A street vendor has enough money to buy 20 pairs of shoes. If he gets discount of Rs. 25 on each pair of shoe, then he can buy two more pairs of shoes, and still have Rs. 70 left with him. How much money did he have originally?
Anonymous Quiz
11%
(a) Rs. 4500
73%
(b) Rs. 4800
13%
(c) Rs. 5000
2%
(d) Rs. 5200
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👆Ans. B | Explanation:
Let the original price of each pair of shoe be Rs. x.
According to the question,
20x = 22(x – 25) + 70
or, 20x = 22x – 550 + 70
or, 22x – 20x = 480
or, 2x = 480
or, x = Rs. 240
So, the amount of money that street vendor originally had = 20x = 20 × 240 = Rs. 4800
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Let the original price of each pair of shoe be Rs. x.
According to the question,
20x = 22(x – 25) + 70
or, 20x = 22x – 550 + 70
or, 22x – 20x = 480
or, 2x = 480
or, x = Rs. 240
So, the amount of money that street vendor originally had = 20x = 20 × 240 = Rs. 4800
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In a certain code language, ‘NOTE’ is coded as ‘MONPSUDF’. How will ‘ROAD’ be coded as in that language?
Anonymous Quiz
66%
(a) QSNPZBCE
15%
(b) QSMPZBCE
11%
(c) QSNQZBCE
7%
(d) QSNPYBCE
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How many pairs of digits in the number 543968 have as many numbers between them as in the series of natural numbers (consider both backward and forward directions)?
Anonymous Quiz
12%
(a) Only one
42%
(b) More than one but less than three
38%
(c) More than three
9%
(d) Only three
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A is the mother of B. B is the sister of C. D is the son of C. E is the brother of D. F is the mother of E. G is the granddaughter of A. H has only two children - B and C. How is C related to E?
Anonymous Quiz
42%
(a) Father
24%
(b) Son
23%
(c) Mother
11%
(d) Cousin
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Which number will replace the question mark (?) in the following series?
A 0, D 5, H 15, M 30, S 50, ?
A 0, D 5, H 15, M 30, S 50, ?
Anonymous Quiz
14%
(a) A 75
16%
(b) A 65
60%
(c) Z 75
10%
(d) Z 85
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Four wooden sticks of lengths 85 cm, 119 cm, 136 cm and 204 cm are to be cut into parts of equal length. Each part must be as long as possible. What is the maximum number of pieces that can be cut?
Anonymous Quiz
6%
(a) 36
67%
(b) 32
20%
(c) 30
7%
(d) 35
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👆Ans. B | Explanation:
Since each stick must be cut into parts of equal length and each part must be as long as possible. So, we need to find out the HCF.
HCF of 85, 119, 136 and 204 = 17
Number of parts from 85 cm long stick = 85/17 = 5
Number of parts from 119 cm long stick = 119/17 = 7
Number of parts from 136 cm long stick = 136 /17 = 8
Number of parts from 204 cm long stick = 204 /17 = 12
∴ Maximum number of pieces = 5 + 7 + 8 + 12 = 32
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Since each stick must be cut into parts of equal length and each part must be as long as possible. So, we need to find out the HCF.
HCF of 85, 119, 136 and 204 = 17
Number of parts from 85 cm long stick = 85/17 = 5
Number of parts from 119 cm long stick = 119/17 = 7
Number of parts from 136 cm long stick = 136 /17 = 8
Number of parts from 204 cm long stick = 204 /17 = 12
∴ Maximum number of pieces = 5 + 7 + 8 + 12 = 32
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👍7
Dr. Bunti made a medicine by mixing two herbs X and Y. In 50 g of that medicine, the percentage of herb X is 40%. How much of herb X should Dr. Bunti add into it further so as to increase its percentage to 84%?
Anonymous Quiz
12%
(a) 142 g
23%
(b) 132.8 g
59%
(c) 137.5 g
7%
(d) 141.7 g
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👆Ans. C | Explanation:
According to the question,
Quantity of herb X in 50 g of medicine = (40/100) × 50 = 20 g
Let x g of herb X is further mixed in the medicine.
