https://careers.morningstar.com/us/en/job/REQ-036608/MDP-Associate
4-5Lpa
Batch 20/21/22/23/24
Test mail confirmed 👍
4-5Lpa
Batch 20/21/22/23/24
Test mail confirmed 👍
All placement help available
I will guide today test
DM @mrtrueliving_ix
@mrtrueliving_ix
💯 Test Clearance▶️
I will guide today test
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@mrtrueliving_ix
💯 Test Clearance
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👍2
Successfully cleared Accenture on campus placement
Prev:
https://t.me/code_alphix/2970?single
https://t.me/code_alphix/2975
All placement help available
@mrtrueliving_ix
@mrtrueliving_ix
#Accenture #shortlisted #communication
#Remote access #100% Help
Prev:
https://t.me/code_alphix/2970?single
https://t.me/code_alphix/2975
All placement help available
@mrtrueliving_ix
@mrtrueliving_ix
#Accenture #shortlisted #communication
#Remote access #100% Help
@mrtrueliving_ix☄️
@mrtrueliving_ix▶️
👨💻🔘 MCQ + Coding Help 🔘 👨💻
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Aptitude + coding Help 👑
Remote Access Available ✔️
Proofs will be provided ✔️✔️
💯😔Genuine Help ✅
⭐ Accenture (MCQ+ Coding)
⭐ Capgemini
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@mrtrueliving_ix☄️
@mrtrueliving_ix▶️
💯 Test Clearance ✔️
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@mrtrueliving_ix▶️
😎All placement help available 😔
👨💻🔘 MCQ + Coding Help 🔘 👨💻
All Coding+MCQs Exams help Available ❤️
Aptitude + coding Help 👑
Remote Access Available ✔️
Proofs will be provided ✔️✔️
💯😔Genuine Help ✅
🔥All Companies help Available (Genuine + Clearance guarantee) ▶️
⭐ Accenture (MCQ+ Coding)
⭐ Capgemini
⭐ Cognizant
⭐ Wipro
⭐ Deloitte
⭐ Infosys
⭐ Tech Mahindra
⭐ Paytm
⭐ Samsung
⭐ Linkdin
All Mnc help available
@mrtrueliving_ix☄️
@mrtrueliving_ix▶️
💯 Test Clearance ✔️
😎All placement help available 😔
👨💻🔘 MCQ + Coding Help 🔘 👨💻
Help available
🔈 Accenture
🔈 Cognizant (Communication) -5pm
🔈 Juspay coding
🔈 Accenture (communication)
Any Kind Of OA { on // off}
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Test Clearance🥇
Any Kind Of OA { on // off}
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Test Clearance
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IBM// Data science
CODING & SQL are done▶️
All placement help available
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Test accomplished ❤️
CODING & SQL are done
All placement help available
@mrtrueliving_ix
Test accomplished ❤️
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Juspay coding help available
End time :8 pm
Asap complete your coding round
CTS communication help
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End time :8 pm
Asap complete your coding round
CTS communication help
DM @mrtrueliving_ix
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string largestMagical(string binString) {
if (binString.empty()) return binString;
vector<string> ans;
int cnt = 0, j = 0;
for (int i = 0; i < binString.size(); ++i) {
cnt += binString[i] == '1' ? 1 : -1;
if (cnt == 0) {
ans.push_back("1" + largestMagical(binString.substr(j + 1, i - j - 1)) + "0");
j = i + 1;
}
}
sort(ans.begin(), ans.end(), greater<string>());
return accumulate(ans.begin(), ans.end(), string{});
}Nvidia ✅
def max_distance(n, intervals):
intervals.sort(key=lambda x: x[1])
def possible(distance):
prev = intervals[0][0]
for start, end in intervals[1:]:
prev = max(prev + distance, start)
if prev > end:
return False
return True
low, high = 0, intervals[-1][1] - intervals[0][0]
while low <= high:
mid = (low + high) // 2
if possible(mid):
low = mid + 1
else:
high = mid - 1
return low - 1
n = int(input())
intervals = [list(map(int, input().split())) for _ in range(n)]
print(max_distance(n, intervals))
Juspay//The social distancing
#include <stdio.h>
#include <regex.h>
int isPowerOfTwo(const char *binaryString) {
regex_t regex;
int result;
result = regcomp(®ex, "^0*10*$", REG_EXTENDED);
if (result) {
printf("Could not compile regex\n");
return 0;
}
result = regexec(®ex, binaryString, 0, NULL, 0);
regfree(®ex);
if (!result) {
return 1;
} else {
return 0;
}
}
int main() {
int t;
char binaryString[1000];
scanf("%d", &t);
while (t--) {
scanf("%s", binaryString);
if (isPowerOfTwo(binaryString)) {
printf("True\n");
} else {
printf("False\n");
}
}
return 0;
}
Nvidia (Regex) ✅