👆Ans. A | Explanation:
Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
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Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
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👍3❤1
एक फोन का अंकित मूल्य 16,000 रुपये है, जो फोन के लागत मूल्य से 60% अधिक है। यदि इसे अंकित मूल्य पर 12% की छूट पर बेचा जाए, तो लाभ प्रतिशत ज्ञात कीजिए।
Anonymous Quiz
6%
(a) 38.6%
21%
(b) 42.7%
36%
(c) 48.6%
36%
(d) 40.8%
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👆Ans. D | Explanation:
दिया गया है कि अंकित मूल्य है = 16000 रुपये
अत:, लागत मूल्य = (16000/160) × 100 = 10000 रुपये
यदि इसे 12% की छूट पर बेचा जाता है, तो विक्रय मूल्य = 16000 × (88/100) = 14080 रुपये
लागत मूल्य पर लाभ = 14080 - 10000 = 4080 रुपये
इस प्रकार, लाभ % = (4080/10000) × 100 = 40.8%
इसलिए विकल्प (d) सही उत्तर है।
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दिया गया है कि अंकित मूल्य है = 16000 रुपये
अत:, लागत मूल्य = (16000/160) × 100 = 10000 रुपये
यदि इसे 12% की छूट पर बेचा जाता है, तो विक्रय मूल्य = 16000 × (88/100) = 14080 रुपये
लागत मूल्य पर लाभ = 14080 - 10000 = 4080 रुपये
इस प्रकार, लाभ % = (4080/10000) × 100 = 40.8%
इसलिए विकल्प (d) सही उत्तर है।
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👍1🔥1
Animesh borrowed Rs.1625 from Anurag. He repaid Rs.10 in the first month and promised to increase the repayment amount by Rs.7.5 every month. In how many months will Animesh be able to return the whole amount (including the first month)?
Anonymous Quiz
8%
(a) 10 months
23%
(b) 15 months
25%
(c) 18 months
44%
(d) 20 months
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👆Ans. D | Explanation:
Payment done by Animesh in the first month = Rs.10
Payment done in the second month = Rs. 10 + 7.5 = Rs. 17.5, and so on.
It’s an arithmetic series, wherein a = 10, d = 7.5, Sn = 1625
We know that, Sn = (n/2) [2a + (n – 1) × d]
Or 1625 = (n/2) [2 × 10 + (n – 1) × 7.5]
Or 1625 = (n/2) [20 + (n – 1) × 15/2]
Or 1625 = (n/4) [40 + (n – 1) × 15]
Or 6500 = 40n + 15n2 – 15n
Or 15n2 + 25n – 6500 = 0
Or 3n2 + 5n – 1300 = 0
On solving it we get, n = 20 months
Hence, option (d) is correct.
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Payment done by Animesh in the first month = Rs.10
Payment done in the second month = Rs. 10 + 7.5 = Rs. 17.5, and so on.
It’s an arithmetic series, wherein a = 10, d = 7.5, Sn = 1625
We know that, Sn = (n/2) [2a + (n – 1) × d]
Or 1625 = (n/2) [2 × 10 + (n – 1) × 7.5]
Or 1625 = (n/2) [20 + (n – 1) × 15/2]
Or 1625 = (n/4) [40 + (n – 1) × 15]
Or 6500 = 40n + 15n2 – 15n
Or 15n2 + 25n – 6500 = 0
Or 3n2 + 5n – 1300 = 0
On solving it we get, n = 20 months
Hence, option (d) is correct.
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👍2
In a class, 40% of the boys is same as half of the girls, and there are 20 girls in total. Total number of students in the class is:
Anonymous Quiz
11%
(a) 70
62%
(b) 45
14%
(c) 35
13%
(d) 25
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👆Ans. B | Explanation:
40% of the boys is same as half of the girls, and there are 20 girls.
So, 40% of boys = 20/2 = 10
Therefore, 100% of boys = (10/40%) × 100% = 25
Therefore, total number of boys = 25
Thus, total number of students = 25 + 20 = 45
Hence, option (b) is correct.
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40% of the boys is same as half of the girls, and there are 20 girls.
So, 40% of boys = 20/2 = 10
Therefore, 100% of boys = (10/40%) × 100% = 25
Therefore, total number of boys = 25
Thus, total number of students = 25 + 20 = 45
Hence, option (b) is correct.
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👍3
A person deposited Rs. 13,200 in a bank, which pays 14% simple interest. If he rather had invested in Rs. 110 stocks which pay a dividend of 15% on the face value of Rs. 100, how much would he had lost or gained?
