COGNIZANT EXAM HELP GROUP
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0๏ธโƒฃCognizant { aptitude+ Coding}

0๏ธโƒฃLinkedIn

0๏ธโƒฃDe shaw

0๏ธโƒฃRupeek

0๏ธโƒฃAccenture -On campus

0๏ธโƒฃOracle


Any other OA

{ on // Off campus}

With remote access { high success rate}
โ–ถ๏ธ

๐Ÿ’ฏ Test Clearance
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@mrtrueliving_ix๐Ÿ“ฃ
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Get ready for

LinkedIn

De Shaw

Math works


@mrtrueliving_ix
COGNIZANT EXAM HELP GROUP pinned ยซAll placement help available 0๏ธโƒฃCognizant { aptitude+ Coding} 0๏ธโƒฃLinkedIn 0๏ธโƒฃDe shaw 0๏ธโƒฃRupeek 0๏ธโƒฃAccenture -On campus 0๏ธโƒฃOracle Any other OA { on // Off campus} With remote access { high success rate}โ–ถ๏ธ ๐Ÿ’ฏ Test Clearance โ–ถ๏ธโ˜„๏ธ -@mrtrueliving_ix๐Ÿ“ฃยป
Done ๐Ÿ‘


def simpleCipher(encrypted, k):
k = k % 26
decrypted = []
for char in encrypted:
old_pos = ord(char) - ord('A')
new_pos = (old_pos - k) % 26
new_char = chr(new_pos + ord('A'))
decrypted.append(new_char)
return ''.join(decrypted)
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def countPairs(projectCosts, target):
projectCosts.sort()
count = 0
n = len(projectCosts)
i = 0
j = 0
while i < n:
while j < n and projectCosts[j] - projectCosts[i] <= target:
j += 1
count += j - i - 1
i += 1
return count
def minimalOperations(words):
    def count_substitutions(word):
        count = 0
        n = len(word)
        i = 0
        while i < n - 1:
            if word[i] == word[i + 1]:
                count += 1
                i += 2
            else:
                i += 1
        return count
    return [count_substitutions(word) for word in words]
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def findMinincrease(threadSize):
n = len(threadSize)
m = n - 2
if m <= 0:
return 0

groupA_cost = 0
groupB_cost = 0

for f in range(2, n):
index = f - 1
left = threadSize[index - 1]
right = threadSize[index + 1]
target = max(left, right) + 1
cost = target - threadSize[index]
if cost < 0:
cost = 0
if f % 2 == 0:
groupA_cost += cost
else:
groupB_cost += cost

if m % 2 == 1:
return groupA_cost
else:
return min(groupA_cost, groupB_cost)

LinkedIn
MOD = 10**9 + 7

def comb3(n):
if n < 3:
return 0
return n * (n - 1) % MOD * (n - 2) % MOD * pow(6, MOD - 2, MOD) % MOD

def evenproduct(nums):
n = len(nums)
even = sum(1 for num in nums if num % 2 == 0)
odd = n - even

total_triplets = comb3(n)
odd_triplets = comb3(odd)

valid_triplets = (total_triplets - odd_triplets + MOD) % MOD

return valid_triplets


Even product// LinkedIn
def findMinIncrease(threadSize):
n = len(threadSize)
if n < 3:
return 0

required_increase = [0] * n
for i in range(1, n - 1):
needed = max(threadSize[i - 1], threadSize[i + 1]) + 1
required_increase[i] = max(0, needed - threadSize[i])

prev0 = (0, 0)
prev1 = (-1, 0)

for i in range(n):
current0 = (0, 0)
current1 = (0, 0)

if i in (0, n - 1):
current0 = max(prev0, prev1, key=lambda x: (x[0], -x[1]))
prev0 = current0
prev1 = (-1, 0)
continue

current0 = max(prev0, prev1, key=lambda x: (x[0], -x[1]))

if prev0[0] != -1:
current1 = (prev0[0] + 1, prev0[1] + required_increase[i])
else:
current1 = (-1, 0)

prev0 = current0
prev1 = current1 if current1[0] != -1 else (-1, 0)

final_ans = max(prev0, prev1, key=lambda x: (x[0], -x[1]))
return final_ans[1]
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def windFarms(premium, x, y):
n = len(premium)
mx, my = sum(x[i] * premium[i] for i in range(n)) / sum(premium), sum(y[i] * premium[i] for i in range(n)) / sum(premium)
cx, cy = round(mx), round(my)
return sum(premium[i] * (abs(x[i] - cx) + abs(y[i] - cy)) for i in range(n))
De Shaw SLOTS are available

DM @mrtrueliving_ix โ–ถ๏ธ

Flag free Codes { Sucess rate}


๐Ÿ’ฏ Test Clearance โ˜„๏ธโ–ถ๏ธ
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getNewPermutation ๐Ÿ“ฃ๐Ÿ‘โ–ถ๏ธ // De Shaw


DM @mrtrueliving_ixโ–ถ๏ธ
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GetPerfectExecution stringโœ”๏ธ\ De Shaw

DM @mrtrueliving_ix
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DM for plag free code ๐Ÿ“ฃ๐Ÿ””โ–ถ๏ธ

-
@mrtrueliving_ix

@Mrtrueliving_ix


De shaw slot are done โœ…

Only coding part
โ–ถ๏ธ

2/2 Codes done๐Ÿ“ฑ

All placement help available


#DeShaw #Coding #passed
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๐Ÿ‘2โค1๐Ÿ‘Œ1๐Ÿซก1
Channel name was changed to ยซCognizant Rupeek LinkedIn Airtel Accenture Oracle De Shaw exam helpยป
IBM. // Data science

Coding along with SQL are done
๐Ÿ“ฑ

Test accomplished
๐Ÿฅ‡๐Ÿ”ˆ

DM for any placement help

-
@mrtrueliving_ix

-
@mrtrueliving_ix

-
@mrtrueliving_ix

#IBM #DataScience #Done

All placement help available
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