Then, [(20 + x)/(50 + x)] × 100 = 84
Or 2000 + 100x = 4200 + 84x
Or 16x = 2200
Or x = 2200/16
Or x = 137.5 g
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According to the question,
Quantity of herb X in 50 g of medicine = (40/100) × 50 = 20 g
Let x g of herb X is further mixed in the medicine.
Then, [(20 + x)/(50 + x)] × 100 = 84
Or 2000 + 100x = 4200 + 84x
Or 16x = 2200
Or x = 2200/16
Or x = 137.5 g
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👍3❤1
A faulty clock was set correct at 6:00 a.m. on Thursday. This clock gains 5 seconds in every 5 minutes. What must be the approximate time displayed by this clock at 5:30 p.m. on the same day?
Anonymous Quiz
53%
(a) 5:41 p.m.
20%
(b) 5:13 p.m.
19%
(c) 5:23 p.m.
7%
(d) 5:56 p.m.
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👆Ans. A | Explanation:
Total time from 6 a.m. to 5:30 p.m. = 11 hours 30 minutes = 690 minutes
Clock gains 5 seconds in every 5 minutes.
∴ Gain in 1 minute = 5/5 = 1 second
∴ Gain in 60 minutes = 60 × 1 = 60 seconds
∴ Gain in 690 minutes = 690 seconds = 690/60 minutes = 69/6 minutes = 23/2 minutes = 11.5 minutes OR 11 minutes 30 seconds
Hence, the correct time = 5:30 + 0:11 = 5:41 p.m. (approximately)
(as the clock is gaining time, it means it is running faster than it should and hence display time will be more than the real time)
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Total time from 6 a.m. to 5:30 p.m. = 11 hours 30 minutes = 690 minutes
Clock gains 5 seconds in every 5 minutes.
∴ Gain in 1 minute = 5/5 = 1 second
∴ Gain in 60 minutes = 60 × 1 = 60 seconds
∴ Gain in 690 minutes = 690 seconds = 690/60 minutes = 69/6 minutes = 23/2 minutes = 11.5 minutes OR 11 minutes 30 seconds
Hence, the correct time = 5:30 + 0:11 = 5:41 p.m. (approximately)
(as the clock is gaining time, it means it is running faster than it should and hence display time will be more than the real time)
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👍5
If α and β are two real numbers such that α + β = - q/p and αβ = r/p, where 0<p<q<r (p, q, r are natural numbers), then which one of the following alternatives represents the highest value?
Anonymous Quiz
6%
(a) 1 / (α + β)
37%
(b) (1/ α) + (1/ β)
47%
(c) – 1/ (αβ)
10%
(d) αβ/(α + β)
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👆Ans. C | Explanation:
It is given that α + β = - q/p and αβ = r/p, where 0<p<q<r
So, let’s assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (α + β) = - p/q = - (1/2)
(B) (1/ α) + (1/ β) = (α + β)/ αβ = -(q/p) × (p/r) = - (q/r) = - (2/3)
(C) – 1/ (αβ) = -(p/r) = - (1/3)
(D) αβ/(α + β) = r/p × (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
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It is given that α + β = - q/p and αβ = r/p, where 0<p<q<r
So, let’s assume p = 1, q = 2 and r = 3.
Putting these values in answer options, we get
(A) 1 / (α + β) = - p/q = - (1/2)
(B) (1/ α) + (1/ β) = (α + β)/ αβ = -(q/p) × (p/r) = - (q/r) = - (2/3)
(C) – 1/ (αβ) = -(p/r) = - (1/3)
(D) αβ/(α + β) = r/p × (-p/q)= - r/q = - (3/2)
We can see that, - (1/3) is the greatest among the above values.
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👍2
What is the ratio of expected police-to-population ratio of West Bengal, Bihar and Andhra Pradesh taken together to the existing police-to-population ratio of Uttar Pradesh, Andhra Pradesh and Maharashtra taken together?
