πAns. B | Explanation:
Interest earned on Rs. 13200 at a rate of 14% = Rs. 1848
Number of shares purchased = 13200/110 = 120
Dividend earned by him on 120 shares which pays a dividend of 15% per share = 120 Γ [(15/100) Γ 100] = Rs. 1800
Therefore, net profit = 1848 β 1800 = Rs. 48
Share & Join: @CSAT_2023
Interest earned on Rs. 13200 at a rate of 14% = Rs. 1848
Number of shares purchased = 13200/110 = 120
Dividend earned by him on 120 shares which pays a dividend of 15% per share = 120 Γ [(15/100) Γ 100] = Rs. 1800
Therefore, net profit = 1848 β 1800 = Rs. 48
Share & Join: @CSAT_2023
π3
A machine costs m rupees per day to maintain and n paise for each unit it produces. If the machine produces r units in a week, then which of the following is the total cost of operating the machine for a week?
Anonymous Quiz
12%
(a) 7m + 100nr
58%
(b) (700m + nr) /100
21%
(c) m + nr
9%
(d) 700mnr
π2
πAns. B | Explanation:
Cost of 1 day to maintain the machine = Rs. m
Therefore 7 dayβs cost for maintenance = Rs. 7m
Similarly, cost of 1 unit = n paise (for 1 day) = Rs. n/100
Therefore, cost of r units = Rs. rn/100
Hence, Total cost = 7m +( rn/100) = (700m + nr) /100
Share & Join: @CSAT_2023
Cost of 1 day to maintain the machine = Rs. m
Therefore 7 dayβs cost for maintenance = Rs. 7m
Similarly, cost of 1 unit = n paise (for 1 day) = Rs. n/100
Therefore, cost of r units = Rs. rn/100
Hence, Total cost = 7m +( rn/100) = (700m + nr) /100
Share & Join: @CSAT_2023
π2
Sonali leaves Delhi at 4 pm by a train and reaches Pune at 10 pm. Priyanka leaves Pune at 6 pm by a train and reaches Delhi at 11 pm on the same day. What is the time when they crossed each other?
Anonymous Quiz
40%
(a) 7:49 pm
24%
(b) 7:20 pm
22%
(c) 6:50 pm
14%
(d) 8:20 pm
π4
πAns. (a) | Explanation:
Let distance between Delhi and Pune be A km.
Time taken by Sonali to reach Pune = 10 β 4 = 6 hours
Time taken by Priyanka to reach Delhi = 11 β 6 = 5 hours
Speed of train which leaves Delhi = A/6 km/hr
And Speed of train which leaves Pune = A/5 km/hr
Relative speed = A/6 + A/5 = 11A/30 km/hr
Distance covered by train which leaves Delhi in 2 hours = 2 Γ A/6 = A/3 km
Distance left to be covered = A β A/3 = 2A/3 km
Time taken by both the trains to cross each other = Distance left to be covered/ Relative speed = (2A/3)/(11A/30) = 20/11 hours = 1 hour 49 minutes
Required time = 6 pm + 1 hour 49 minutes = 7: 49 pm
Hence, option (a) is the correct answer.
Share & Join: @CSAT_2023
Let distance between Delhi and Pune be A km.
Time taken by Sonali to reach Pune = 10 β 4 = 6 hours
Time taken by Priyanka to reach Delhi = 11 β 6 = 5 hours
Speed of train which leaves Delhi = A/6 km/hr
And Speed of train which leaves Pune = A/5 km/hr
Relative speed = A/6 + A/5 = 11A/30 km/hr
Distance covered by train which leaves Delhi in 2 hours = 2 Γ A/6 = A/3 km
Distance left to be covered = A β A/3 = 2A/3 km
Time taken by both the trains to cross each other = Distance left to be covered/ Relative speed = (2A/3)/(11A/30) = 20/11 hours = 1 hour 49 minutes
Required time = 6 pm + 1 hour 49 minutes = 7: 49 pm
Hence, option (a) is the correct answer.
Share & Join: @CSAT_2023
π5β€2
A museum has an average of 640 visitors on each Saturdays and Sundays, while 310 visitors on other days. The average number of visitors per day in a month of 30 days beginning with a Saturday is
Anonymous Quiz
8%
(a) 560
13%
(b) 240
18%
(c) 620
61%
(d) 420
π2
πAns. D | Explanaton:
In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 Γ 5 = 3200
Visitors on 5 Sundays = 640 Γ 5 = 3200
Visitors on Other days = 310 Γ 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
Share & Join: @CSAT_2023
In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 Γ 5 = 3200
Visitors on 5 Sundays = 640 Γ 5 = 3200
Visitors on Other days = 310 Γ 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
Share & Join: @CSAT_2023
π3
A shopkeeper labelled the price on his articles in such a manner so as to earn a profit of 30% on the cost price. He, then sold the articles by offering a discount of 10% on the labelled price. What is the actual profit percentage earned by him?