Anonymous Quiz
14%
(a) Loses Rs. 48
60%
(b) Gains Rs. 48
17%
(c) Loses Rs. 132
9%
(d) Gains Rs. 132
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👆Ans. B | Explanation:
Interest earned on Rs. 13200 at a rate of 14% = Rs. 1848
Number of shares purchased = 13200/110 = 120
Dividend earned by him on 120 shares which pays a dividend of 15% per share = 120 × [(15/100) × 100] = Rs. 1800
Therefore, net profit = 1848 – 1800 = Rs. 48
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Interest earned on Rs. 13200 at a rate of 14% = Rs. 1848
Number of shares purchased = 13200/110 = 120
Dividend earned by him on 120 shares which pays a dividend of 15% per share = 120 × [(15/100) × 100] = Rs. 1800
Therefore, net profit = 1848 – 1800 = Rs. 48
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👍3
A machine costs m rupees per day to maintain and n paise for each unit it produces. If the machine produces r units in a week, then which of the following is the total cost of operating the machine for a week?
Anonymous Quiz
12%
(a) 7m + 100nr
58%
(b) (700m + nr) /100
21%
(c) m + nr
9%
(d) 700mnr
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👆Ans. B | Explanation:
Cost of 1 day to maintain the machine = Rs. m
Therefore 7 day’s cost for maintenance = Rs. 7m
Similarly, cost of 1 unit = n paise (for 1 day) = Rs. n/100
Therefore, cost of r units = Rs. rn/100
Hence, Total cost = 7m +( rn/100) = (700m + nr) /100
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Cost of 1 day to maintain the machine = Rs. m
Therefore 7 day’s cost for maintenance = Rs. 7m
Similarly, cost of 1 unit = n paise (for 1 day) = Rs. n/100
Therefore, cost of r units = Rs. rn/100
Hence, Total cost = 7m +( rn/100) = (700m + nr) /100
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👍2
Sonali leaves Delhi at 4 pm by a train and reaches Pune at 10 pm. Priyanka leaves Pune at 6 pm by a train and reaches Delhi at 11 pm on the same day. What is the time when they crossed each other?
Anonymous Quiz
40%
(a) 7:49 pm
24%
(b) 7:20 pm
22%
(c) 6:50 pm
14%
(d) 8:20 pm
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👆Ans. (a) | Explanation:
Let distance between Delhi and Pune be A km.
Time taken by Sonali to reach Pune = 10 – 4 = 6 hours
Time taken by Priyanka to reach Delhi = 11 – 6 = 5 hours
Speed of train which leaves Delhi = A/6 km/hr
And Speed of train which leaves Pune = A/5 km/hr
Relative speed = A/6 + A/5 = 11A/30 km/hr
Distance covered by train which leaves Delhi in 2 hours = 2 × A/6 = A/3 km
Distance left to be covered = A – A/3 = 2A/3 km
Time taken by both the trains to cross each other = Distance left to be covered/ Relative speed = (2A/3)/(11A/30) = 20/11 hours = 1 hour 49 minutes
Required time = 6 pm + 1 hour 49 minutes = 7: 49 pm
Hence, option (a) is the correct answer.
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Let distance between Delhi and Pune be A km.
Time taken by Sonali to reach Pune = 10 – 4 = 6 hours
Time taken by Priyanka to reach Delhi = 11 – 6 = 5 hours
Speed of train which leaves Delhi = A/6 km/hr
And Speed of train which leaves Pune = A/5 km/hr
Relative speed = A/6 + A/5 = 11A/30 km/hr
Distance covered by train which leaves Delhi in 2 hours = 2 × A/6 = A/3 km
Distance left to be covered = A – A/3 = 2A/3 km
Time taken by both the trains to cross each other = Distance left to be covered/ Relative speed = (2A/3)/(11A/30) = 20/11 hours = 1 hour 49 minutes
Required time = 6 pm + 1 hour 49 minutes = 7: 49 pm
Hence, option (a) is the correct answer.
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👍5❤2
A museum has an average of 640 visitors on each Saturdays and Sundays, while 310 visitors on other days. The average number of visitors per day in a month of 30 days beginning with a Saturday is
Anonymous Quiz
8%
(a) 560
13%
(b) 240
18%
(c) 620
61%
(d) 420
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👆Ans. D | Explanaton:
In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 × 5 = 3200
Visitors on 5 Sundays = 640 × 5 = 3200
Visitors on Other days = 310 × 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
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In a month of 30 days beginning with Saturday, we will have 5 Saturdays, 5 Sundays and 20 Other days.