Anonymous Quiz
47%
(a) 2962 : 2955
22%
(b) 331 : 297
21%
(c) 93 : 97
11%
(d) 5920 : 6131
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👆Ans. A | Explanation:
Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
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Expected police-to-population ratio of West Bengal = 1187
Expected police-to-population ratio of Bihar = 1133
Expected police-to-population ratio of Andhra Pradesh = 642
Existing police-to-population ratio of Uttar Pradesh = 1173
Existing police-to-population ratio of Andhra Pradesh = 953
Existing police-to-population ratio of Maharashtra = 829
Required ratio = [(1187 + 1133 + 642)/ (1173 + 953 + 829)] = 2962/2955 = 2962 : 2955
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👍3❤1
एक फोन का अंकित मूल्य 16,000 रुपये है, जो फोन के लागत मूल्य से 60% अधिक है। यदि इसे अंकित मूल्य पर 12% की छूट पर बेचा जाए, तो लाभ प्रतिशत ज्ञात कीजिए।
Anonymous Quiz
6%
(a) 38.6%
21%
(b) 42.7%
36%
(c) 48.6%
36%
(d) 40.8%
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👆Ans. D | Explanation:
दिया गया है कि अंकित मूल्य है = 16000 रुपये
अत:, लागत मूल्य = (16000/160) × 100 = 10000 रुपये
यदि इसे 12% की छूट पर बेचा जाता है, तो विक्रय मूल्य = 16000 × (88/100) = 14080 रुपये
लागत मूल्य पर लाभ = 14080 - 10000 = 4080 रुपये
इस प्रकार, लाभ % = (4080/10000) × 100 = 40.8%
इसलिए विकल्प (d) सही उत्तर है।
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दिया गया है कि अंकित मूल्य है = 16000 रुपये
अत:, लागत मूल्य = (16000/160) × 100 = 10000 रुपये
यदि इसे 12% की छूट पर बेचा जाता है, तो विक्रय मूल्य = 16000 × (88/100) = 14080 रुपये
लागत मूल्य पर लाभ = 14080 - 10000 = 4080 रुपये
इस प्रकार, लाभ % = (4080/10000) × 100 = 40.8%
इसलिए विकल्प (d) सही उत्तर है।
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Animesh borrowed Rs.1625 from Anurag. He repaid Rs.10 in the first month and promised to increase the repayment amount by Rs.7.5 every month. In how many months will Animesh be able to return the whole amount (including the first month)?
Anonymous Quiz
8%
(a) 10 months
23%
(b) 15 months
25%
(c) 18 months
44%
(d) 20 months
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👆Ans. D | Explanation:
Payment done by Animesh in the first month = Rs.10
Payment done in the second month = Rs. 10 + 7.5 = Rs. 17.5, and so on.
It’s an arithmetic series, wherein a = 10, d = 7.5, Sn = 1625
We know that, Sn = (n/2) [2a + (n – 1) × d]
Or 1625 = (n/2) [2 × 10 + (n – 1) × 7.5]
Or 1625 = (n/2) [20 + (n – 1) × 15/2]
Or 1625 = (n/4) [40 + (n – 1) × 15]
Or 6500 = 40n + 15n2 – 15n
Or 15n2 + 25n – 6500 = 0
Or 3n2 + 5n – 1300 = 0
On solving it we get, n = 20 months
Hence, option (d) is correct.
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Payment done by Animesh in the first month = Rs.10
Payment done in the second month = Rs. 10 + 7.5 = Rs. 17.5, and so on.
It’s an arithmetic series, wherein a = 10, d = 7.5, Sn = 1625
We know that, Sn = (n/2) [2a + (n – 1) × d]
Or 1625 = (n/2) [2 × 10 + (n – 1) × 7.5]
Or 1625 = (n/2) [20 + (n – 1) × 15/2]
Or 1625 = (n/4) [40 + (n – 1) × 15]
Or 6500 = 40n + 15n2 – 15n
Or 15n2 + 25n – 6500 = 0
Or 3n2 + 5n – 1300 = 0
On solving it we get, n = 20 months
Hence, option (d) is correct.
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