Anonymous Quiz
13%
(a) 18%
16%
(b) 15%
20%
(c) 20%
51%
(d) None of these
β€3π1
πAns. D | Explanaton:
Let the cost price of the articles be Rs. 100.
Shopkeeper labeled the price 30% higher than the cost price.
So, Marked price = 100 + 30% of 100 = 100 + 30 = Rs. 130
After giving a discount of 10%, the selling price of the articles = 0.9 Γ 130 = Rs. 117
So, actual profit percent = [(117 - 100)/100] Γ 100 = 17%
Share & Join: @CSAT_2023
Let the cost price of the articles be Rs. 100.
Shopkeeper labeled the price 30% higher than the cost price.
So, Marked price = 100 + 30% of 100 = 100 + 30 = Rs. 130
After giving a discount of 10%, the selling price of the articles = 0.9 Γ 130 = Rs. 117
So, actual profit percent = [(117 - 100)/100] Γ 100 = 17%
Share & Join: @CSAT_2023
π2
Rani bought more apples than oranges. She sells apples at Rs. 23 a piece and makes 15% profit. She sells orange at Rs. 10 a piece and makes 25% profit. If she gets Rs. 653 after selling all the apples and oranges, find her profit percentage.
Anonymous Quiz
10%
(a) 16.8%
53%
(b) 17.4%
29%
(c) 18.9%
8%
(d) 183%
π4
πAns. B | Explanaton:
Let number of apples and oranges that Rani brought be A and O respectively.
Now, 23A + 10O = 653
Since 653 has last digit as 3 which can come by multiplying 23 with 1, 11, 21, 31 and so on. Here, number of apples bought is greater than number of oranges. So, A > O
We can see that A = 21 and O = 17 is the only solution.
So, number of Apples bought = 21 and number of Oranges bought = 17.
Cost of an Apple = 23/1.15 and
Cost of an Orange = 10/1.25
Overall cost = (23/1.15) Γ 21 + (10/1.25) Γ 17 = 483/1.15 + 170/1.25 = 420 + 136 = 556
Profit = 653 β 556 = 97
Profit percentage = (97/556) x 100 = 17.4%
Share & Join: @CSAT_2023
Let number of apples and oranges that Rani brought be A and O respectively.
Now, 23A + 10O = 653
Since 653 has last digit as 3 which can come by multiplying 23 with 1, 11, 21, 31 and so on. Here, number of apples bought is greater than number of oranges. So, A > O
We can see that A = 21 and O = 17 is the only solution.
So, number of Apples bought = 21 and number of Oranges bought = 17.
Cost of an Apple = 23/1.15 and
Cost of an Orange = 10/1.25
Overall cost = (23/1.15) Γ 21 + (10/1.25) Γ 17 = 483/1.15 + 170/1.25 = 420 + 136 = 556
Profit = 653 β 556 = 97
Profit percentage = (97/556) x 100 = 17.4%
Share & Join: @CSAT_2023
π6β€1
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants. What is the ratio of the prices of one shirt and one pant?
Anonymous Quiz
19%
(a) 1 : 3
13%
(b) 4 : 5
62%
(c) 3 : 1
5%
(d) 5 : 4
π3π₯2β€1
πAns. C | Explanation:
Let price of one shirt be Rs. S and price of one pant be Rs. P.
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants.
So, 15S + 21P = 18S + 12P
β 21P - 12P = 18S β 15S
β 9P = 3S
β S/P = 9/3 = 3/1 = 3 : 1
Hence, the ratio of the prices of one shirt and one pant is 3 : 1.
Share & Join: @CSAT_2023
Let price of one shirt be Rs. S and price of one pant be Rs. P.
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants.
So, 15S + 21P = 18S + 12P
β 21P - 12P = 18S β 15S
β 9P = 3S
β S/P = 9/3 = 3/1 = 3 : 1
Hence, the ratio of the prices of one shirt and one pant is 3 : 1.
Share & Join: @CSAT_2023
π5
In an exam, average marks of A, B and C is 650. If marks of B are 50 more than A, and 20 less than C, then what must be the marks of C?