Visitors on 5 Saturdays = 640 × 5 = 3200
Visitors on 5 Sundays = 640 × 5 = 3200
Visitors on Other days = 310 × 20 = 6200
So, Total number of visitors in 30 days = 3200 + 3200 + 6200 = 12600
Average number of visitors per day = 12600/30 = 420
Hence, option (d) is the correct answer.
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👍3
A shopkeeper labelled the price on his articles in such a manner so as to earn a profit of 30% on the cost price. He, then sold the articles by offering a discount of 10% on the labelled price. What is the actual profit percentage earned by him?
Anonymous Quiz
13%
(a) 18%
16%
(b) 15%
20%
(c) 20%
51%
(d) None of these
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👆Ans. D | Explanaton:
Let the cost price of the articles be Rs. 100.
Shopkeeper labeled the price 30% higher than the cost price.
So, Marked price = 100 + 30% of 100 = 100 + 30 = Rs. 130
After giving a discount of 10%, the selling price of the articles = 0.9 × 130 = Rs. 117
So, actual profit percent = [(117 - 100)/100] × 100 = 17%
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Let the cost price of the articles be Rs. 100.
Shopkeeper labeled the price 30% higher than the cost price.
So, Marked price = 100 + 30% of 100 = 100 + 30 = Rs. 130
After giving a discount of 10%, the selling price of the articles = 0.9 × 130 = Rs. 117
So, actual profit percent = [(117 - 100)/100] × 100 = 17%
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👍2
Rani bought more apples than oranges. She sells apples at Rs. 23 a piece and makes 15% profit. She sells orange at Rs. 10 a piece and makes 25% profit. If she gets Rs. 653 after selling all the apples and oranges, find her profit percentage.
Anonymous Quiz
10%
(a) 16.8%
53%
(b) 17.4%
29%
(c) 18.9%
8%
(d) 183%
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👆Ans. B | Explanaton:
Let number of apples and oranges that Rani brought be A and O respectively.
Now, 23A + 10O = 653
Since 653 has last digit as 3 which can come by multiplying 23 with 1, 11, 21, 31 and so on. Here, number of apples bought is greater than number of oranges. So, A > O
We can see that A = 21 and O = 17 is the only solution.
So, number of Apples bought = 21 and number of Oranges bought = 17.
Cost of an Apple = 23/1.15 and
Cost of an Orange = 10/1.25
Overall cost = (23/1.15) × 21 + (10/1.25) × 17 = 483/1.15 + 170/1.25 = 420 + 136 = 556
Profit = 653 – 556 = 97
Profit percentage = (97/556) x 100 = 17.4%
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Let number of apples and oranges that Rani brought be A and O respectively.
Now, 23A + 10O = 653
Since 653 has last digit as 3 which can come by multiplying 23 with 1, 11, 21, 31 and so on. Here, number of apples bought is greater than number of oranges. So, A > O
We can see that A = 21 and O = 17 is the only solution.
So, number of Apples bought = 21 and number of Oranges bought = 17.
Cost of an Apple = 23/1.15 and
Cost of an Orange = 10/1.25
Overall cost = (23/1.15) × 21 + (10/1.25) × 17 = 483/1.15 + 170/1.25 = 420 + 136 = 556
Profit = 653 – 556 = 97
Profit percentage = (97/556) x 100 = 17.4%
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👍6❤1
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants. What is the ratio of the prices of one shirt and one pant?
Anonymous Quiz
19%
(a) 1 : 3
13%
(b) 4 : 5
62%
(c) 3 : 1
5%
(d) 5 : 4
👍3🔥2❤1
👆Ans. C | Explanation:
Let price of one shirt be Rs. S and price of one pant be Rs. P.
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants.
So, 15S + 21P = 18S + 12P
⇒ 21P - 12P = 18S – 15S
⇒ 9P = 3S
⇒ S/P = 9/3 = 3/1 = 3 : 1
Hence, the ratio of the prices of one shirt and one pant is 3 : 1.
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Let price of one shirt be Rs. S and price of one pant be Rs. P.
Price of 15 shirts and 21 pants is equal to the price of 18 shirts and 12 pants.
So, 15S + 21P = 18S + 12P
⇒ 21P - 12P = 18S – 15S
⇒ 9P = 3S
⇒ S/P = 9/3 = 3/1 = 3 : 1
Hence, the ratio of the prices of one shirt and one pant is 3 : 1.
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