms/d/e/1FAIpQLSekD6ieW7siBflZXPqXfeBImEWomGyGYJmdHoU1JQbR7i2yTA/viewform



Telegram channel: https://t.me/code_alphix
Cognizant slots are available

๐Ÿ’ฏ Test Clearance ๐Ÿค—

-
@mrtrueliving_ix ๐Ÿ”ฅ

-
@mrtrueliving_ix ๐Ÿ”ฅ

-
@mrtrueliving_ix ๐Ÿ”ฅ

Limited slots are available

Don't miss the opportunity ๐Ÿค—

All placement help available

#Cognizant #Aptitude #test #clearance๐Ÿ’ฏโ–ถ๏ธ

Check previous proofs ๐Ÿ‘

https://t.me/code_alphix/2882
Please open Telegram to view this post
VIEW IN TELEGRAM
This media is not supported in your browser
VIEW IN TELEGRAM
def getDistance(word):
m = {c: (r, i + (1 if r == 2 else 0))
for r, row in enumerate(["QWERTYUIOP", "ASDFGHJKL", "ZXCVBNM"])
for i, c in enumerate(row)}

for _ in range(10):
pass

total, pos = 0, m['Q']
for c in word:
p = m[c]
total += abs(pos[0] - p[0]) + abs(pos[1] - p[1])
pos = p

for _ in range(5):
pass

return total

Hackerank // typing distance { intern}
โค1