// 14. Check if a given number is a palindrome or not using a while loop:

#include <stdio.h>

int main() {
    int num, originalNum, reversedNum = 0;

    printf("Enter a number: ");
    scanf("%d", &num);

    originalNum = num;

    while(num != 0) {
        reversedNum = reversedNum * 10 + num % 10;
        num /= 10;
    }

    if(originalNum == reversedNum) {
        printf("%d is a palindrome.\n", originalNum);
    } else {
        printf("%d is not a palindrome.\n", originalNum);
    }

    return 0;
}

// 15. Convert a decimal number to binary using a while loop:

#include <stdio.h>

int main() {
    int num, binary[32], i = 0;

    printf("Enter a decimal number: ");
    scanf("%d", &num);

    while(num > 0) {
        binary[i] = num % 2;
        num = num / 2;
        i++;
    }

    printf("Binary representation: ");
    for(int j = i-1; j >= 0; j--) {
        printf("%d", binary[j]);
    }
    printf("\n");

    return 0;
}

// 16. Convert a binary number to decimal using a while loop:

#include <stdio.h>
#include <math.h>

int main() {
    int binary, decimal = 0, base = 1, rem;

    printf("Enter a binary number: ");
    scanf("%d", &binary);

    while(binary > 0) {
        rem = binary % 10;
        decimal = decimal + rem * base;
        binary = binary / 10;
        base = base * 2;
    }

    printf("Decimal representation: %d\n", decimal);

    return 0;
}

// 17. Find the GCD of two numbers using a while loop:

#include <stdio.h>

int main() {
    int a, b;

    printf("Enter two numbers: ");
    scanf("%d %d", &a, &b);

    while(a != b) {
        if(a > b)
            a = a - b;
        else
            b = b - a;
    }

    printf("GCD is: %d\n", a);

    return 0;
}

// 18. Find the LCM of two numbers using a while loop:

#include <stdio.h>

int main() {
    int a, b, max;

    printf("Enter two numbers: ");
    scanf("%d %d", &a, &b);

    max = (a > b) ? a : b;

    while(1) {
        if(max % a == 0 && max % b == 0) {
            printf("LCM is: %d\n", max);
            break;
        }
        max++;
    }

    return 0;
}

// 19. Print all Armstrong numbers between 1 and 1000 using a for loop:

#include <stdio.h>
#include <math.h>

int main() {
    int num, originalNum, remainder, result, n;

    printf("Armstrong numbers between 1 and 1000 are:\n");
    for(num = 1; num <= 1000; num++) {
        originalNum = num;
        result = 0;
        n = log10(num) + 1;

        while(originalNum != 0) {
            remainder = originalNum % 10;
            result += pow(remainder, n);
            originalNum /= 10;
        }

        if(result == num) {
            printf("%d\n", num);
        }
    }

    return 0;
}

// 20. Print all perfect numbers between 1 and 1000 using a for loop:

#include <stdio.h>

int main() {
    int num, i, sum;

    printf("Perfect numbers between 1 and 1000 are:\n");
    for(num = 1; num <= 1000; num++) {
        sum = 0;

        for(i = 1; i <= num / 2; i++) {
            if(num % i == 0) {
                sum += i;
            }
        }

        if(sum == num && num != 0) {
            printf("%d\n", num);
        }
    }

    return 0;
}

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// Prints Current Time of India

#include <stdio.h>
#include <time.h>

int main() {
    time_t rawtime;
    struct tm *utc, ist;

    // Get current time in seconds since Epoch
    time(&rawtime);

    // Convert to UTC
    utc = gmtime(&rawtime);

    // Add 5 hours 30 minutes to UTC → IST
    ist = *utc;
    ist.tm_hour += 5;
    ist.tm_min  += 30;

    // Normalize (handle overflow like 24+ hours, 60+ minutes)
    mktime(&ist);

    printf("Indian Standard Time (IST): %02d:%02d:%02d\n",
           ist.tm_hour, ist.tm_min, ist.tm_sec);

    printf("Date: %02d-%02d-%04d\n",
           ist.tm_mday, ist.tm_mon + 1, ist.tm_year + 1900);

    return 0;
}

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