Anonymous Quiz
5%
(a) 615
18%
(b) 720
14%
(c) 580
63%
(d) 680
β€1π1
πAns. D | Explanation:
According to the question,
β [A + B + C]/3 = 650
β A + B + C = 1950 ------------------ (i)
Marks of B are 50 more than A, and 20 less than C.
So, marks of B = A + 50
Marks of C = B + 20 = A + 50 + 20 = A + 70
From equation (i), we get:
A + (A + 50) + (A + 70) = 1950
β 3A + 120 = 1950
β 3A = 1950 β 120 = 1830
β A = 1830/3 = 610
So, marks of C = A + 70 = 610 + 70 = 680
Share & Join: @CSAT_2023
According to the question,
β [A + B + C]/3 = 650
β A + B + C = 1950 ------------------ (i)
Marks of B are 50 more than A, and 20 less than C.
So, marks of B = A + 50
Marks of C = B + 20 = A + 50 + 20 = A + 70
From equation (i), we get:
A + (A + 50) + (A + 70) = 1950
β 3A + 120 = 1950
β 3A = 1950 β 120 = 1830
β A = 1830/3 = 610
So, marks of C = A + 70 = 610 + 70 = 680
Share & Join: @CSAT_2023
π7
Ratio of the speeds of Priyanka and Priya is 4:5. If Priya takes 44 minutes to reach a destination, then find the time taken by Priyanka to reach the same destination?
Anonymous Quiz
17%
(a) 36 minutes
12%
(b) 42 minutes
67%
(c) 55 minutes
4%
(d) 56 minutes
π3π₯1
πAns. C | Explanation:
Ratio of the speeds of Priyanka and Priya = 4:5
Ratio of the time taken by Priyanka and Priya = 5:4
So, let the time taken by Priyanka to reach the destination = 5x
Time taken by Priya to reach the destination = 4x
According to the question,
4x = 44
or, x = 11
So, Time taken by Priyanka to reach the destination = 5x = 5 Γ 11 = 55 minutes
Share & Join: @CSAT_2023
Ratio of the speeds of Priyanka and Priya = 4:5
Ratio of the time taken by Priyanka and Priya = 5:4
So, let the time taken by Priyanka to reach the destination = 5x
Time taken by Priya to reach the destination = 4x
According to the question,
4x = 44
or, x = 11
So, Time taken by Priyanka to reach the destination = 5x = 5 Γ 11 = 55 minutes
Share & Join: @CSAT_2023
π4
If Ξ± and Ξ² are two real numbers such that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r (p, q, r are natural numbers), then which one of the following alternatives represents the highest value?
Anonymous Quiz
9%
(a) 1 / (Ξ± + Ξ²)
25%
(b) (1/ Ξ±) + (1/ Ξ²)
54%
(c) β 1/ (Ξ±Ξ²)
11%
(d) Ξ±Ξ²/(Ξ± + Ξ²)
π3
πAns. C | Explanation:
It is given that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r
So, letβs assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (Ξ± + Ξ²) = - p/q = - (1/2)
(B) (1/ Ξ±) + (1/ Ξ²) = (Ξ± + Ξ²)/ Ξ±Ξ² = -(q/p) Γ (p/r) = - (q/r) = - (2/3)
(C) β 1/ (Ξ±Ξ²) = -(p/r) = - (1/3)
(D) Ξ±Ξ²/(Ξ± + Ξ²) = r/p Γ (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
Share & Join: @CSAT_2023
It is given that Ξ± + Ξ² = - q/p and Ξ±Ξ² = r/p, where 0<p<q<r
So, letβs assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (Ξ± + Ξ²) = - p/q = - (1/2)
(B) (1/ Ξ±) + (1/ Ξ²) = (Ξ± + Ξ²)/ Ξ±Ξ² = -(q/p) Γ (p/r) = - (q/r) = - (2/3)
(C) β 1/ (Ξ±Ξ²) = -(p/r) = - (1/3)
(D) Ξ±Ξ²/(Ξ± + Ξ²) = r/p Γ (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
Share & Join: @CSAT_2023
π1
What is the ratio of expected police-to-population ratio of West Bengal, Bihar and Andhra Pradesh taken together to the existing police-to-population ratio of Uttar Pradesh, Andhra Pradesh and Maharashtra taken together?
Anonymous Quiz
44%
(a) 2962 : 2955
27%
(b) 331 : 297
18%
(c) 93 : 97
11%
(d) 5920 : 6131
π2π₯2
πAns. A | Explanation:
Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
Share & Join: @CSAT_2023
Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
Share & Join: @CSAT_2023
π1